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Prevedena knjiga sa engleskog na hrvatski jezik od strane Drage Majera iz Nasica i editirana u PDF formatu uz pomoc Zeljka Fajdetica iz Crikvenice
Iba't Ibang Panahon
1
Dimenzionisanje T T –pr –pr ese eseka ka ( B < 5b 5 b ) B
εb
σb
p
d x
2 b
M u
p
d x
y
x
p
εbd
Dbu2
d ) p d x (
1
η
Dbu1
2 η
h d
N u
Gb
1 b
y
1 b
2 b
x h
z
z
Aa1 1
1
a
a
b
∑ M
a1
= 0 :
Z au au
Dbu × z = M au
ε a1
= M u + N u × (y b1 − a1 ) ⇒
s
2
Dimenzionisanje T T –pr –pr ese eseka ka ( B < 5b 5 b )
B
εb
σb
p
d x
x
p
εbd
p
d – x
)
p
Dbu2
d – x (
2
η
b
Dbu
1
d
= Dbu1 − Dbu 2
η
Dbu1
3
Dimenzionisanje T T –pr –pr ese eseka ka ( B < 5b 5 b ) B
εb
σb
x 1
η x
Dbu1 b
Dbu1
= α b1 ⋅ B ⋅ x ⋅ f B
α b1 = α b ( ε b )
,
η1 = η( ε b )
4
Dimenzionisanje T T –pr –pr ese eseka ka ( B < 5b 5 b ) B
εb
p
p
d
p
d – x
x
d
εbd
)
Dbu2
p
d – x (
2
η
b
Dbu 2 = α b 2 ⋅ ( B − b ) ⋅ ( x − d p ) ⋅ f B
α b 2 = α b ( ε bd )
,
η2 = η( ε bd )
5
Dimenzionisanje T T –pr –pr ese eseka ka ( B < 5b 5 b ) B bi =κ ×B ×B
εb
σb
x
p
η
d 2 b
M u
p
x
Dbu
d x
y
h d
N u
Gb
1 b
y
b
z
x h
Z au au
Aa1 1
1
a
a
b
ε a1
bi = κ ⋅ B
α δ b κ = 1 − b 2 × − 1 × 1 − α b1 s B
;
δ=
d p h
6
Primer 1 5 (m aterijal MB 30 RA 400/500
⇒ ⇒
z a ve b e, st r. 38) za
f B = 2.05 kN/cm2 σv
= 40 kN/cm2
B = 60 c m
b = 30 c m
d = 60 c m
d p = 10 cm
M g = 200 kNm M p = 250 kNm M u = 1.6× 1 .6×20 200 0 + 1.8×25 1.8×250 0 = 770 77 0 k N m
7
Primer 1 5 (m aterijal pretp. a1 = 9 cm
⇒
z a ve b e, st r. 38) za
h = 60 – 9 = 51 cm
pretp. x
51 770 × 10 60 × 2 .05 2
= 2 .038 ⇒
s
= 0 .348
x = = 0.3 0.348 48 ×51 = 17 17..7 cm > d p = 10 c m
Pretpo Pretposta stavka vka o polož položaju aju neut neutral ralne ne linije linije nije nije ta na, na, pa se presek se dimenzioniše kao T presek. Kako je B / b = 60/30 = 2 < 5 , u prora un un se mora uzeti i nosivost rebra
dp/h 0.5
0.45
0.4
0.35
0.3
0.25
B/b 0.2
0.15
0.1
0.05
1.5
2
2.5
3
3.5
5
7.5
10
15
20
25
κ
0.45
0.4
0.35
0.3
0.25
0.2
0.15
0.1
0.05
1
1
1
1
1
1
1
1
1
1
1
1
0.5
0.44
0.39
0.33
0.28
0.22
0.17
0.11
0.06
0.99
0.99
0.99
0.99
0.99
0.99
0.98
0.98
0.98
0.98
0.98
0.98
0.5
0.44
0.38
0.31
0.25
0.19
0.13
0.06
0.97
0.96
0.95
0.95
0.95
0.94
0.94
0.93
0.93
0.93
0.93
0.93
0.5
0.43
0.36
0.29
0.21
0.14
0.07
0.95
0.92
0.9
0.89
0.89
0.88
0.87
0.86
0.86
0.85
