LOGII If you've never solved a logic puzzle before, this introduction wiil show you how. We'll take you step by step through two
in the intersections of'Abner" and "Gunter," and "Abner" and "King cobra."
simple logic puzzles, and give you some solving tips along the
Irlolelrl-r r3r I
way.
logic p,.,zrl" is a test ofyour abihLy to think clearly You don'r need dictionaries or other reference books to solve a logic just a pencil and plenty of common sense' puzzle, Usualiy, a logic puzzle asks you to match up sets of things' For exanple. you might be told lhat four men each own an exotic pet, and to solve the puzzle you'd -match up each man's first nime \ /ith his last name and his kind of pet. You figrrr:e *Ihe out how to mat h them up by studying a list ofclues, like to Duane." belong llama doesnt In order to make solving fa-ster and easier, experienced logic puzzlers use a solving grid to record the information they've deduced. They've found that seeing the inforrnation in black and white, neatly organized, helps them make furiher deductions. lhere are two kinds of solving grids you'll find most often: the "crosshatch" grid and the "fiIl-in" grid. Sometimes you can't tell.which kind will work best until you've spent a lot of time trying to solve the puzzle with the wrong ki^d. In Dell logia Puzzles, we figure out which kind of grid is the most useful for each puzzle, and we print it on the same page. Sometimes we'll even give you both kinds if we think it will help. Let's look at a typical puzzle that works best with a crosshatch grid.
i
PET OWNERS
Each of four men owns a different species of exotic pet. .F rom the following clues, can you frgure out each man's full name and what kind of pet he owns? 1, Mr..Engels (whose pet is named Sparky), Abner, and Mr. Foster all belong to a club for owners of unusual pets. 2. The iguana i6n't owrred by either Chuck or Duane. 3. Neither the jackal nor the king cobra is owned by Mr. Foster. 4. The llama doesn't belong to Duane (whose pet is named Waggles).
5: Abner, who doesn't own the king cobra, isn't Mr. Grint€r. 6. Bruce and Mr. Foster are neighbors. 7. Mr. Halera is afraid of iguanas. And heret the crosshatch grid:
I4t's look first at clue 1. From it we can see that !{bner isrit Mr. Engels or Mr. Foster. We record this information in the
solving grid by pr-rtting an X rmeaning -no", in the square at the intersection of "Abner" and "Engels," anil another X at the intersection of "Abner- and 'Foster." Now let's look at clue 5. From it we learn that Abner doesn't ovfir the king cobra, and that Alner isn't Mr. Gunt€r..Put Xs
,6
DELL LOGIC PUZZLES February 1995
[$
P UZZ
rHr#r;Erglilel5l
.m-rml-n-'' lAb*, Txl-lTiITTTiT-]
fri-rtt+t |r,1,:.,Hfl1-l
En
FFTffi
i
werc care)ess. you mighl witho'.rt *rinking put an X into !the intersection of 'Gunted and fiing cobra' Does Mr. Gunter{ own the king cobra? Well, maybe he dnes and maybe he doeso't. i bul clue 5 really doesnt say anl'thing about it. Read each cluef, carefirlly and think about what it's really saying; if you jump to I a wrong conclusion now, you'lJ be confilsed later on. 1
Ifyou
Now we can se€ at a glance lhat Abner isn't Mr. Engels, Mr. I Foster, or Mr. Cunl,er. We can make a deduction: Abner must t be Mr. Halew. We'tl pr-rt a large dot (meaning :yes') in the I intersection of 'Abner" and -Halera." And that meals we can -l put )Cs in rhe intarsecl ions of fialeqa and "Bruce." 'Chuck," ll also -'Duare." \^/henever you add a dot to lhe grid, be sure ln', ar|d add any Ks you can: Lhej,4l ofien lead to more dedtrctions
I
I
|$fam lnls l( -
ffi X
(9
'6
x
Bruce
F:*FF+]T Chuck
X
Duane
X
That was a fairlv simple deduction, but in order to solve this puzzle you'll need to make some deductions that are a little i.i"ti... Go through the rest of the clues,and. pu-t Xs into ihe grid wherever you can. You'll end up with this:
Sometimes, with a very easy puzzle. just putting the informaQori lhts lall out oul- to you This solurion fall the solution srid is enough enoush to make ttre in the grid
putzle'i a bit harder, though, and at first glance th9r9 dTsn't seem to be enoueh inforrn;tion to mal
"
Mr. Haleqr doesrft own thd iguana. Since Abner is Mr'
..
Halevy, that meansAbner doesn,t own the iguana either, right? Put an X in the int€rsection of ,,Abner, ana ;tglru"u. u"j yo?i" ready to make another deduction: the iguina i" Brrce. Add the appropriate dot and X's t;he "*"""a-tu erid. 0.;;"f; ring infornation from one section of the grid'to anotherl as jl"l 919: is an imporranr srep in solving, ald ir's an one ro overtook,) "asy isn't Mr. Foster, so Mr_ Foster doesn't own the iguana. __Bruce Voih! Another deduction: Mr. Foster owns the llama_ Mr. Foster is either Chuck or Duane, while the llamat owner is either Abner or Chuck. Since both ar" tfr" ifrr,,.,"i be Chuck who is Mr. Foster and owns the.llama. ""-" -".r, Now Abner Haler,l s per can only be rhejackal, and Duane.s pel. by eliminaLion, must be the ldng cobra. Don.t for8ct to add a dot at the intersection of "Halely; and ,,Jackal," aia tfr" X"
Here's a hot_tip: Very often, the way to break into a puzzle that has a fill-in grid is to find a list ofall the people invotvedThere s one in clue I. so we start by put[ing each woman named rn clue I into a different column ofthe srid:
lll
First name Last name
A[ice
'Espinq ffoin
Pet
i6"X
that go rvith it.
now you seem to be stuck. owns the iguana, and -Ald owns the l.ing-cobra, but Bruce Duane you can.t tell f; ;;;; whjch.one is Mr. Engels and which one is Mr. Gunter. ls th"ere anlanrng ln the clues you ve missed? Why, yes: Mr. Engels.pet rs-named Sparky fclue l/, while Duaoe's pel is narned Waeeie" {clue 4). so Duane canr be Mr. Engels. As you solve i6gic puzzles, you'll learn that you often ne;d to combi"" f;;; i*; two or more clues to mal
beginning ofthe magazine. Don,t try l,o swan_dive bpfore you,ve learned to swlm
let's,look at a.similar puzzle where a crosshatrh grid ,Nowt work very wcli.
ctoesn
MORE PET OWNERS Doris and three other women each own a different species of exotic pel,. From the following clues, can you figure out cach woman s tuU name lonp is Ms. Hankerr and what kind of pel she owns rone owns a kangaroor?
All four-Alice, Ms- Eiping, Ms, Florin, and the ibels gvne;-belgng to a clutr for owners of unusual pets.
1,
2. " The leopard dioesn,t belone to Beite. 3. The jaguar doesn't belong to Alice. 4. Ms. btiuer, *ft" 5*rr iil" f*o*a, jives noxr door to
a""*i
Chloe.
5. Bette, who isn't Ms. Florin, doesn.r, own the ibex. 6. Ms. Esping doesn't own r_he iazuat. And here's the fill-in gr-id: First name
Last name Pal
It doesn't look as helpful as the crosshatch grid, docs it? And yell,e lt.Eee^thal the puzzlc practically solves itselfon a fill_in
rl.you tned lo use a crosshatch grid for this puzzle, ryl,,rynrre youd Just get tfus lar and no further: o AIice
6 E -9
I (9
Bette
X
Chlo€ Doris
Jaguar Kanqaroo Leopard
I
X
X
Fill in the.rest of the grid yourself as you read on. Ttre jaguar doesn't belong to Alice (clue B) or Ms. Efping (ctue O)i s"o by looking at ou.€rid we can see it must leilonito U". fio"i"." is neither Ms. f'lorin nor the ibex's owner (clue 5), so -Bette she must be Ms. Espin!. . The leopard doesn t belong ro Betle Esping {clue 2), so it belongb to Alice, and by elimiration Lhe kangaroo beiongs to Bette Esping. ryl6_ ns rhe leopard, isn'L Ms. Glover {clue 4}, so .Alice, _6q, shp is Ms. Hanker. and Ms. Clover is the ibex.s o*n"r. M". Glover isn't Chloe (clue 4), so she is Doris, and Chloe is Ms.
Florin
your answer: Bette. Esping owns thc kangaroo, ^l..nd Ill..:k lorln owns the jagrrar, Dorjs Glover owns the ibex, and {::.ruoe Alice Hairl€r owns the leoDard.
Before.we 6nish up our inlroduction, here are a few more llps: Read a puzzle's introduction carefully, and make sure you understand what you're trying to figure out. If each person Las /rro pets, for example. and yolr assumrr each person has onlv one, youll end up with your solving grid in a muddte! A puzzles introduoion somelimeJhas a piece of information you'll need to solve the puzzle. For example, the introduction to.a puzzle about the seating chart al a dinner party might tell you thar no husband was seated next to his own wiie. Oirl miss lhosc important clues. lfyoure stuck. go over the ciues agajn, one at a lime. Have you really used every bit of informal_ion thal_ can be soueezed out of each one? Another way to get unstuck-though it,s more wo.k_is to make an asshmption. A.ssume, say, ttat Alfred is Mr. Greene, and see where that leads. (MaJ
qlspro!1ng assumpl,ions. But experienced solvers know that the most effective way b I get unstuck is to put the puzi,le aside for a while. Go on to olber puzzles. and come back to rhe sticky one an hour, a day. or a wcek farer. When you try the puzzle again with a cleir mind. youll probably see things you didnl no-ce th9 first rime. ll you need a hint, turn to the solution and read il one line at a time, just until you reach a deduction you didn't think J ii Then 6top r"ading, go back to lhe puzzle. and conlinue solving lrom thal, point. Since Del/ lngic ptuzl*s gives complcrc steD-_ 1by-step solulions for each puzzle, you can get as h.lp a" f you neFd tnts way. at any staqe in your solyine. ^uih lf yotr think you've found , sol"ton to a puzz]o lhat doesn.r mal,ch ours, carefully check it against each clue in the puzzle. Almost always, you'll find lhat you've overlookcd a subtle conlradiction. Ifyour solurion still holds up, please let us krowl I Enough introducrions -it's time to start s;lving! And we sin_ ll cerely hope you enjoy this issuc of Dp11 Logic puzzles. I
*
BRAIN PICKERS BY CHRIS PERTON "Brain Pickers" is an annual quiz tournament for high school teams from around the state. This year's winning team was from Mark Twain High School, and consisted of two young
women-Andrea and Monica-and two young men-Ran-
(d
o o
Y
.g
dall and Thomas. Their last nuures are Brennan, Garcra' Hardy, and McKay, and ea-ch has a differelt academic specialty (fine arts, history, literature, or science). Can you march each teammate's full name with his or her specialty? Solution ts on page 5 ).
l.
Monica and McKay are seniors, the science expert is junior, and Andrea is a soPhomore.
Andrea
2.
Randall (who isn't Brennan) isn't strong in history.
Monica
3.
Ms. Garcia isn't a senior.
(!
a
Randall
a
The young wordpn specialize in fine ans and
Thomas Fine arts
5.
The literature €xpert isn't Brennan.
History Literature
'JUST iAY
BIIIS
BY HUMPHREY DUDLEY
This morning's mail brought four bills, three for utilitieselectricity, telephone, and water-and one for my account at Frack's department stoie. Each was for a different amount$2!, $30, $40, or $6G-and I paid them with checks num-
(s
bered 604 though 607. Can you reconstruct 'my register by matching each check number with the amount the check and which bill I paid with it'l Solution is on page
1.
Check #605 isn't for $60.
2.
The checR to Frack's is for more money than checki #604, which in tum is for. more than the check to the' telephone
#604 #605
3.
The check for the electric bill is for twice as much
1
.
as
The $40 check has a higher number than the check for the water
DELL LOGIC PUZZLES FebtuarY 1995
I
check #60?.
#606
#607
company
bill.
FRUITS AND VEGETAETES BY ALEX KNIGHT Two men (Damon and Harry) and two women (E
Molly) met yesterday afternoon at the local produce inarket. Each was buying a different kind of fruit (apricots, can-
l.
No one bought both nectarines ana ipinach.'
2.
Neither Damon nor Molly bought eirher zucchini broccoli.
3.
Harry didn't buy limes or nectannes.
* taloupes, limes, or nectarines) and a different kind of vesetable t broccoli. green pepper'. spinach. or zucchini t. Can y-ou find each one's purchases? Solution is on page 51 .
.
A man bought both cantaloupes and green peppers. 5.
*
No one bought both apricots and zucchini.
IOST AND
FOUND
*
BY IDA J. MASON
While rushing to get ready for the first day ofschool, the four Holsum childreu (Karen, Larry, Molly, and Norman) each lost a different necessary item (a box of cray,ons, a pencil, a ruler, and a pair of scissors). After a frantic search, each item
l.
The box of crayons (which isn't Karen's item) wasn't found under the table.
2.
The ruler (which doesn't belong to Molly) didn'r tum up behind the bar.
3.
The four children are: Molly, Norman. rhe child who lost the box of crayons, and the child who found his or her ilem behind lhe bar.
4.
The item found in the cupboard (which doesn't belong lo Larry) wasn't the ruler or the scissors.
was found in a different spot in the kitchen (behind the bar, in the cupboard, in the refrigerator, and ulder the table). Can you link each child with the item he or she lost, and where gach item was found? Solution is on page 5l .
.DELL LOGIC PUZZLES February
1995
9
THE EAR OF THE
BEHOLDER
**
BY CHRIS PERTON
Five co-workers were discussing their favorite types of music over lunch recently. It tumed out that each ofthe three women (Agnes, Gayle, and Linda) and two men (Brian and Jef|) has
in a different way (on CDs, LPs, or tapes, on the radio, or live). lnst names are Dryer, F4nshaw, Nevins, Quigley, and Willis. Can you match each person's full name with his or her
different favorite kind of music (classical, country western, rap, rock and roll, or show music), aod each prefers to hea[ it
musical preferences?
a
Solution ts on page 51.
l.
