Laterally Loaded Piles Broms

q = 10 kN/m (No access)

2

Ph = 46 kN = 19.8 kN/m 2 cu = 50 kN/m s

1.17m

3

p = 17.5 kN/m2

s = 19.8 kN/m

cu = 50 kN/m

3

2

D

Actual Structure

Calculation Model (For soldier pile stability and integrity)

2

At z = 0 m bgl :

p

= 1.0×10 - 2×50 = -90.00 kN/m

At z = 3.5 3.5 m bgl bgl :

p

= 1.0× 1.0×(1 (10 0 + 3.5× 3.5×19 19.8 .8)) - 2×50 ×50 = -22. -22.68 68 kN kN/m /m < 0

2

2

MEFP= 5z = 5×3.5 = 17.50 kN/m

(From: CIRIA Special Publication 95, p. 36)

Ph = ½×17.5×3.5 = 30.63 kN/m × 1.5m = 45.95 kN/№ yh = ⅓ × 3.5 = 1.17 m

MEFP governs

The stability and integrity of the soldier piles will be assessed according to a laterally loaded pile by the method of Broms (refer charts next page).

□

DESIGN LOAD FH = e= ɣ Lf  FH =

□

PILE DATA Pile Top Condition:

46 kN/ № 1.17 m 64.4 kN/ №

{ Horizontal load } { Load application from GL } (( ɣLf  = 1.4 ))

FREE

Pile Size: H-200x200x8x12 My = py Sx = b OR d = D OR L = □

▪

275 N/mm² ))

=

19 kN/m³

{ Average unit weight of soil }

cu =

50 kN/m²

{ Ave undr shear strength }

SOIL DATA

CAPACITY AS SHORT PILE Ultimate Lateral Resistance in Cohesive Soils (( L/d = 17 e/d = 5.85 )) Hu,c =

▪

(( py =

{ Breadth of pile } { Embedment of pile }

Hu,c / (cu d²) =

□

525 cm³ ))

0.2 m 3.4 m

ɣs

□

144.375 kNm/№

(( Sx =

33.28

{Read from chart}

66.57 kN/№

CAPACITY AS LONG PILE Ultimate Lateral Resistance in Cohesive Soil s (( My / (c u d³) =

360.9

Hu,c / (c u d²) =

45.18

Hu,c =

e/d =

5.85 )) {Read from chart}

90.37 kN/№

Apply factor by embedment, provide embedment length D = 1.2 × 3.4 = 4.08m Required total length of soldier pile = 3.50 + 4.08 = 7.58 say 8.0m