0.85
0.85
0.5
0.42
0.33
0.25
0.17
0.08
0.91
0.87
0.84
0.82
0.81
0.8
0.79
0.77
0.76
0.75
0.75
0.75
0.5
0.4
0.3
0.2
0.1
0.5
0.38
0.25
0.13
0.83
0.75
0.7
0.66
0.64
0.5
0.33
0.17
0.79
0.69
0.62
0.58
0.5
0.25
0.75
0.62
0.55
0.5
0.71
0.56
0.47
s > 0.348 0.348 κ
4
= bi/B
s = x/h 0.5
8
B /b = 60/30 = 2
d p / h = 1 0 /51 /5 1 = 0 .19 .1 9 6 ≈ 0 .2
= 0.81
⇒
b i = 0.8 1×60 = 48 .6 c m
0.87 0.81 0.77 0.75 0.73 0.71
k =
0.7
0.67 0.66 0.65 0.64 0.63
0.62
0.6
0.56
0.54
0.53
0.52
0.51
0.55
0.53
0.5
0.45
0.43
0.41
0.4
0.39
0.5
0.46
0.44
0.4
0.35
0.32
0.3
0.29
0.28
0.42
0.37
0.34
0.3
0.24
0.21
0.18
0.17
0.16
51 770 × 10 48 .6 × 2 .05 2
= 1.835 ⇒
s = 0 .452
dp/h 0.5
0.45
0.4
0.35
0.3
0.25
B/b 0.2
0.15
0.1
0.05
1.5
2
2.5
3
3.5
4
5
7.5
10
15
20
25
= bi/B
s = x/h 0.5
9
B /b = 60/30 = 2
d p / h = 1 0 /51 /5 1 = 0 .19 .1 9 6 ≈ 0 .2
κ
0.45
0.4
0.35
0.3
0.25
0.2
0.15
0.1
0.05
1
1
1
1
1
1
1
1
1
1
1
1
0.5
0.44
0.39
0.33
0.28
0.22
0.17
0.11
0.06
0.99
0.99
0.99
0.99
0.99
0.99
0.98
0.98
0.98
0.98
0.98
0.98
0.5
0.44
0.38
0.31
0.25
0.19
0.13
0.06
0.97
0.96
0.95
0.95
0.95
0.94
0.94
0.93
0.93
0.93
0.93
0.93
0.5
0.43
0.36
0.29
0.21
0.14
0.07
0.95
0.92
0.9
0.89
0.89
0.88
0.87
0.86
0.86
0.85
0.85
0.85
0.5
0.42
0.33
0.25
0.17
0.08
0.91
0.87
0.84
0.82
0.81
0.8
0.79
0.77
0.76
0.75
0.75
0.75
0.5
0.4
0.3
0.2
0.1
0.87
0.81
0.77
0.75
0.73
0.71
0.7
0.67
0.66
0.65
0.64
0.63
0.66 0.64 0.62
0.6
0.56 0.54 0.53 0.52 0.51
0.5
0.38 0.25 0.13 0.83 0.75 0.33
0.17
0.79
0.69
0.62
0.58
0.55
0.53
0.5
0.45
0.43
0.41
0.4
0.39
0.5
0.25
0.75
0.62
0.55
0.5
0.46
0.44
0.4
0.35
0.32
0.3
0.29
0.28
0.5
0.71
0.56
0.47
0.42
0.37
0.34
0.3
0.24
0.21
0.18
0.17
0.16
= 0.75
⇒
0.5
s > 0.452 0.452
κ
0.7
b i = 0.7 5×60 = 45 4 5 c m
10
Primer 1 5 (m aterijal k =
51 770 × 10 45 × 2 .05 2
Aa
z a ve b e, st r. 38) za
= 1.765 ⇒
s
= 0 .501 ≈ 0 .5 ; µ = 40 .533%
= 40 .533 × 45 × 51 × 2 .05 = 47 .67 cm2 100
40
usvojeno 10RØ25 (49.09 cm2 )
11
Primer 1 5 (m aterijal
z a ve b e, st r. 38) za
60 2RØ25
A a1 = 49.09 49.09 c m 2 (10 (1 0 R Ø25 )
5 . 4 0 1
5 . 5 2
UØ8/30
a I = 4.5 cm
2RØ12
a II = 10 cm 0 6
5 . 4 1
2RØ25
5 . 5 5 . 5
4RØ25
5 . 4
4RØ25 4.5
3x7=21 30
4.5
II I = 15.5 cm a III
0 5
a 1 = (4× (4 ×4 .5 + 4 ×1 0 + 2×1 5 .5)/1 .5 )/10 0 a 1 = 8.9 8.9 c m h = 60 - 8.9 8.9 = 51.1 51 .1 cm h > h r a . = 51 cm