Jeff (who isn't Quigley) likes rap music best.
2.
The two who prefer their music live and on tape are Agnes and Ms. Nevins in some order.
3.
Quigley never listens to tapes or CDs. Neither Gayle Willis nor the man who loves classical music owns a radio.
THE S.O.F.T.E.
TOUCH
5.
Agnes (who isn't Dryer) favors country westem music,
6.
Linda doesn't own any kpes.
'7.
The one who prefers rock and roll never lislens to it live,
BY JEAN ROWELL
[,ast spring, the councils of the neightroring towns Stabney and Ofwell began promoting the Stabney and Ofwell Friendly Tourism Extravaganza. Each of the five Stabney council lnembers (Abner, Betty, Carla, Devin, and Ellie) teamed up with one of the Ofwell council members (Lana, Mavis, Norton, Osgood, and Paddy) to present a different idea for a
promotion gimmick (a camera raffle, free film motel discount coupons, free postcards, or ftee sunblock)
thejoint council meeting. Can you matcheach pair of rirembers with their idea, and find the order in which the teams made their presentations?
Solution is on page 5
1.
Devin and Norton were paircd; they didn't give the presentation.
2. 3.
Paddy and his partner were fourth to present an
Ellie's team spoke immediately after Lana's, but time before the pair that proposed motel coupons.
A
I-ana (whose team didn't come up with the idea having free raffles for caineras) spoke sometlme than Osgood and his partner.
5.
Carla was on the second team to speak.
6.
Free sunblock wasn't the first idea presented-' but.it immediately before Abner and his pal
Presented spoke, which was sometime bdfore one team mended giving free postcards of the cities'
DELL LOGIC PUZZLES February 1995
WIGS AND MAKEUP
**
BY SCOTT MARTEY
The Snoobville Community Theater is presenting that classic 1920s drawing room comedy Poor ButtedT:t, each Friday and Saturday night at 8:00 p.m. The cast includes three womenBelle, Diane, and Hillary-and two men-{laude and Fritz --'each ofwhom must be wigged and made up before the play
begins. The theater has a wig stylist and a makeup artist
l. . 2.
3.
working backstage to assist the performers in getting ready. Each performer has been assigned one ten-minute time slot with the wig stylisr and another ten-minute time slor with the makeup artist. The time slots begin at 7:20,'1:3O,7:40,7:50, and 8:00. Can you reconstruct the wig arld makeup schedule? Solution is on page 5l .
No performer, of course, is assigned to be wigged and
wig
made up at the same time. Since Belle, Fritz, and Hillary are olr stage as the curtain rises, they must & ready by the 8:00 curtain. (Claude and Diane, who don't appear until about a halfhour into the play, needn't be ready by 8:0O.)
Belle gets made up before she gets wigged, and the same
Makeup
7:20
7:30
is true of at least one man.
4.
Only one of the five performers, a man, doesn't haye to wait at all between his time slots.
7:40
5.
Hillary is finished with her wig and makeup before any of the others.
7:50
6.
No one has to wait longer than 20 minutes from the end of his or her first time slot to rhe beginning of the
8:00
second.
t' rt
POINTS OF
VIEW
BY ALEX KNIGHT
il Two men-Julius and Toby-and two women-Dixie and Mercedes-hiked together to the top ofPanorama peak. Once al the summil. each brought out his or her camera and took a photo of the view. The four friends took their photos at the sam€ time, but each was facing in a different direction (north,
J.
Hedgerow
2.
Toby, and the hiker photographing Vista Vale faced nonh and east in some order.
3.
Mercbdes and the hiker photographing Goblin Grove
Hill isn't to the north of Panorama
east, south, or west) in order to get
natural wonder
(Goblin Grove, Hedgerow Hill, Robinet River, or Vista Vale) into the shot. Can you match each hiker with the direction he
peak.
faced south and west in some order.
4.
Julius stood wirh his back ro Robinel River.
5.
Dixie and one of the men faced rn opposite directions. Direction
Sight
'
/as
rcr
m:
DELL LOGIC
P
UZZLES February
1995
ll
PIECE OF THE
PIE
**
BY HUMPHREY DUDLEY
one ordered a glass of wine). Can you match each person's full name (last names are Piney, Quilteq Rogers, and Sloane) with the number of slices he or she ate and the drink he or she ordered? Solution is on page 52.
Two men-Len and Ozzie-and two women-Magnolia and Nell-went out for pizza last night. They ordered a pizz^ to share, and among them they ate all eight slices. Each ordered something to drink (two ordered colas, one ordered milk, and
l.
Everyone had at least one slice.
2.
The two cola drinkers ate lgss than half the pizza b€tween
I
them. I
"-r
3.
Magnolia had exactly two more slices than Rogers did.
4.
l€n
5.
had exactly one more slice than Piney did.
Mr. Sloane had at least as many slices as the wine drinker did.
DIVE INTO STOCKS BY CHRIS PERTON Ms. Rhodes decided last year to begin investing in the stock market. After doing some research and seeking advice from herfriends, she decided that the bestway to leam was tojump right in and buy a few shares. She purchased one hundred shares in five different companies (BMS, JEP. LKB, VlP, and XYZ), each at a different purchaSing price ($10, $20, $.30,
$40, and $50). After owning them for a year, she what she had. Thre€ stocks had increased in value (bv 25/o, and 454o), and two had decreased (by 157o and 35 Can you find out how much each stock was worth when Rhodes purchased it, and lhe percentage by which each changed over the course of the year?Solution is on page
c
1.
:The
C\J
stock that Ms. Rhodes purchased for $10 isn't the qne that lost 157o.
BMS
XYZ (which she didn't purchase for $30) and the $50
JEP
stock both lost money.
]LKB
3.
JEP increased by 57o.
VIP
4.
The $20 stock (which wasn't LKB) increased by 4sEo.
5.
Ms. Rhodes purchased VIP at $40.
2.
xYz 45"/"
25Y" up
5% up 15% down
down
.12
DELL LOGIC PUZZLES February 1995
o
'
dtil $lc!
s
tr)
(r)
BAGEIS FOR BREAKFAST
***
BY MARK T. ZEGARELTI
Five people (Adrienne, David, Glen, Lianna, and Steve) were
Can you find out the full name o-f each customer (last names are Bogard. Karros. Marciulionis. Niles, and Zezel). lhe rype
already in line at 7 a.m. when The Holesome Bagel Shop opened its doors. Each ordered a differenl rype of bagel (egg, onion, pumpemickel, raisin cinnamon, and whole wheat).
of bagel each ordered, and the order in which they served?
Lianna was served just before the person who ordered the egg bagel, and just after Z€zel.
o.
Niles was served sometime before either Glen or the person who ordered pump€rnickel, but not both of them,
Karros didn't order the pumpemickel bagel.
t.
were
Solution is on page 53.
Order
First
name
Last name
Bagel
One customer was servedjust before andjust after Glen and Steve, in some order.
The person who ordered the whote wheat bagel was servedjust before Adrienne (who isn't Bogard), andjust after Marciulionis. 5.
The person who ordered the raisin cinnamon bagel was served sometime before the one who ordered the onion bagel.
co E
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o c
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o
d
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):
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o) q)
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)<
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3 z
o)
(')
N o c') N ul
(tr
o '6 3 .s _qt '6 o E 3
First
s.
Second
le' 3.
Third Fourth Fifth
Ess Onion
R"iai"
"m"r*
Whole wheat Bogard Karros
Marciulionis Niles
Zezel
)
DELL LOGIC PUZZLES February 1995
r3
I
BIZARRE
TREK
***
BY RICH SONES
The Federation Starship Boobyprize iE approaching a new star that is orbited by five planets: Arrth, Kudo, Ort, Ranus, and Velcron. Each planet is inhabited by a different species Coneheads-, Gnatites, Pachydermi, Slimese, and Turtillians). each of which has a differcnt distinctive charac-
of life (the
l. Amh
ter hait (impud€nce, laziness, orneriness, Prsnicketiness, or sullenness). The relative masses of the five planets' in some order, are l, 3, 5, 7, and I l. Can you put the planets in order
from first (nearest the star) to fifth (farthest from the star)' and match each with its relative mass, species, and trait? Solution is on page 53.
(which isn't thd smatlest of the planets) is less than half the size of Ranus'
2.
Velcron (which isn't inhabited by Gnatites) is farther from the star than the impudent planet, but nearer to the star than the Turtillians' planet i
3.
The founh planet is smalle r than Orl.
4.
The Tunillians are never sullen.
5.
The Coneheads live on the fiflh planel.
6.
Ranus's orbit is just inside Arrth's, and just outside that of the largest planet'
7.
Ranus, which is the omery planet, is smaller than Velcron.
8.
The residents of Kudo (which isn'l the first planet) aren'l lazy.
9.
The Pachydermi are neither from Arrth (which is the sulten planet) norfrom Velcron'
(U
€l€l
itstd.
=
(U
o
E
d)
o)
c o (,
1l3l5l7
(5
o) o)
.E
6
.q E l
First
Second Third Fourth Fifth
,
Lazy
Ornery Persnickety Sullen Coneheads
Gnatites Pachydermi Slimese ,f_ 1
3 5 7 l,t
DELL LOGIC PUZZLES FebruarY.1995
PYRAMIDS
BY
***
IDAJ. MASON
I-ong agqin the country of Islypt, pyramids were the only socially acceptable burial places for thc leaders of the five major peoples-the Fakiris, Grinjas, Hulagos, Ifendus, and Kuzois. In the yea$ 279, 280, 281, 283, and 284 of the Islyptian calendal five leaders (Abdul, Baba Roi, Cleon, Dobal, and Emut), one from each group, were laid to rest in
l.
The leader of the Grinjas was entombed in 283, not in the silver pyramid.
2. .
Dobal (who didn't lead the Ifendus) was enrombed in
3.
Emut was laid to rest in a pyramid ofgold.
4.
The ebony pyranid was built by the Hulagos, not for
pyramids, each made of a different material (bronze, ebony, gold. marble. rnd silverr. Though the leaders have been forgotten for centuries, the pyramids remain popular tourist attractions. Can you find the leader who was entomb€d in eaah year, the people he led, and the material his pyramid was made from? Solution is on page 54.
7.
281.
Baba Roi and the leader for whom the bronze pyramid was built were entombed two years apart from each other, in some order.
Year
Leader
People
Pyramid
Baba Roi.
5.
lhe Kuzois' leader was entombcd in
an even -numbered
year.
6.
The leader entombed in the marble pyramid in 280 wasn't Abdul.
tfo -o (5 (n
(u
-o
o
o
-
'(tt
LL
(t
co)
o N E
p
m
(5
o
I a
279 281
283 Bronze Ebony Marble Fakiris
Grinjas Hulagos Kuzois
DELL LOGIC PUZZLES February 1995
t5
TEE
UP
***
BY CHRIS PERTON
names are Baxter, Chappell, Fox, Ramsey, and Young)' score (six betow par, one below par, par, two over par, and three
The Tri-County Golf Association hosted a toumament for local amateur gotfers, The five finalists (Donald, Gordon, tee. Marvin, and Warren each represenled a different golf ' club (Arlington, Meadowbrook, Rivercrest. Springtown. and Trophy). Can you figure oul each finalist's full name tlast
l.
over par), and the club he represented? No/e.- In golf, a lower score is better than a higher one. Solution is on page 54.
The Rivercrest gotfer finished three strokes ahead of Gordon.
2.
First
Score
The Trophy Club golfer finished next ahead of Lee, and
name
next behind Mr. Baxter. 3.
The golfer from Meadowbrook finished next ahead of Mr. Chappell, and riext behind Mr. Young. Mr, Baxter finished three staokes ahead of the man who golfs at Arlington.
5.
Marvin finished someplace ahead of Warren, and someolace behind Mr. Fox.
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Six below One below Par Two over
Three over Arlington Meadowbrook Rivercrest
Springtown T
Baxer Chappell Fox
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DELL LOGIC PUZZLES FebruarY 1995
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HAPPY CAJIAPERS
ore
Four couples (the Adamses, the Bartons, the Grimleys, and, the Serapiglias) went camping on their vacations last year. Each couple is from a different home state (Catifomia, Massachusetts, New Jersey, and Vemont), and each went to a
re0 I,Ver
***
BY CONSTANCE ADAMS
54.
different tourist site (the Grand Canyon, Mammoth Cave, Old Faithful, and the Painted Desert) in a differeht season of the year. Can you find the season in which each couple took their vacation, their home state, and their camp site? Solution is on page 54.
7.
The couple from Vermont went camping sometime later
in the year than the couple who went to the Painted
The couple from Massachusetts sent a postcard to the Serapiglias.
Desert. The Serapiglias sent Mammoth Cave.
3.
a
posrcard to the couple that visited
Season
Couple
State
Site
The couple from New Jersey took their vacation between Christmas and New Year's Eve.
4. Mr. and Mrs.
Adams, who didn't visit the Grand
Canyon, didn't send or receive any postcards all year.
5.
The Banons didn t camp in spring or winter.
6.
The California couple received a videotape of Old Faithful from the couple who took their spring vacation there.
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Grand Canyon Mammoth Cave
Old Faithful California Massachusetts New Vermont
DELL LOGIC PUZZLES February 1995
t7
***
MICROBE TOUR,ISM BY GLENN SCHOEN Unbeknownst to Jenny Tetra, her anatomy was an accommodating.host to the four members of the Germano family last week. On each day from Wednesday through Saturday, a different family member was given a guided tour of a well-
of
1.
Serrata's tour either took place on Wednesday or was the Islet of Langerhans, or both.
2.
Cfuoma's tour and the father's tour took place either on Wednesday and Thursday respectively, or on Thursday and Saturday respectively.
3.
The mother is either Vermis or the one who toured the Mediastinum Isthmus. but nol bolh.
n
The sister's tour and the tour of Lake l-acrimal were either on Wednesday and Thursday respectively, or on Thursday and Saturday respectively.
5.
r8
The- brother's Fossa's tour.
tour occur€d at least two days after
DELL LOGIC PUZZLES February 1995
known "geographic" location. Can you determile the day on which each Germano went on tour, his or her relation to the family, and the site visited? Solution is on page 54.
6.
The tour ofthe Hyaloid Canal wasn't on Friday.
Day
Name Relation
Site
BUILDING BLOCKS BY HUMPHREY DUDLEY on
he
Baby Gina has a brand-new set of bright yellow atphabet blocks. Each of the four blocks has a single letter of the alphabet on each ofits six sides. In all, the six blocks conrain
t4.
*** every letter but Q and X. By arranging the blocks in various ways, Gina can spell all of the'words listed below- Can vou figure out how rhe letrers are arranged on the four block;? Solutioh is on page 54.
BANK DOZE
JUTE MOTH
GLIB SLAV HARD SUFI
IOWA
JUMP
DOMINOES
***
BY ATEX KNIGHT
The dominoes of an ordinary double-six set have been scrambled and arranged into the pattem shown below. Each number shows the numb€r irf pips in that square, from zero to six, but the boundaries between the dominoes have all been
33 14 50 52
oo 7
62 65 CL
ZINC
226354 | 3 4 0 22 ltt06l 603665 o35432 o64'437 5124 5 4
removed. Can you deduce where each domino is, and draw in the lines to show how they are arranged? As a help, the 28 dominoes.,pre listed with the diagram; remember that each domino is used exactly once. Solution is on page 55.
lo-o|
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DELL LOGI:C PUZZLES Februrary 1995
19
SUNDAY ERUNCH
***
BY CHRIS PERTON
This Sunday, four couples staying at the Luxury Hotel (the Johnsons, the [.opezes, rhe Mileses, and the Sullivans) shared a brunch table for eight. During the course of the meal, the men (Doug, Jesse, Rex, and Scott) and women (Colleen,
moon, on vacation, and visiting relatives). Each couple had arrived on a different day fmm W.ednesday through Saturday. Can you determine each couple's full names, day of arrival, room number {103,212,319, or 406; the firsr digit is the number of the floor). and reason for their sray? Solution is on page 55.
Emily, Hanna, and Maureen) discussed their reasons for staying in the hotel (they were on business, on their honey-
l.
5.
Thc Johnsons arrived the day before the couple in room 212, and the day after Emily and herhusband (who isn't
The Mileses arrived the day before the couple who were on vacation, and th€ day after the couple in room 319.
Jesse).
Day
The four couples are: Hanna and her husband, the couple visiting relatives, the couple who arrived Wed-
Husband
nesday, and the couple in room 40b. 3.
Wife
Scott (who isn'r Mr. Mites) arrived sometime before Colleen.
Last name The room in which Doug and his wife stayed is one
floor Room #
higher than that of the Lopezes (who arrived sometime after Hanna and her husband), and one floor lower than thal o[ the couple who were on business.
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Wednesday Thursday Friday 406 319
103
Business Honeymoon Relatives Vacation Colleen
Hanna Doug
Jesse Rex
X)
DELL LOGIC PUZZLES February 1995
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OFFICE REDECORATION BY MARK T. ZEGARELU
d ay. AI, :he
t5.
***
Like most nonprofit agencies, Grove Street City Services has neyer bebn overfunded. Nevertheless, the five dedicated staff members (Golda, Kent, Steve, Ursula, and Wally) recently received a little money to give each of their offices a fresh coat of paint- Each person holds a different position at the agency (administrative coordinator, clinical services director.
l.
Golda and Zyp are in some order the executive director and the one who chose beige.
2.
Palmer didn't choose ivory.
3
.
4.
executive director, funding, directol and volunteer coordina_ tor), and each picked a diffefent color for his or her office (beige, deep blue, ivory, tight blue, and tan). Can you find the full name of each staff memb€r (last names are palmer, Queen, Ramsay, Yonkowski, and Zyp), the position each holds, and the color of paint each chose? Solution is on page 55.
6,
The five staff members are: Ursula, Wally, yonkowski, the administrative coordinator, and th€ one who chose tan for the office color.
First Neither of the women (one of whom is clinical services director) chose a shade of blue.
name-
Last
name Position
Neither the one who chose ivory (who isn't yonkowski)
nor Kent Ramsay is the executive direcbr or the
ad_
ministratiye coordinator.
5.
The funding director chose deep blue.
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Administrative Clinical Executive Volunteer
DELL LOGIC PUZZLES February 1995
Color
SIJI/EET
SUCCESS
BY JO
***
MASON
heroine (Annemarie, Beatrice, Celeste, Janell, Shanna, and Suzanne), and exciting location (Greece, New York City, Portugal, Scotland, Spain, and Wales). Can you find the order in which he wrote his six books, and match each with its hero, heroine, and setting? Solution is on page 55.
Sidney Schopenhauer writcs enormously popular romance novels under the pen name ofRosamonde LaSalle. He cranks out more or less the same story over and oYer, chahging little morc than the chatacters' names and th€ settings. So far he's written six books, each one featuring a different virile hero (Adolfo, Damien, Jeff, Kyle, Pierre, and Ricardo)' spunky
l.
Sidney's first book, which is set in Portugal, features Kyle but not Shaana'
2.
Janell is the heroine of Sweet Rendezvous.
3.
Annemarie finds romance in Sidney's sixth book.
As soon as Sidney iinished writing about Jeff's advenrures in Wales, he began Damien's story in Scotland. Srleet Pdssion was written sometime before the book featuring Beatrice, which was written sometime before the book set in Greece, which was written sometime before
the book featuring Suzanne. o.
Sidney's second book is Sweet Desire-
7.
Ricardo finds his trudlove in Sweet Surrender.
8.
New York City is the setting for Sw,eet Nothings.
9.
The two novels that feature Celeste arld Jeff weren't written consecutiv€ly in either order.
10.
The heroine of Swe et Goodbye isn't Stianne-
11.
The man Suzanne falls for is neither Adolfo nor Jeff.
Order
Book
February 1995
Hero
Heroine
Setting
BROWN.BAGGING nd
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IT
***
BY CHRIS PERTON
berry ice cream, and vanillapudding). Each of the five friends brought lunch from home on :r different day, and the rest of the week bought his or her lunch at school. Can you figure out on which day each student chose to brown-bag it, and which entr€e and dessert was served on each ofthe five days? Solution is on page 55.
Five students at Ridgewood Junior High (Anne, David, EUen, lnuis, and Maftha) eat lunch together every day. Each day
last week, the cafeteria sei'ved a different entr6e (chicken, fish, meat loaf, pasta salad, and tacos) and a different dessert (blueberry pie, gingerbread cake, oatmeal cookies, shaw-
t5.
1.
5.
Anne brought her lunch to school sometime before the
day or days on which fish and bluebeny pie were served.
2.
Chicken (which wasn't served the same day as gingerbread cake) was served sometime after the day Ellen brtiught her lunch, and sometime b€fore the day Louis brought his.
3.
Atl ofthe gills
4.
Vanilla pudding and tacos were served either two or
ate both the meat
The oatrneal cookies were served sometime before the day David brought his lunch, and sometime after the day meat loaf was served.
Day
Entr6e
Student
Dessert
loafand thepastasalad.
three davs aDart.
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Monday Tuesday Wednesday Thursday Cake Cookies
lcecream Pie
Chicken Fish Meat loaf Pasta salad Tacos
DELL LOGIC PUZZLES February
1995 Lt
IN FOLDERO|jS COURT
***
BY JEAN ROWELL
Prince Folderol hired five new acts last week for appearances
amne, and Solange. Each pair performed upon musical instru-
at banquets. At dinner each night from Monday though
ments (drums, flutes, harps, lutes, or mandolins) and had some non-instrumental tale;t as well (aciobatics, dancing, juggling, magic, or singing). Can you find eachday's pair and discover their instrumental and non-instrumental talents? Solution is on page 56.
different act appeared to entertain Folderol's guests. Each act consisted of two performers, one male and one female. The five men were Chester, Fester, Lester, Nester, and Tester; the frve women were Ariane, Dionne, Katrinka, MariFriday,
a
1.
The magicians don't play lutes.
2.
Mariamne ( who wasn't in Thursday's act) i sn't an acrobat.
3.
Fesler can't dance, and Tesler can't sing.
Katrinka, the magicians, and Fester performedon three consecutive days in that order.
8.
The five pairs are Solange and her panner, Nesler and his paFn€r, the lutists, the singers, and Friday's act.
Friday's act didn't involve any mandolins5.
7.
9.
harpists.
Irster (who isn't Katinka's partner) didn't perform on Monday.
10.
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Drums Flutes Lutes Mandolins Acrobats Dancing
Ariane Dionne Katrinka Mariamne
DELL LOGIC
P
UZZLES February
1995
o
The dancers performed the day after Tester and the day
before Dionne.
The haryists (who don't include Ariane) don't juggle.
q)
The flautists performed earlier in the week than the
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ITEMS FOR SCHOOT BY MARGARET EDMISTON ru-
nd Irg'
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t6.
It's back-to-school time, and Mrs. Calautti has just retumed from shopping for the items her children have reouested (calculalors, lunchboxes, notebooks, and pencil cases). Each
*** item is sold in four colors (trlue, green, red, and yellow). Can e?rch child received, and the Solution is on page 56.
you decide which three items color of each?
l.
In all, Mrs. Calautti bought three of each item, in thee different colors, and she bought three items of each color
2.
Each child received three different types of items, in three different colors.
3.
Joshua received an item in red which one of the othcr children received in sreen.
4.
Adrienne gor a yellow pencilcase.
5.
Joshua's lunchbox and Morgan's pencil case are the same color
6.
Adrienne's calculator and Tony's lunchbox are the same color.
7.
Morgan and Tony both received notebooks.
8.
Tony didn'r get
9.
Joshua got a green calculator.
a
red item.
Calculator
Lunchbox
Notebook
Pencil case
Adrienne
Joshua
Morgan
Tony
DELL LOGIC PUZZLES February 1995
25
i
l
KATIE's BUSY SCHEDUIE
***
BY CHRIS PERTON
Katie iS one of the busiest nine-year-olds around. Every day after school, Monday through Friday, she has a different activity (baseball, dance, karate, piano, and scouts). Each activity is taught or coached by a different adult (Barbara, David, Susan, Ted, and Vicki) whom Katie has known for a
different number of years (one through five). Can you determine the day on which Katie goes to each activity, the full name ofeach instructor (last-names are Bach, Collins, Graves,
Hare, and Wood), and the numb€r of years she has known each of them? Solution is on page 56.
l.
David is either the first or the last instructor of the week.
2.
Katie has known Susan one year longer than hef baseball coach, and one year less than her piano teacher.
3.
Graves has known Katie for five
years-
r
Piano and ka&te are both taught by men. 5.
Katie has krown Wood one year less than Barbara, and one year more than herscout troop leader,
6.
The instructor who has known Katie for thfee years sees her each week the day before Mr. Hare and the day after the other male instructor.
7.
Katie has her weekly piano lesson the day before she sees Collins, and the day after she sees Graves.
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WHO SHOT AAILLEN?
BY CONSTANCE ADAMS
***
fast season was the most popular ever for the soap opera "Lighthouse Love"-thanks, no doubt, to rhe writers who
Moroccan prison, at one of the family's oil well sites, or at a press conference. The fifth wa's proven to be the guilty party.
introduced into an already complex plot the mysterious shooting of Millen, the show's notorious villain, Boss Nailer. the
(At the beginning of next season, of cou$e, Mitten will somehow retum from the dead when the actor who plays his part retums from shooting a moyie in Hollywood.) Can you figure out each woman's fuu name (last names are Bridge,
show's dedicated district atrorney. had ro son out rhe evidence against the five women (Contessa, Di, Gretyl, Lily, and
Maybetline) who had well-known motives to kill Millen. By the season.'s end, four of them had produced iron-clad alibis: at the time of the murder they were at the country club, in a
l.
'
The women who were at the couutry club and the oil well are, in some order, Mrs. Roko and Angelo's wife.
Fox, Moss, Roko, and White). her husband's first name (Angelo, Fuzz, Hatcher, Quinn, or Xavier), and her alibi, if
any? 8.
Fuzz aryl Quinn were relieved when their wives were proven innocent of the shooling.
Quinn and his wife don't own any oil wells.
name
First Angelo (who isn't
Mr
Solution is on ospe 56.
Last
name
Husband
Atibi
Moss) isn't Lily's husband.
Mrs. Moss, who was innocent herself, stispecred that either Di or Lity was guilty. Contessa Bridge (who isn't married to Angelo) had an alibi, which did not involye a press conference.
Di and Gretyl are married toXavierand Mr. Fox in some
order Mrs. White had an alibi which didn'tinvolve an oil well. (|)
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Angelo Fuzz
Hatcher Quinn
Xavier
DELL LOGIC PIJZZLES February 1995
27
OAK HILTS TEE-OFF
***
BY GTENN SCHOEN
The Oak Hills Country Club features five golfcourses, called the Green, Orange, Red, White, and Yellow Courses. Five
friends-Anne, Barry, Carla, Denis, and Eunice-played gotf last Saturday, each on a different course, and they agreed to me€t in the clubhouse afterward to comDare scores over
l.
Carla (who didn't play the Yellow Course) arrived immediately before the one who played the White Course.
lunch. Inst names are Morley, Norton, Parker, Sherman, and golferls full name with the Thompson. Can you match -each course he or she played, and tell in what order they arrived in the clubhouse afterward? Solution is on page 56.
8.
Barry arrived immediately after the one who played the
Order
Green Course. 3.
Thompson arived immediately after the one who played the Red Course.
First
name
Last
name
Course
Sherman arrived immediately before Denis, whose last name is either Parker or Thompson.
Norton arrived immediately before Eunice. 5.
Morley arived sometime after the one who played the White Course. Norlon (who isn't Barry ) played either the Green or the Yellow Course-
7.
Parker arrived imrnediately after Anne.
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Third Fourth Fifth Green Red
White
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Morley Norton
Parker Sherman
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DELL LOG|C ?UZZLES Fehrunrv taas
1..
CRCDIT FOR CHRISTAIIAS BY CHRIS PERTON nd the red
56.
***
Every year iri November, Sylvia hosts parties at which a saleswoman comes to show-and hopefully to sell-merchandise. This year Sylvia held them on five consecutive Friday nights (on the lst, 8th, 15th, 22nd, and 29rh). Each
Violet, and Xenia) gave Sylvia a different amount of credit ($50, $100, $150, $200, and $250), which Syliia then used to purchase Christmas gifts. Can you discover the full name ofeach saleswoman (last names are Berger, Davis, Hayward, Kent, and Simms), the evening her party at Sylvia's home took place, the merchandise she sells, and the amount of credit that she gave to Sylvia? Solution is on page 57.
party featured a different type ofmerchandise (art, cosmetics, food containers, lingerie, and toys). All ofthe parties were so successful that each saleswoman (Gretchen, Marissa, Rose,
The cosmetics party was sometime later in the month than Violet's, but sometime earlier than Ms. Hayward's.
5.
Marissa's party wasn't the first or last of the five.
6.
Gretchenb party was sometime after the one tiatearned Sylvia $100 in credit, and sometime before Ms. Kent's
Sylvia eamed the most credit at the last party of the' month; the merchandise sold that night wasn't art or lingerie.
pary. 7.
Ms. Davis's party eamed Sylvia more in credit than
The first party, which earned Sylvia $150 in credit, wasn't given by Rose.
Violet's, but less than the one held on the l5th.
4,
The pany ar which toys were sold was sometime before the one that earned Sylvia $50 in credit, and sometirhe after the one by Ms. Simms (who doesn't sell art).
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November 22 November 29 $250
$20c $150
$100 Art Containers Cosmetics Lingerie
I Berger
{
Davis Hayward Kent Simms
DELL LOGIC PUZZLES February 1995
THI BRIDE WORE SHINPADS
BY RANDALL L, WHIPKEY
Notan Spahn, pitcherofthe Smashers in the Summerset Coed
Soflball teague. called a timeour in the third innins for a the mound- and proposed ro carcher iammy T"".,ing.1, Banks. After she had had time to thint it over- she callei
ano{her timeout in lhe sixth inning and acceDted. Tammy and Nolan decided ro have their wedding at hlme ptare of tne softball field, and to have their eight teammates act as their wedding party: maid of honor, best man, three bridesmaids_ and three groomsmen. In slow pitch soflbali, there are ten
players on a team; in addition to the pitcher and catcher, there
l.
3.
Mr. Snider (who isn't Dwight) didn't escort either yvette
Ms. Berra and Joe were immediately fo[owed by the
10.
Chad esconed Ms. Reese.
ll.
The second baseman isn't Ms. Mays.
The three groomsmen (in no particular order) were The three bridesmaids (in no particular order) were
The right center fielder is a woman.
12. Carmen and the female right fielder helped select rhe striped dresses for the women in the wedding party,
Leah, Ms. Mays, and the first baseman
13.
5.
Yvette and Ms. Reese arranged a bridal shower for Tammy after a game.
t4. If
6.
The third baseman (who isn't Chad) and Mr. Clemente
organized Nolan's bachelor party at the Summerset Sports Bar.
Ms. Berra doesn't play first base,
Order First name
c d
Last name
E
o
3
Position Role
First name Last name (E
Position Role
30
DELL LOGIC PUZZLES February tg95
short_
or Susan. 9.
Ramon, Mr. Maris, and the third baseman.
7.
irlfielders-first baseman, second baseman,
man, and then by three bridesmaids, each escorted by a gfoomsman..
second baseman and Mr. Clemente.
4.
are four
stop, and third baseman--:and four outfielders_left fielder, lefr cenrer fielder, righr cenrer fielder. anO riehr nelOer. Th; eight tearnrnates are four women--Carmen, Gah, Susan, and Yvette-and four men -Chad, Dwight, Joe, and Ramon; lasr names are Berra, Clemente, Drysdale, Ford, Maris, Mays, Reese, and Snider. Can you find each player.s full name, playing position, and rol€ in the wedding party, and discover the order in which the eight walked up the first baie line after the vows were exchanged? Solution is on page 57.
After the ceremony, the bride and groom were followed rn order by the maid of honor escorted by the best
2.
****
Ms. Drydale's escort doesn't piay left center field. was Joe, one of the infielders, whojokingly suggested at the reception thatwedding guests should have thrown
softballs instead of rice. 15.
Mr. Ford wasn't part of the last couple in line.
YOUR STORE BY MARGARET EDMISTON ollCer,
Ihe
clq last lys,
****
Five customers stood in line at the Your Store Convenience Mart last Sunday moming. Each spent a different amount on gas, each amount being a whole number of dollars from $l to $10- And each also bought another item as well (bread, a candy bar, milk, a newspaper, or soda). The customers were
Ms. Fugate, Mr. Grimes, Mr. Hebel, Mr. Jacksol, and Mr. l-ang. Can you find the order in *hich they stood in line, and match each with the amount of money he or she spent on gas and the second item he or she bought?
Solution is on page 57.
0o' ,Ver
fter
l.
The five c\tomers were.the first in line, the one who bought a cand4barl candnbarl Mr Grimes, the one who spent $8 on gas, and Ms.l Ms.lFugate (who didn't buy milk).
2.
The person in line next after",,, Mr. Jackson was a man who bought anewspaperandspentaneven numberof dollars for gas --one dollar less. as it happened. than Jackson himself spent on gas.
3.
The person who bought soda was rwo places in line behind Mr. Hebet, who spent $5.
4.
The third customer in line spent one dollar more on gas than some other customer.
57.
5.
The one who bought milk spent twice as much on gas as the first person in line.
Order Customer Amount
ltem
Amount o
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Fourth Fifth Bread Candy bar
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Newspaper
I
Soda i
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DELL LOGIC PUZZLES FebtuaD, 1995
3I
INTERNATIONAI PICNIC
****
BY DEIRDRE DOWNES
of thes€ children was born in a different country (China,
A potluck picnic is held annually for families with adopted children from other countries. This year, the firstfive families tq arrive (surnamed Baker, Metzger, Oates, Schroeder, and Trevino) each had one adopted child (two girls---Carly and Marissa-and three boys-Jared, Kevin, and Nathan). Each
Ethiopia, India, Korea, and Peru), and each is a different age (in whole numbers of years). Can you determine the order in which the families arrived at the picnic, and identify each
child's full name, country of origin, and age? Solution is on page 57.
l.
The five children are Nathan (who isn't from China), the Schoeder boy, the oldest of the five, the chitd from India, and the child whose family arrived second.
2.
Marissa is older than the Baker child, but one year younger than thc child whose family arrived last.
3.
The Trevinos arrived sometime after the family whose child is from China.
4.
Carly Metzger, thd two-year-old, is the youngest of the five children.
5.
The Oates family (which didn't arrive third) arrived immediately after Marissa's family.
6.
The six-year-old (who isn't Kevin) quickly made friends with the Trevino child.
7.
The child from Ethiopia is one year younger than the one from Korea, but somewhat older than the child from Peru.
8.
Marissa and the five-year-old played together in the playgrouod.
Age o c) q)
cl;lelElx First Second Third Fourth
o
Korea Peru Baker Oates
Schroeder Tr
32
DELL LOGIC
P
UZZLES February
1995
('
I .;
o o
a F
c
E
(l)
(U
:<
f
o
L
CABIN FEVER,
****
BY JEAN ROWELL
kind of stnrcn[e (an A-frame cotlage, dome, landbound house-
found each of the five (Blagden, Glendon, Kingsden, Langdon, and Ogden) adding a different amenity to his hideaway---either a barbecue pit, boat dock, porch, satellite dish, or sauna. Can you match each brothe with his retreat,
boat, log cabin, or trailer) near a different town (Kiva,
improvement, and nearest town?
Every spring the Alexander brothers are eager to visit their wedkend retreats to see how they fared over the winter, and to begin various improvements. Each retreat is a different
Solution is on page 58.
Naubinway, Point Abbaye, Toivola, or Traunik). This spring
l.
10.
Neith€r Ogden's camp nor the Traunik property has the new porch.
The Naubinway property (which isn't the hailer) isn't Glendon's.
ll.
Neither the Toivola hideaway nor the A-frame was
Neither the log cabin nor the Toivola proprty is owned by Blagddn.
12. The Traunik property remains unequipped with
Langdon owns neither the A=frame nor the retreat near
Toivola. 2.
3-
improved with a boat dock.
One man has towed an old houseboat into the woods for his getaway; it doesn'tsport the new sauna.
6.
Kingsden (who helped build his brother's A-frame)
the houseboat.
14.
The A-frame isn't near Kiva.
Brother Retreat
lmprovement
Town
added neither a porch nor a sauna to his own property.
7.
The brick barbecue pit wasn't added to either the dom€ or the Traunik property.
8.
Blagden owns neither the A-ftame nor th€ PointAbbaye hideaway.
9.
Neither the dome nor Ogden's property is near either
Kiva or Naubinway.
34
DELL LOGIC PUZZLES February 1995
sauna.
13. . Blagden (who didn't build the new porch) doesn't own
The porch wasn't added to the Point Abbaye structure-
5.
a
---
CARTOON CRITTERS BY RANDALT n,
is te It,
****
L. WHIPKEY
Five new prime-time cartoon series haye been scheduled on various cable networks for the upcoming season. Each series features a pair of animal caricatures who have some very human traits; they include a bear, dog, fox, groundhog,
l.
mouse, opossum, parrot, pig, and rooster, as well as a puntrocker cat. Names are Binky, Bombel Fen, Jojo, Lu, Matt, Mugsy. Red. Skimpy. and Yu. Can you find the names and species of each pair? Solution is on page 58.
Fen, Mugsy, and the bear who's allergic to honey are featured in three different sefles.
2.
One show features a big-eared mouse and a long-nosed dog.
3.
The slow-witted fox (who isn't Bomber) isn't paired with the soflspoken rooster.
Yu's cartoon cohort is neither the hyperactive opossum who never plays dead nor the fastidious pig. 5.
Binky (who isn't the bear) isn't on the same show
tt.
Fen (\&ho isn't Lu's pall isn't the roosrer.
'1.
Malt (who isn't the dog) isn't paired with Fen.
8.
Skimpy, who is the shadow-boxing goundhog, isn't?artner to the fox
9.
The series featuring Binky and the rooster will be shown on a different night from the one starring Lu and the politically coffect parrot.
10. I
i.
as Mugsy.
Red's television buddy isn't the opossum.
TheinagazineTV Tal,t recently devoted
a
feature article to the new "Bomber & Jojo
Neither Mugsy nor Red is the speechifying parrot.
Lu is neither the bear nor the fox. 14. Malt (who isn't the rooster) isn't paired wi{h Lu.
Name
Animal
Name
Animal
and
and
ano
ano
and DELL LOGIC PUZZLES February 1995
35
CIRCLE OF
WO'IAEN
****
BY MARK T, ZEGARELLI
Eleven women (Heidi, Ivy, Joanne, Kiandra, Lyn, Mabel, Nona, Olivia, Patti, Qula, and Ruth) gathered for a discussion group, sitting in a circle on two couches and five chairs, as shown below. They b€gan the session by introducing themselves in clockwise order, beginning with one woman at
random. Can you decide the full name of each womat (last names are Ayers, Blaine, Colby, Dobson, Effingham, Fox, Glass, Stone,Townsend, Volpone, and Zapata), where she sat, and what order she spoke in? Solution is on page 58.
l.
The first to introduce hcrself was Joanne, who sat in a chair'
2.
The second was Kiandra, who is married.
3.
The fourth was Mabel and the fifth was Nona; their last names are, in some order, Blaine and Effingham. The sixth was neither Ms. Fox (who sat in a chair) nor Ms' Volpone.
5.
The seventh and eighth were, in some order, Ruth and Ms. Townsend; at least one of them is married.
6.
The ninth and tenth were Ms. Ayers and Ms. Glass, in that order; they share the same marilal stalus.
7.
The eleventh was Ms- Stone, who is married.
8.
Olivia and Qula are sisters-in-law
9.
Lyn and Ms. Dobson sat adjacent to each other on one of the sofas.
10.
Ms. ( olby sat belween lwo married women.
11.
Heidi and Ms. Zapata are siste$-in-law
12.
Ms. Blaine didn't sit between two single women.
13.
Olivia and Patti didn't sit adjacent to each other; they both
sat on the same kind
of
seat (either chair or sofa).
14.
Of the four married women, only Ivy sat on a sofa rather than in
a
chair'
ffi 36
DELL LOGIC PUZZLES February 1995
REPI.ACEMENT
WEEK
****
BY GLENN SCHOEN
(last Fox,
It was a busy week for the members of the Random Access Computer Users Club. Five members (Alberto, Glenda.
sat,
Lawrence, Selena, and Zeke) each purchased a different new item for his or her system (a disk drive, a graphics monitor, a keyboard, a modem, and a printer). Each item was pur-
e
e 58.
l.
The Thursday purchase was either the one made by Eng or the printer.
2.
f,awrence made his purchase sometime after the one who bought the graphics monitor, and sometime before
chased on a different day, Monday through Friday. Can you find the full name of each club member (last names are Eng, Jipescu, Knowles, Pascayo, and Thornton), the day he or she went shopping, and what he or she purchased? Solution is on page 58.
8.
Zeke is Knowles.
9.
The graphics monitor wasn't purchased by Selena, and wasn't purchased the day before Selena made her purchase"
Jipescu.
Day
1.
The keyboard wasn'r purchased on Wednesday.
1.
Glenda and Pascayo made their purchases on consecutive days, in some order.
i
.
First
name
Last
name
ltem
Selena mide her purchase the day before the person who
bought the disk drive.
6.
Jipescu shopped the day before the person who bought the modem.
Thornton didn't go shopping on Monday.
o E
(lJ
(!
o
-g
o
to
J
(tr
o o o a N _9
E q)
.9
o
o
o TL
Monday
T
Eng
Jipescu Knowles Pascayo
DELL LOGIC PUZZLES Februan 1995
37
WTHOUT A CIUE
****
BY ALEX KNIGHT
Arbuckl€, Babette, Clive, Dahlia, Esmeralda, and Florian sat down last night for a game of Clue. In Clue, a deck of cards represents the possible suspects (Mr. Green, Colonel Mustard, Mrs. Peacock, Professor Plum, Miss Scarlett, and Mrs. White), weapons (candlestick, knife, lead pipe, revolyer, rope, and wrench) and rooms (ballroom, billiard room, conservatory, dining room, hall, kitchen, library, lounge, and study) in a murder mystery; each suspect, weapon, and room is represented on one card. Florian divided the cards into three piles and.picked one suspct, one weapon, and one room at random; these cards were the solution to the mystery, and they were set aside sight unseen. Florian then shuffled the remaining l8 cards and dealt three to each player, At various times in the game, a player may suggest a combination of susp€ct, weapon, and
1.
2.
WhenArbuckle suggested that the crime was committed by Mr. Green with the candlestick in the lounge, Babette (haying none of those three cards) passed, and Ctive (having at least one of those three cards) disproved it.
room as a solution to th€ mystery; after such a suggestion, each player to the left in tunreither passes (indicating that he or she doesz', hold any of th€ three cards in thc suggestion) or disproves the suggestion (indicating. that he or she does hold at least one of thg three cards); as soon as someone has disproved the suggestion, the tum is over. After 16 suggestions had been made and disproved, the players (who were not very good at logical thinking) didn't realize that there was enough information to solye the mystery. Can you do better than they did, by identifying the three cards in each player's hand, and determining which suspect,
weapon, and room were not held by anyone-and were therefore th'e solution to themystery?Nate. Itis possible that, for deceptive purposeS, a player might hold one or more of the cards in his or her own suggestion. Solution is on page 59.
l0: When Arbuckle suggested that the crime was committed by Colonel Mustard with the candlestick in the billiard room, Babette disproved it,
ll.
When Babette suggested that the crirrie was committed
byProfessorPlum with therevolver in the lounge, Clive
When Babette suggested that the crime was committed by Mr. Green with the lead pipe in the library, Clive and Dahlia passed. Then, before Esmeralda could say any-
passed, and Dahlia disproved it.
When Cliie suggested that th€ crime was committed by Professor Plum with the rope in the study, Dahlia, Esmeralda. Florian. and Arbuckle passed, and Babetl,e disproved it.
thing, Florian passed. Esmeralda scolded Florian for spdaking out of tum, and said she could disprove the suggestion herself, but it didn't occur to any ofthe plalers to make use of the information Florian had glven away.
When Dahlia suggested that the crime was committed by Mr. Green with the wrench in the lounge, Esmeralda and Florian passed, and Arbuckle disproved it.
3.
When Esmeralda suggested that the crime was committed by Mrs. Peacock with the candlestick in the dining room. Florian passed. and Arbuckle disproved i1.
13.
4.
when F'lorian suggested that the crime was committed by Professor Plum with the wrench in the kitchen, Arbuckle disproved it.
t4.. When Florian suggested that the crime was committed by Miss Scarlett with the revolver in the dining room. Arbuckle disproved it.
5.
When Arbuckle suggested that the crime was committed by Miss Scarlett with th€ lead pipe in the hall, Babette passed. and Clive disproved it.
15.
6.
When Babetre suggested that the crime was committed by Mrs. Peacock with the knife in the hall. Clive, Dahlia, and Esmeralda passed, and Florian.disproved it.
16.
When Clive suggested that the crime was committed by Colonel Mustard with the wrench in the study, Dahlia, Esmeralda, and Florian passed, and Arbuckle disproveil it.
17. Th€ playeis followed the curious
mitted by Mrsr White with the revolver in the ballroom, Babette disproved it.
.
?.
8.
When Dahlia suggested thal the crime was committed by Miss Scarlett with the rope in the conservatory, Esrneralda disproved it.
9.
When Esmeralda suggested that the crime was committed by Mr. Green with the lead pipe in the kitchen, Florian passed, and Arbuckle disproved it.
When Arbuckle sugg€sted that the crime was com-
'
When Batiette suggeited that the crime wds committed by Mrs. White with the knife in the conservatory, Clive disproved it. house rule that
if
anyone was dealt a hand of three cards of the samelype (three suspe€ts, three weapons, or tfuee rooms) at the beginning of the game, he or she had to announce it, and the cards would all be remixed and redealt.
See
grid on thefacing page.
BATIER stion, lat he
ihon) does & has
UP!
****
BY DEIRDRE DOWNES
Five married couples (surnamed Krebs, Lopez, Mincus, Nye, and Ong) play softball as a team. These women (Anna, Barb, Chloe, Diana, and Ebony) and men (Frank, Gus, Hal, Ian, and Jack) have played together for so many years that they have an agreed-upon batting order, with only an occasional substitution due to injury, advanced pregnancy; or vacation trips.
Can you determine each player's full name. position on the team (there are one catcher, four infielders, four outfielders, and one pitcher), and the order in which they come.to bat? Note: The order repeats, with the first batter irnmediately following the tenth. Solution is on page 59.
I, the
lidnl mysthree ipect, were ) that, ne of ie
Jy,
l. kague
Order
rules require altemating male and female batters.
2.
Spouses never bat consecutively.
3-
The four outfield positions are played by Ebony, Ian, Mr.Iopez, and theplayer who bats fifth;no two ofthese four ever bat consecutively.
4.
Jack takes his first at-bat sometlme betbre Chloe and sometime after Ms. Mincus.
5.
The fow infield positions are played by Diana, Ms. Mincus, Barb's husband, and the player who bats fourth.
First
name
Last
name
Position
comn the
Gus's wife (who isn't Ms. Krebs) bats just after Frank.
Anria bats just before Gus and just after Mr. Ong. The pitcher bats third. Ian bats seventh, immediately before Ha1's wife.
tted ralda
sed 'oom,
p(!
o o c) 6 J o o (L
nt if )
t)rPe
rt the
Arbuckle
and
Babette
t,
E
.9 E (L
-9 (g
o
o
=c
(tJ
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o) O l< J E
I
p g
co)
.c,
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Clive Dahlia Esmeralda Florian
DELL LOGIC PUZZLES February 1995
THE UNFOR.GOTTEN BY RANDALL L. WHIPKEY In his latest film, Tft e U nforgot ten, action star Flint Westwood plays aging gunfighter Brandy Alexander, who reluctantly leayes peaceful retirement as a mushroom farmer to rid the territory of five very bad hombres. In the movie. Brandv faces each of the viltains (Bitly Bonner, Moondance Cassidv. Doc Easler. Wyan Urp. and John Hardly Westem) in a sho*down
**** in a different town (Booty Hill, Crumpet Creek, Dog City, El Peso, and Silver Town). The-showdowns take place on five
consecutive days, Monday though Friday, of a truly hard work week. Can you find each day's villain, his nickname ('Deadeye," "Full House," "Snake," "Two Bits," ard ,,Widow-
maker'), and the town in which Brandy challenges him? Solution is on page 59.
l.
"Two Bits" doesn't meet Brandy in El peso.
2.
Brandy finishes with Billy Bonnet sometime earlier in the film than his showdown in Crumpet Creek (which isn't on Friday).
3.
Brandy's battle with Wyatt Urp doesn't take place in hardscrabble Booty Hill.
4.
"Deadeye," "Widowmaker," and Doc Easter are all three bitter enemies of Brandy because he had stolen their shares of the money from a bank robbery the four had pulled together many years earlier
56.
Booty Hill isn't the site ofBrandy,s run-in with,.Deadeye.,'
The shootout with,'Full House', doesn't take Dlace on
Monday or Friday.
7.
Brandy confronts John Hardty Western the day before he meets with the notorious ,.Two Bits" (which isn't on Fridav).
8.
Neither Doc Easter nor Moondance Cassidy is nicknamed "Snake."
&
DELL LOGIC PUZZLES February 1995
9.
On three consecutive days, Brandy meets up with Wyatt
Urp, "Widowmaker," and a villain in El peso. in that
10.
When Brandy gallops into SilverTown, the bandit who is hiding in an alley, planning to ambush our hero, isn,t
'Snake."
Day
Nickname
NAme
Town
DINNER PARTY y, El
five hard lame
low'|
e
BY MARK
I
****
ZEGARELLI
The Elkinds invited fourcouples (the Fischers, Glasses, Marquezes, and Zigmonds) to dinner recently- The five men @ave, Irwin, Quenrin. Richard, and Witliam.; and five women (Judith, Nancy, Olga, Ursula, and Yetta) sat inchairs arranged around the table as shown below. Each person at the table has a different occupation (an aerobics inirructor, botanist, cel-
59.
0att
1
.
Mr. and Mrs. Elkind sai respectively at the east and west ends ofthe table.
that
2. who
list, hardware store owner, jeweler, optometrist, private detective, sociology professor, fiix attomey, and video producer). Can you find the full name and occupation of the person in each chair? Note.. Seats are considered to be ..next to" each other even around corners: thus seat 2 is next to and immediately between seats I and,3. Solution is on page 60.
Seat
Firsl
name
Last name
Occupation
No husband saton the same side ofthe table as his wife.
The jeweler-who is of the same sex as the yideo producer-sat directly across from Yetta.
isn't ,1
The botanist sat on the north side of the table, to the immediate teft of Mrs. Zigmond; each of these two sat next to at least one marl.
5.
William didnt sit next to Olga. Judith sat immediately between Mrs. Marquez and the priYate detective. One woman sat immedialely between Mr. GIass and Mr.
Zigmond.
8.
Dave sat direcily across from Mi. Fischer.
9.
Ir,lrs. Zigmond is either the tax attorrey or Richard's wife, bur not both.
I0.
The hard ware store owner sat nexl lo Ursula, and ly across from the optomertrist.
d
irect -
11. Nancy sat next to Quentin, and directly across froni the sociology professor
12, Mrs. Fischer and Mrs, Glass
are, in some order, lhe
aerobics instructor and the botanist.
.13.
Richard, Mr. Marquez, and the cellist all sat on the same side of the table.
trtrtrtr trtrtr
N
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lt +
il
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J',
I
t-_l t7 tl
l l
|
DELL LOGIC PUZZLES February 1995
ti
ii 4t
i1
il
YOU.MUST HAVE BEEN A BEAUTIFUL
BABY
BY JEAN ROWETL
On the occasion of Fenetville's centennial, The Dailt Blab published a series ofbaby pictures of town notables-the fire chief, mayor, police chief, and school superintendent, as well as a famous docror and a best-selling writer Each picture appeared on a different day from Monday through Satufday, and each tyke was posed in a different setting (in a bathtub,
on a blanket, on a rocking horse, on a rug, on a hicycle, or in a wading pool). The six subjects were identified only by their first n4mes (Cherise, Clifton, Deborah, Gregory, Jessica, and Mitchell). Can you find the first name, adult occupation, and pose of each day's photo subject? Solution is on page 60.
l.
The fire chief appeared one day before the infant in a bathtub, who appeared one day before Clifton.
2.
The toddter riding
a
tocking horse appeared one day after the mayor, but one day
before Gregory.
3.
Clifton wasn't shown on a blanket.
4.
The police chief (who didn't appearon Wednesday) isn't Deborah.
5.
Gregory wasn't shown splashing in a bathtub.
6.
The school superintendent and the tot on the tricycle appeared on consecutive days, in one order or t_he other
/.
The doctor is reirher Clifton nor Jessica.
8.
Cherise (who was posed neither on the rug no-r on the rocking horse) didn,t grow up lo become rhe mayor.
9.
Jessica appeared one day after the child on the blanket, who appeared one day after the police chief.
10.
The mayor (who wasn't shown in a bathtub) isn't Clifton
u.
Jessica (who isn't the fire chief or the writer) wasn't photographed on a rocking horse.
Day
.42
DELL LOGIC PUZZLES February 1995
****
Pose
DEAR. or rn
their t,
and
r,
and
JOHN
Five young women who shared a dormitory in their freshman year at college had one thing in common: before leaving for college, each had sworn undying devotion to her high school boyfriend who was attending a different college far away. Much to tho young women's own surprise (though not, perhaps, to the surprise of older and wiser hearts), after a month at college each found herself writins a "Dear John" letter to herboyfriend explaining why her feelings had changed. Each of the women (Alicia, Barb, Jessica, Julie, and Winona) gave her boyfriend (John Johnson, John Jones, John Roberts, John Smith, or John Williams) a differentexcuse for her change of
l.
****
BY DEIRDRE DOWNES
John Johnson's romance had lasted twice as long as Alicia's, which had endured twice as long as th€ romarce terminated on the adyice of a.psychic.
heart. One said she hated her boyfriend's obsession with baseball, one objected to long-distance romances, one admitted to having met a new boyfriend, one said she was acting on a psychic's advice, and one claimed she was taking religious vows. As it happened, each young man's youthful ardor had cooled as well, so no heart was seriously injured. Can you match each woman with her boyfriend, her excuse, and the
of months (a whole number in each case) th€ir romance had lasted? Note.' Solvers who wish to skip much of number
the arithmetic needed to solve this puzzle may fiad an extra Solution is on page 60clue on page 63.
8.
John Roberts's rofirance lasted longer than John Smith's.
9.
One woman broke off a romance that had begun over the summer, just thrQe months Previously.
Julie (whose boyfriend wasn't John Johnson) had been in her relationship one third as many inonths as Winona had been in hers.
Woman
Man
Reason
Months
Neither John Roberts nor John Williams was the baseball fanatic.
4.
Exactly two of the women had first initials that matched their boyfriend's last initials.
5.
The shortest rorirance of the five was Jessica's; the longest lasted 24 monGs.
6.
John Robens
didn't believe his girlfriend's insistence
thal she hadn't met anyone new.
?.
The woman who said she was taking religious vows had been in her relationship exactly half as long as John Jones had been in his.
o
DELL LOGIC PU?ZLES Februory 1995
/|:l
MINOR LEAGUE
****
BY RANDALL L. WHIPKEY
Each oftheeight teams in therookie North Atlantic
L€ague-
which features newly signed professional players-is a farm for a different major league team. The eight teams are based in the towns of Cold Harbor, Gravesend, New Chartres, Ocean City, St. Bamaby, Summerset, West Ham, and Wintergle$ thek team names are the Admirals, Dukes, Meteors, Mountaineers, Parrots, Sharks, Suns, and Waves; the major
league teams they aro afhliated witl are the Baltimore Orioles, Colorado Rockies, Houston AstrOs, New York Yankees, Pittsburgh Pirates, San Francisco Giants, Seattle Mariners, and Texas Rangers. Can you find each minor league team'$ city, name, and major league affiliation, and discover how the teams ranked in last yea.r's season? Solution is on page 61.
The top four teams ilr the ranking are, in no particular order, New Chartres, the San Francisco Giants farm team (which finished second), the Meteors, and the
The Summerset Suns finished one place ahead of the Pittsburgh Pirates farm team and two places ahead of the Mountaineers.
Sharks.
fie
9.
New York
ahead
YanJcees
affiliate finished immediately
The Winterglen team isn't named the Sharks or the Meteors.
of Ocean City.
St. Bamaby isn't the Pittsburgh Pirates farm team.
The Waves finished immediately ahead of West Ham, which finished immediately ahead of the Seattle Mariners farm t€am. The Baltimore Orioles affrliate finished one place behind Winterglen, which finished one place behind the
Admirals.
10.
The Parrots aren'l from Ocean City.
ll.
The'New Chartres team isn't named the Admirals or the Mountaineers.
12. Cold Harbor finished one place behind the Meteors. 13.
The Sharks linished somewhere ahead of the Texas Rangers farm team (which isn't in Wintergten).
14. The Houston Astros farm team isn't the Mountaineers.
The Seattle Mariners farm team isn't in New Chartres.
The Dukes (who aren't the San Francisco Gian* affiliate) didn't finish last.
City
Team
Afiiliated with
i
i I
i I
ti I
?
I
J
DELL LOGIC PUZZLES February
1995
4,lt
ALBA's ABODES
****
BY ELIOT GEORGE
Georgian, and Victorian) and located in five different (Kentfield, Lanhamton, I',lew Durham, Oak Creek, and er Village). Can you discover the month in which each purchased their new home, the style ofeach house, the in which each is located, and the number of bedrooms Solution is on page 6 each has?
Alba Armskong is a real estate agent with a prosperous business in Snoore County- Looking over her record of 1994 sales, she noted that her frve most lucrative sales of the year
(to couples named Quinn, Uknalis, Weyrick, Yardley, and Zubin) took place in five consecutive montlts. These houses were in five different styles (art nouveau, Bauhaus, colonial,
l.
The house in New Durham has exactly three fewer bedrooms than one of the others.
2.
Alba's first sale was lhe colonial.
3.
The Weyricks (who didn't buy the Bauhaus) purchaqed theirhouse the month after the Quinns; one of these couples bought the house in Palmer Village.
The Uknalises purchased a house in April that had two fewer bedrooms than the house in Kentfield. 5.
Alba sold the house in Lanhamton sometime after the Georgian.
b-
The two houses that have four bedrooms were purchased exactly two months aPan; the Zubins bought one of them.
at.
Alba sold the Victorian the month before the house in Oak Creek, and the month after'she sold a house to the Yardleys.
8.
The art nouveau house has exactly twice
as
many bedrooms as one of the other
houses.
9.
A five-bedroom house was purchased in March.
Couple
&
DELL LOGIC PAZZLES February 1995
Style
lown
.
Bedrooms
FARCE
*****
BY SCOTT MARLEY
accepted quickly when his old college roommate. Dotv. invited him to visit for a week. Since their e ns
qe6
days. Ralph had become fabulously wealthy heading
small company that produced computer software so adthat no one tlut Ralph himself quite understood what did. Now Ralph lived in a lavish mansion in which an entire in the form of a five-srory tower as shown below, was
just to bedrooms-Ralph's own bedroom and
14
bedrooms. Because Ralph had trouble keeping the straight, he had numbered them from 1 to 15 as shown. addition, each bedroom was decorated in two colors. Ralph invited another friend ofhis, a woman named Dorabella, stay the week, and he invited each of his guests to stay in
Only ten colors were used in this wing of the house: amber, burgundy, crimson, emerald, gold, ivory, jet, peach, silver, and turquoise. Each room was decorated
in two of these colors, and each color was used in exacdy three rooms. No two rooms were decorated in the same pair ofcolors.
different bedroom each night from Monday to Sunday. Thus between them Barnaby and Dorabella stayed in all.14 of the guestbedrooms during the week. Unfortunately, Bamaby and a
Dorabella took their meals at different hours, and absent' minded Ralph never thought to introduce them or €ven mention the presenca of one to the other, so that Bamaby and Dorabella spentseven days under that enormous roofwithout actually meeting. Can you find the two colors each loom is decorated in, discover which room is Ralph's, and discover when and by whom each of the guest rooms was occupied? Note.'Solvers who want to skip rdost ofthe arithmetic needed to solve this puzzle-can find an extra clue on page 63. Solution is on page 62.
9.
Bamaby stayed in atmostone room (andpossibly none) decorated in ivory.
10.
Three days after Dorabella stayed in the crimson and gold room, Bamaby stayed in the emerald ard peach room,
11.
No room was decorated in both silver and turquoise.
No color was used more than once on any floor or in any vertical column of rooms.
12.
Barnaby never had a room that was bdth in the same vertical column as Dorabella's and on a lower floor.
On each night, Barnaby and Dorabella slept in bedrooms that were on different floors and which had no
13.
Someone slept one night in a room decorated in amber, and moved to the burgundy and ivory room on the same
colors in common.
floor the following night. Each night after the first, the sum of Bamaby's and Dorabella's room numbers was greater than the night
14.
Barnaby's rgom on Tuesday night wasn't decorated in emerald.
15.
Barnaby's room number on Monday night was three
before.
Ralph's bedroom was decorated in gold and turquoise.
i
times Dorabella's room number on Sunday night. The jet and silver room was never occupied by Barnaby.
stayed
in at least one room
decorated in
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DELL LOGIC PIJZZLES February
1995
47
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TILI THE FAT LADY
SINGS
BY MARK T. ZEGARELTI
The opera world raised a collective eyebrow when reclusive soprano Signora Algelica di Tempeste----on the advice of her
most frusted numerologist {ame out of retirement for just one month to give voice lessons. From Wednesday, January I, through Wednesday, January 29, she scheduled one lesson
taught eight stUdents that month; they were three (Deena, Jill, and Lilliae) and five men (Adam, Harold, Matt, and Xavier); tieir last names are B Fitzpatrick, Grauer, Kleiner, Stuart, Ventura, Wolf, Zaines. Can you match each student's full name with his
each Wednesday and two lessons each Saturday and Sunday.
her lesson or lessons?
(No student ever took two lessirns in one day.) In alt,
Solution is on page 6
she
l.
Harold and Fitzpatrick never had lessons on the same Saturday.
2.
Stuart had at least one lesson on an earlier day than at least one of Xavier's.
3.
Adam had more lessons rhan anyone else.
4.
Ventura's three lessons were on three consecutive woiking days for the Signora.
5.
Lillian aad Kleiner had two lessons each; each of Lillian's was exactly four days after one of Kleiner's.
6.
Matt's thee lessons were all on Sundays.
7.
Jill and Bradley had the lessons on the eighth and the 22nd in some order.
8. Tvoof Edward's three lessons were the Signora's first and last lessons 9.
Any day that Deena had a lesson, Grauer had one, too.
10. All 11.
of the month,
of Mr. Wolf's lessons were on later days than all of Jil['s.
Of Bradley, Fitzpatrick, and Kleiner, the two men had no lessons on any of the first three Wednesdays,
12.
Mr. Zaines (who isn't Adam) had lessons on the fourth and fifth ofthe month-
DELL LOGIC PUZZLES February 1995
*****
rlf,
a
h his taSe
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DELL LOGIC PUZZLES February
1995
41,
I l
$trIL€# TftWffiffi PAGE 8 Garcia is female, but she's not a senior (clue 3), so she's not Monica (clue 1); she must be Andrea. Randall's specialty isn't
history {clue 2). nor fine arts or lirerature (clue 4), so jt s science. Randall. then, isn'r McKay rwho isn't r}|e science expert clue l) or Brennan (clue 2), so Randall is Hardy. Monica isn't McKay (clue 1), so she's Brennan, and by elimi-
(clue l), so it was found in the refrigerator, and by elimination Norman's ruler was found under the table. In summary: Karen, scissors, bar Larry. box of crayons. refrigeraror Molly, pencil, cupboard Norman, ruler, table
nation McKay is Thomas. Thomas McKay's specialty isn't fine
arts or literature (clue 4), so it's history. Monica Brennan's specialty isn't literature (clue 5), so it's fine ans, and by elimination the literature expert is Andrea Garcia. In summary: Andrea Garcia, literature Monica Brennan, fine arts 3tn
Randall Hardy, science Thomas McKay, history
{g
ly ,s ln
d e
I ;
JUST MY BILLS PAGE 8 Check #(04 isn't for $20 or $60 (it can't have the greatest or smallest amount of ths four checks--clue 2), nor is it for $40 (the $40 check can'r have the smallest number-{lue 4). so check #604 is for $30. Check #607 isn't for $40 or $60 (clue 3), so it's for $20. Check #605 isn't for $60 (clue 1), so ir's for $40, and by elimination check #606 is for $60. The $40 check is for the electric bill (clue 3). Check #604 is for the water bill (clue 4). The check to the telephone company is for $20, and the $60 check is to Frack's (clue 2). In summary: Check #604. $30. water Check #605, $40, electricity Check #606, $60, Frack's department srore Check #607, $20, telephone
1 I
I I
I
I I
I I
FRUITS AND
VEGETABLES
PAGE 9 Molly didn't buy broccoli or zucchini {clue 2 ) or green peppers
(clue 4). so she bought spinach. Damon didn't buy broccolior zuccbini (clue 2). so he boughr green peppers. Damon also bought cantaloupes (clue 4). Harry didn't buy limes or nectarines(clue 3), so he bought apricots; hedidn't buy zucchini (clue 5), so he bought broccoli. Molly didn't buy neclarines {clue l). so she bought limes. By eliminarion, Edilh bought necrarines and zucchini. In summar': Damon, cantaloupes. green peppers Edith, nectarines. zucchini Harry, apricots, broccoli Molly, limes, spinach
I LOST AND FOUNO
PAGE 9
The box of crayons doesn't belong to Karen (clue l), nor to Molly or Norman (clue 3), so it's Larry's. The item tbund behind the bar isn't Lany's box of crayons (clue 3), nor does it belong to Molly or Norman (clue 3), so it's Karen's. The ruler doesn't belong to Karen or Molly (clue 2), so it's Norman's. The item found in the cupboard isn't Larry's box of crayons, th6 ruler, or the scissors (clue 4), so it's thepencil; therefore it. can only belong to Molly, and by elimination the scissors are Karen's. Larry's box of crayons wasn't found under the table
THE EAB OF THE BEHOLDEB PAGE 10 Gayle is Willis (clue 4). Nevins is a woman, but she isn't Agnes (che 2), so she's Linda. Linda Nevins doesn't listen to tapes (clue 6), so she likes her music live, and Agnes listens to tapes (clue 2). Agqes, then, isn't Quigley (clue 3) or Dryer (clue 5), so she's Fanshaw. Jeff isn't Quigley (clue 1), so Jeff is Dryer, and by elimination Quigley is Brian. Jeff Dryer likeslap (clue 1), and Agnes Fanshaw likes country western (clue 5). The one
who likes qlassical music is a man (clue 4), so he's Brian Quigley. Linda Nevins doesn't prefer rock and roll (clue 7), so she likes show music, and by elimination Gayle
Willis likes
rock and roll. The radio listener isn't Gayle Willis or Brian Quigley (clue 4), so this is Jeff Dryer. The CD listener isn't Brian Quigley (clue 3), so this is Gayle Willis, and by elimination Brian Quigle) lislens lo LPs. ln surnmary: Agnes Fanshaw, country westem, tapes Brian Quigley, classical, LPs Gayle Willis, rock and rotl, CDs Jeff Dryer. rap. radio Linda Nevins, show music, live THE S.O.F.T.E. TOUCH PAGE 10 The second team included Carla (clue 5), and the fourth team
inchided Paddy (clue 2). Lana and Ellie were on consecutive teams in that order (clue 3), which can only have been either second and third or else third and fourth; in any case, the third team included either Ellie or Lana, so Deyin and Norton, who . were a team (clue 1), weren't third; they also weren'tfifth (clue l), so they were first. Lana's team, then, didn't speak second (since Osgood's didn't speak first--{lue 4), so Lana was on the third team, Ellie was on the fourth, and the fifth team proposed motel discount coupons (clue 3). Osgood was on the second team (clue 4), so by elimination Mavis was on the fifth. Abner wasn't on the fifth team (clue 6), so he was on the tlrird, and by elimination Betty was on the fifrh. Carta and Osgood suggested the free sunblock, and Ellie and.Paddy suggested the free postcards (clue 6). Abner and Lana didn't propose the camera raffle (clue 4t. so Devin and Nonon did. and by elimination Abner and Lana propord lhc free film dereloping. ln summary; First. Devin. Norton. camera raffle Second, Carla, Osgood, free sunblock
I
tl
tf
l
li I
i
Third, Abner, Lana, free filr.n developing Fourth. Eltie. Paddy. free postcards Fifth, Bett)a, Mavis, motel discount coupons WIGS AND MAKEUP PAGE 11 No one is assigned simultaneous slots with the wig stylist and the makeup artist (clue 1). The two 8:00 time slots must be assigned to Claude and Diane in some order (as the others must
DELL LOCrc PUZZLES Februory
I
1995 5l
be ready by 8:00---
but her two slots'aren't consecutive (the only performer with consecutive slots is a man----clue 4), so her slots are at 7:20 and 7:40. Belle and Fritz both have their second slots after Hillary (clue 5), so they have the two 7:50 slots. The man whose slots ale consecutive (clue 4), then, can't be Claude, so he's Fritz, and therefore Fritz's first slot is al 7:40. Claude and Diane must
have the two 7:30 slots (clue 6), and by elimination tlle other 7:20 slot is Belle's. Belle is made up at 7:20 and wigged at 7:50 (clue 3), so Hillary's 7:20 slot must be for a wig, and Fritz's 7:50 slot must be for his makeup; at 7:40, then, Hillary gets made up and Fritz gets his wig. The man who gets made up before he gets wigged (clue 3) must be Claude, so Claude is made up at 7:J0 and wigged ar 8:00: by elimination. Diane is wigged at 7:J0 and made up ar 8:00. In summary:
Wigs:7:20.Hillary
Mal
7:30, Diane 7:4O,
7:30, 7:40, 7:50, 8:00,
Fritz
7:50, Belle 8:00, Ctaude
Claude
Hillary Fritz Diane
POINTS OF VIEW PAGE .I1 Mercedes and Toby photographed Robinet River and Hedgerow Hil[ ir1 some order, and Dixie and Julius photographed Goblin Grove and Vista Vale in some order (clues 2 and 3). Dixie didn't face in fte opposite direction from Mercedes (clue 5) or Julius (or she'd have photographed Robinet River---=clue zl-which she didn't--clues 2 and 3), so Dixie faced in the opposite direction from Toby, and lherefore Julius and Mercides also faced in opposite directions. Dixie, then, didnt photograph Vista Vale {since she and Toby faced in opposile direclions----clue 2), so she photographed Goblin Grove, and Julius phoographed Msra Vale. Mercedes photographed Robinet River (clqe 4), so by elimination Toby phorographed Hedgerow Hill. Toby didn't face north (clue J), so he faced east (clue 2), and Dixie, who faced in the olposite direction, faced w€st. Mercedes faced south (clue 3 ), and by elimination Julius faced north. In surnmary: Dixie, west, Goblin Grove Julius, north, Vista Vale Mercedes, south, Robinet River Toby, east, Hedgerow Hill
PIECE OF THE PIE PAGE 12 There were eight stices eaten in all (introduction), and everyone had at least one slice (clue
l).Therearefivewayslodivide
eight slices among four people so that each gels at least one: 5-l:l-1, 4-2-l-1,3-3-1-1, 3-2-2-l, ar.d 2-2-2-7. Btlt 5-1-1-1, 3-3-l-l and 2-2-2-2 are impossible (clue 4). [f rhe slices were divided, 3-2-2-l, then Magnolia would have had three slices and Rogers would have had one (clue 3), and clue 4 would be impossible. So the.slices can only have been divided 4-2-1-1. Magnolia had four slices and Rogers had two (clue 3). ten had two slices and is Rogers, and Piney had one slice lclue 4). Magnolia isn't Sloane (Sloane is male----clue 5), io she's Quilter, and by elimination Sloane is the other person besides Piney who had one slice. Since Sloane is malei(clue 5), he must be Ozzie, and by elimination Piney is Nell. Nell Piney is the only one who could have ordered wine (clue 5). kn Rogers and Ozzie Sloane ordered cola (clue 2), and by elimination Magnolia Quilter ordered milk. In summary: lxn Rogers. two slices. cola
Magnolia Quilter, four slices, milk NellPiney- one slice, wine Ozzie Sloane, one slice, cola
52
DELL LOGIC PUZ?LES February 1995
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PAGE 12 DIVE INTO STOCKS JEP increased by 57o (clue 3), and the $20 stock by 4570 (clue 4). VIP was purchased for $40 (clue 5), so it isn't either of the two that decreascd in value (clue.2); therefore it increased by 254a. XYZ wasn't purchased for $30 or $50 (clue 2), nor for $20 (clues 2 and 4), so ir was purbhased for $lO; it didn't lose l5Vo (clue l), so it tost 3570 (clue 2). The $50 stock lost 1570 (clue 2), so by etimination JEP was purchased for $30. LKB wasn't purchased for $20 (clue 4), so it was purchased for $50, and by elimination BMS was purchased for $20. In summary: BMS, $20. 45qa increase JEP. $30- 57o increase LKB. $50. 15olo decrease VIP, $40, 257o increase XYZ, $10,35Vo decrease
5.
IF
BIZARRE
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BREAKFAST
PAGE 13
Clues I and 4 each mention three consecutive people; since there werejust five people in all, there must be overlap b€tween clues I and 4. The only two ways these two clues can overlap is ifAdrienne is Zezel or if Marciullonis ordered the egg bagel. But ifAdrienne were Zezel, then she wouldbe third and Lianna would be fourth (clues I and 4), and there would be no way Glen and Steve could be two places apart in line (clue 3), so this is impossible. Thus the five people in order were Zeze\ Lianna, Marciulionis (who ordered the egg bagel), the one who ordered the whole wheat bagel., and Adrienne (clues I and 4). Glen and Steye were first and third in some order (clue 3), so. by elimination David was fourth. Adrienne isn't Bogard (clue 4) or Niles (clue 6), so she's Karros: Her bagel wasn't pumpernickel (clue 2) or raisin cinnamon (clue 5), so it was onign. David isn't Niles (btue 6), so Lianna is Niles, and David is Bogard. Glen is Marciulionis (clue 6), so Steve is Zezel. Lianna Niles didn't have the pumpemickel tragel (clue 6), so:she had the raisin cinnamon'bagel, and by elimination Steye Zezel had the pumpernickel bagel. In summary: First, Steve Zezel, pumpernickel bagql Second, Lianna Niles, raisin cinnamoh bagel Third, Glen Marciulioris, egg bagel Fourth, David Bogard, whole wheat bagel Fifth, Adrienne Karros, onion bagel
TREK
PAGE 14
Amh isn't rhe smallest plane{. but is less than half the size of
d tr
Ranus (clue 1), which is smaller than Velcron (clue 7); the only possibility is that their relative masses are 3, 7, and 1l respectively. Orl isn't lhe smallest planet (clue 3), so Ort's relative mass is 5. and by eliminarion Kudo's relative mass is l. Three consecutive planets, from innermost orbit to outermost, are Velcron, Ranus, and A[th (clue 6Xthey aren'tthe first, sccond,
)e
1-
to
V a
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and third planets (Velcron isn't hrst----clue 2), nor the third, founh, ar)d'fifth (Ranus isn't fourlh---
Third, Ranus, 7, Turtillians, ornety Fourth, Arrth, 3; Gnatites, sulle4 Fifth, Kudo, 1, Coneheads, persnickety DELL LOGIC PUZZLES February
1995
53
PYRAMIOS
PAGE 15
The two leaders in clue 7, entombed two years apart, can only have been entombed either in 279 and 281, or in 281 and 283; in either case, one was entombed in 281; this leader was Dobal (clue 2), so his pyramid was bronze (clue 7). The Grinja leader was entombed in 283 (clue 1). Dobal didn't lead the Ifendus (clue 2), Hulagos (whose pyramid wasn't bronze - {lue 4), or Kuzois (clue 5), so Dobal led the Fakiris. The pyramid used in 280 was marble (clue 6); this wasn't for Emut (clue 3), Abdul (clue 6), or Batra Roi (clue 7), so it was for Cleon. The pyramid used in 283 by the Grinjas wasn't made of silver (clue l) or ebony (clue 4), so it was gold, and thus it was for Emut (clue 3). Baba Roi was entombed in 279 (clue 7), and by elimination
Abdul was entombed in 284. The Hulagos used the'ebony pyramid, but not in 279 (clue 4), so they used it ir 284. By elimination, Baba Roi's pyramid was silver. The Kuzois' leader wasn't Baba Roi (clue 5), so this was Cleon, and by elimination Baba Roi led the lfendus. In summary: 279, Baba Roi. Ifendus. silver 280, Cleon. Kuzois, marble 281, Dobal, Fakiris, bronze 283. Emut. Crinjas. gold 284, Abdul, Hulagos, ebony
TEE UP PAGE 16 The man who scored six below par-the best of the six scores from the Rivercrest (since no one finished thrce b€low -isn't par---due l), Trophy (clue 2), Meadowbrook (clue 3), or Arlington Club (clue 4), so he's.from Springtown. The man who scored (h-ree over par-the worsl score isn't from the Rivercrest
(clue 1), Trophy (clue 2), or Meadowbrook Club (clue 3), so he's from Arlington. Baxter scored par (clue 4), the golfer from the Trophy Club scored two overpar, and Ire scored three over par (clue 2). The Rivercrest golfer and Gordon can only have scored one b€low par and twir over par respectively (clue l), so by elimination Baxter is from the Meadowbrook Club. Chappell and Young scored two over par and one below par respectively (clue 3). Fox, Marvin, and Warren can only have scored six below par, one below par, and par respeciively (clue 5). By elimination, Fox is Donald, and Lee is Ramsey. In summary: Six below par, Donald Fox, Springtown Club One below par, Marvin Young, Rivercrest Club Par, Warren Baxter, Meadowbrook Cluti Two over par, Gordon Chappell, Trophy Club Three over par, [,ee Ramsey, Arlington Club
Cave (clue 2), so they camped at the Grund Canyon, and by elimination the Badons camped at Mammoth Cave. In summary: Spring, Grimley, Massachusetts, Old Faithful Summer. Adams. Califomia, Painted Desert Fall, Banon, Vermont, Mammoth Cave Winter, Serapiglia, New Jersey, Grand Canyon PAGE.IS MICROBE TOUFISM Chroma's tour was eitherWednesday orThursday (clue 2), and so was Fossa's (clue 5), so Serrata and vermis toured on Friday and Saturday, in som€ order. Serata toured the Islet ofI:ngerhans (clue l). The Mediastinum Isthmus wasn't toured by Vermis (clue 3), so it wasn't toured Friday or Saturday. The Friday tour also wasn't of Lake Lacrimal (clue 4) or the Hyaloid Canal (clue 6), so it was of the Islet of Langerhaos, Serrata's tour. Therefore Vermis toured on Saturday. Serrata isn't the father (clue 2), mother (clue 3), or sister (clue 4), so he's the brother. Fossa's tour ivas on Wednesday (clue 5), and by elimination Chroma's was on Thursday. Vermis is the father (clue 2). The mother toured the Mediastinum Isthmus (clue 3). The sister's tour wasn'ton Wednesday (sinie in that case the Lake Lacrimal tour would have been on Thursday--clue 4-and the mother's
it was Thursday, and by elimination the mother's tour was on Wednesday. The l-ake Lacrinial tour was Saturday (clue 4), and by elimination the. tour would be impossible), so
Hyaloid Canal tour was Thursday. In summary:
.
Wednesday, Fossa, mother. Mediasrinum Isthmus Thursday, Chroma, sister, Hyaloid Canal ' Friday, Serrata, brother, Islet of Langerhans Saturday, Vermis, father, Lake I-acrimal
BUILDING BLOCKS PAGE 19 From the introduction, the four blocks contain all the letters of the alphabel except Q and X, so each of the 24 sides shows a different letter. The letters of GLIB must be on four different blocks. We'll call lhe block with G "block 1," the block with L "block 2," the block wirh t "block 3." and the block wilh B "block 4." (These numbers are arbitrary and only used to make the solution easier to follow.) The letter A doesn't appear on
block 2 (or it would be impossible to spell SLAV), block 3 (IOWA), or block 4 (BANK), so A m.ust be on block l. The letter S doesn't appeiu on block I or 2 (SLAV), or block 3 (SUFI), so S must be on block 4. Then V must be on block 3 (SLAV). The letter N doesn't appear on btock I or 4 (BANK), orblock 3 (ZINC), so N must tre on block 2. Then K is on block J (BANK). Block I can't conlain H (HARD) or O (IOWA), so it contains either M or T (MOTH), and in either case block I doesn't contain U (JUMP and'IUTE). The letter U also can't be on block 3 or 4 (SUFI), so U is on block 2. The letter
HAPPY CAMPERS
PAGE 17
The couple from New Jersey camped in winter and were the last couple to take their vacation that year (clue 3), so the couple who visited Otd Faithful in spring were the first (clue 6). The couple who visited the Painted Desert camped in summer and the couple from Vermont camped in fall (clue 1). The couple from California didn't camp in spring (clue 6), so they camped in summec and by €limination the couple from Massachusetts camped ih spring. The Adamses didn't camp at the Grand Canyon (clue 4), Mammoth Cave (clues 2 and 4), or OId Faithful 1as they aren't from Massachusetts--
54
DELL LOGIC PUZZLES Februdry 1995
4
then,
is on block 1 (SUFI). Block 2 can't contain E or T (JUTE), M (ruMP). or Z (ZINC). so it must contain eilher H or O (from MOTH) and either D or O (from DOZE): therefore if block 2 didn't contain O, it would have to contain bo& D and H, which is impossible lHARD); so block 2 must contain O. The lener W is on block 4 (IOWA.). One of the le$ers 'of HARD must appear on block 2: this can't be H (MOTH) or D (DOZE), so it must be R. We've found dree of the six letters on block 4 (8, S, and W ): a fourth must be either D or H THARD), a fifth must be either J, M, 6r P (JUMP), and a sixth must be either C or Z (ZINC); but block 4 muSt also contain a letter from JUTE,,, which now can only be J. Block 4 must also contain a lettsf from MOTH, which now.iari't be M (JUMP), so it's H. Then, block 4 must contain a letter from DOZE, which can only be Z. Bl
by ry:
18
nd
xy uls
ris
ur ral ur.
ter on
he r's la!
rs oy
ke
hi
19
of
block for which we haven't found all six letters, namely block 2. In summary: One block contains A, C, E, 4 G, and M Another block contains L, N, O, R, U, and Y A third block contains D, I, K, P, T, and V A fourth block contains B, H, J, S, W, and Z
DOMINOES PAGE 19 The 5 at e5 must be part ofthe 3-5 or 4-5 domino, and the same is true of the 5 at g7, so these two 5's belong to the 3-5 and 4-5 dominoes in some order. The 5 at g1, then, can't b€long to the 3-5 or 4-5 domino, so it's part of the 2-5 domino, which forces the 2'4 domino to its right. Now the 2 at e7 can only be pail of the l-2 domino (as we've aheady found the 2-4 elsewhere). Similarly, the 2 at h5 can only be part of the 2-3 domino. Now there is only one spot for the 2-2 and 3-3 dominoes, along the top edge. Neither of the 4's at e6 and f5 can be connected to the 4 at f6 (which would leave an area of five squares in the lower right comer which could never be evenly divided into 'domino€s), and these two 4's can't both be linked to 6's, so one or tho other must be linked to the 5 at e5. Then the 5 atgT can't be pah ofthe 4-5 domino, so it's part of the 3-5 domino, which forces the 1-4 and 4-4 dominoes to its sides. Now there is only one spot for the 3-4 (at d2-e2), forcing the 3-6 and 0-0 nearby. With these in place, there is only one 33 22 63 5
spot for each of the 1-3 and 0-4 dominoes (at e3-e4 and b3-b2), the latter forcing the 1-5 to its left and the l-l and 0-l to its righl. With these in place, there is only one spot for the
5
0-3, 1-6, and 5'5 dominoes, and this forces the locations of all the remaining dominoes. In summary:
6
34
1
5 0
0
1
26 0 0 03 2 06
2
0
2
T
0
3
6
61 65
5
4 4
6
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PAGE 20 SUNDAY BRUNCH The ctruple tttat arrived Wednesday weren't the Johnsons (clue 1), the I-opezes (clue 4), or the Mileses (clue 5), so they were the Sullivans. The couple that arrived Saturday weren't the
Johnsons (clue l) or the Mileses (clue 5), so they were the Lopezes. The l-opezes don't include Hanna and didn't stay in room 406 (clue 4). so they were visiling relalives (clue 2). The couple on vacation didn't arrive Wednesday or Thursday (clue 5), so they arived Friday. The Mileses arrived Thursday (clue 5), and by elimination the Johnsons arrived Fiiday. The Lopezes stayed in room 212 (clue 1), aild the Sullivans in room 319 (clue 5). The couple on business stayed in room 406 (clue 4), so they were the Mileses. Byelimination, the Sullivans were. on their honeymoon, and the Johnsons stayed in room 103. Emily is Ms. Miles (clue 1), so Hanna is Ms. Johnson (clue2). Colleen isn't Ms. Sullivan (clue 3), so she's Ms. Lopez, and by
elimination Maureen is Ms. Sullivan..Doug is Mr. Sullivan (clue 4). Scott isn't Mr. Miles or Mr. Lopez (clue 3), so he's Mr. Johnson. Jesse isn't Mr. Mites (clue 1), so he's Mr Lopez, and by elimination Rex is Mr. Miles. In summary: Wednesday, Doug and Maureen Sullivan,3l9, honeymoon Thursday; Rex and Emily Miles, 406, business Friday, Scott and Hanna Johnson, 103, vacation Saturday, Jesse and Colleen [,opez. 212, relatives
)o, DE
OFFICE REDECORATION
iin
The five staff iremben are Ursula, Walty, Yonkowski, the
so
P dy
funding director (clue 5), so he's volunteer coordinator. Wally isn't clinical services director (clue 3), so he's either executive director or funding director; in either case he didn't choose ivory (clues 4 and 5), nor did Yonkowski or the administrative coordinator (clue 4), so the one wlo chose ivory is Ursula. Ursula isn't executive director (clue 4) or funding director (clue 5), so she's clinical services director. Golda didn't choose deep blue or light blue (clue 3), so she chose beige. Zyp is executive director (clue l), so he's Wally, and by elimination Yonkowski is funding director. The funding director chose deep blue (clue 5), so Golda, who chose beige, is administrative coordinator. By elimination, Steve is funding director, and Wally Zyp chose light blue. Ursula isn't Palmer (clue 2), so she's Queen, and by elimination Golda is Palmer. In summary: Golda Palmer, administrative coordinator, beige Kent Ramsay, volunteer coordinatot tan Steve Yonkow'ski, funding director, deeD blue Ursula Queen, clinical services director, ivory Wally Zyp, executive director, light blue
SWEETSUCCESS
PAGE,2z
The second book is Sweer Desire (clue 6). The sixth book features Annemarie (clue J), Since Suzanne, lhen. can appear
in the fifth book at the latest, Sweet Passio, can only be the first book (clue 5). The first book is set in Portugal, its hero is Kyle, and its heroine isn't Shann4 (clue l), Janetl (clue 2), or Beatrice or Suzanne (clue 5), so she's Celeste. The secondbook isn't set in Scotland (clue 4), Wales (clues 4 and 9), Greece
;a LL B
dtector (a woman is----clue 3), executiv€ director (clue 4), or
PAGE 21
administrative coordinator, and the one who chose tan (clue 6).
'K€nt Ramsay isn't administratiye coordinator (clue 4), so of these five- he's the onc who chose tan. He isn't clinical services
(clue 5), or New York City (clue 8), so it's set in Spain. Suzanne's hero isn't Jeff (clue l1) or Damien (Suzanne isn't in Sweet Rendezvous-clue 2---or Sweet Desire or Sweet Pqssion- -{lri,e 5--ar Sweet Goodbye----clue 10-And Damien isn't in Sweet Surrender- .lue 1-ar Sweet Nothings----clues 4 and 8-so there's no book they can both be in); Jeff and Damienappearin consecutive books, set in Wales and Scotland respectively (clue 4); these can't be the third and fourth books (either the third or fourth book is set in Greece----clue 5), nor the fourth and fifth books (either th€ fourth or fifth book features Suzanne-"-clue 5), so they're the fifth and sixth books. Suzanne isn't in the fifth book (clue 11), so she's in the fourth book, the third book is set in Greece, and Beatrice is in the second book (clue 5). By elimination, the fourth book is set in New York City, so it's Sweet Nothings (clue 8). Ricardo is the hero of Sweet Surrender (cltte 7), which therefore can only be the third book. Janell is the heroine of Sw eet Rendezvous (clne 2) , which lherefore can only be the fifth book. The hero of Sweet Nothings isn't Adolfo (ctue 11), so he's Pierre. By elimination, the second book features Adolfo, the third book features Shanna and the sixft book is Swcct Coodbye.ln sumnraryi First, Sweet Passion, Kyle, Celeste, Portugal Second, Sweet Desire, Adolfo, Beatrice, Spain Third, Sweet Surrender, Ricardo, Shanna, Greece Four'th, Sv,eet Nothizgs, Piene, Suzame, New York City Fifth, Sweet Rendezyard, Jeff, Janell, Wales Sixth, Sweet Goodbye, Damien, Annemarie, Scotland BROWN.BAGGING IT
PAGE 23
The student who ilidn't eat meat loaf was a boy (clue 3), but not David (clue 5), so he was Louis. Therefore Ellen brought her lunch Monday. chicken was served Tuesday, Louis brought his lunch Wednesday, oatmeal cookies were served Thursday, and David brougl.rt his lunch Friday (clues 2 and 5). The student who didn't eat pas&i salad wasn't a girl (clue 3), so this was David. Anne brought her lunch Tuesday and fish was served Thursday (clue 1), so by elimination tacos were served Monday and Martha brought her lunch Thursday; Vanilla pudding was sewed Wednesday (clue 4), so blueberry pie was served Friday
DELL LOGIC PUZZLES February
1995
55
(clue l). Gingerbread cake wasn't served Tuesday (clue 2), so KATIE'S BUSY SCHEDULE PAGE 26 it was served Monday, and by elimination shawberry ice cream Katie has known Graves for five years (clue 3), and she sees was Tuesday. In summary; him or her one day before the piano teacher (clue 7), who is a _served Monday, Ellen, Tacos', gingerbread cake man (clue 4). The piano teacher, however, can't be Mr, Hare, Tuesday, Anne, chicken, strawberry ice cream who teaches the diy after the one who's known Katie tbree Wednesday, Louis, meat loaf, vanilla pudding years, so the piano teacher is the other male instructor (clue 6), Thursday, Martha, fish, oatmeal cookies Thus four consecutive teachers are Graves (who has known Fridav' David' pasta sarad' brueberry
pt
m;^tli,['lili];']i#i]:J.'",]? Ex::?,S'JtT,!-i:.H: 24 ir.:;; :; ""ii n", p;;;i;i;;|il t-;;..;;;s;""i, !l"Ii'g iti."r"t oi lntu;, f.rt*,if*., i il;;;;'; Sf,';; *9 ti;t;ir;J;i ;;;;;;; i, ,;;;;;;';; ffr"rii"i .i*." ;; Mariamrie and Mariamne by tl* hamisti didn't perform on Monday tclue 9), Thursdai lwhen Ariane did----clue 6), or Friday (when the jugglers did,---cl[e 6), so they WHO SHOT MTLLEN? PAGE 27 performed on Wednesday. The flautists performed on Monday The guilty woman isn't Roko lctue l), Moss (clue 4), Bridge (ctue 9). The mandolinists didn't perform on Friday (clue 4), (clue 5), or White (clue 7), so she's Fox. Angelo's wife isn't so they played on Thursday, and by elimination Friday:s pair Fox (because Angelo's wif.e has some kind oi alibi, ctue 1), were- the drummers. ln summary: nor is she Roko (clue l), Moss (clue 3), or Bridge (clue 5), so Monday, Tester and Solange, acrobats, flautists she's White. White's, alibi isn't the oil well (clu;7), so it's the Tuesday, Chester and Katrini{a, dancers, lutists country club (clue l). Roko's alitri is the oil well (clue l). Wednesday, Nester and Dionne, magicians, harpists Bridge's alibi isn't the press conference (clue 5), so it's the Thursday, Fester and Ariane, singers, mandolinists priso-n, and by eliminarion Moss's alibi is the presi conference. COURT
piano teacher can't b€ David (clue 1), so he's Ted, and Mr. Hare pAGE tN FOLDEFOL'S must be David' David Hare, then, teaches K?tie on Fridays As there are only five acts in all, the three consecutive actsln {clue 1), and he's the karate teach€r (clue 4). Katie has knowd clue 7 and the three in ctue tO musio""ii"". a, F"r,"l piano teacher_ longer_than at least two other teachers (clue dancer (clue 3), there is ou".fup,-i*. the so ;;i-,h;y she hasn't known him one or two year^s; by elimination 2.), acrs are Tester uni ttii'o*ni,"-r"t.l"r" i"o "onr""uiiue partner (the dancers), Dionne anJnei partner (ttre magiciairl snet known him four' Then she's known Susan three years her C.ollins), and the baseball coach two years (clue ind FestLr and his i6j. tne uaseball coach, then, canonly be Monday's teacher, and zt: then, wasn't on nriauy; in-r"" rut", l"r,t" ii-5o by€liTinatiorvKatie has known karate teacher David Hare one the acts in clue 8, it can onty Ue ttre one *lttr N"ri.i.k"t t""1. Katie. has_known Barbara longer than at least two other partner isn't Lesrer (clue 5j, so he;s Ctr"rt i. irn leachers (clue 5). so Barbara isn't lhe baseball coach (whom in any of rhe four conseculive ac,r *.'u. la.nrin.a: years.); Barbara is Graves, and by befoie them all 1or he'd have performed Vr"auy --.;". \3'i9 has only known-two the four consecutive acts weri on Monauv tt .o'ief, Thurrf,fl dimination the baseball coach is vicki. Since Katie has known Barbara Graves five years. she's known-wood.tou.t y.g: and Lester's act was on Friday. The her sco_ul hoop leader three years (clue 5), so they're Ted and (ctue Monday 31 or Friday i.r". Sl. ;h.y Susan Collins respectively.By elimination. Barbara Graves is the Thursday- Solange didn'l i.rforr on rin" teacher' and vicki's last name is Bach. In summary: did---
-
Fridav' Lester and Mariamne' juggrers'
TTEMS FOR
drummers
SCHOOL
plOe
ZS
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.liJi:Til'#::}Illl;,x.T,]il#iiilr*fii,13:
Di or Lit (clue.4). so ste's Gretyl. Fox, then, is Di 6), and by eliminalion Rbko is Lily.. Gretyl Moss is manied to xavier (clue 6 ). Di Fox, the. guilty. wom_an, isn't Ygss (clue
t-s.n't
a iJ"v{ -.r.,.'rj, r;;;;;; ;;i;;t";; ,.irii,"tii"i. l"ti t| ;;;.'Ji;l;. bJ;';; (clue item *u*. if," Adrienne ljil }ll:tf:=: "lly:11 it TEEOFF 8). summary: pencit case case pencil : case
Adrienne got a yellow pencit case {clue 4,1, and Joshua gor green calcularoi (clue 9 r. Adrienneli ."riirr"i"r ,"a iunchbox are lhe same co lor l clue 6). but ttrev're n or Uotfr gie'en manied to Fuzz or Quinn (clue 8). so she s married to Hatcher. Lily Roko. whose alibi was the oil well, isn't married to Quinn a;i""; i; ;;";; (clue 2),.so she's married to Fuzz, and by elimination Quinn is Adrienne's pe*ir ii y.no"*Jt"; maflleo to Lonlessa nnoge' rn-summary: they're blue, Joshua's lunchbox and Morgan's pencil case are . Moroccan prison rhe same cotor (ctue 5), but rhey're nor bo;h blul, ye ow :glf*i,l:gq:'aYinn, ul fox, nalcner' gullry I ), or green (clue 2). so lhey're rcd. Tony didn't get a red Gr€tl Moss, Xavier, press conference (clue E), so Adrienne did (clues I and'2), andit lunchbox (clue t). so ir was the no(ebook (ctue 2). - club Maybeltine white' Angelo, country didn't get a lunchbox (clue 2), so Morgan
56
DELL LOGIC PUZZLES February 1995
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elimination Eunice Parker olaved the Green Course. The last to arrive wasn't Carla Sherman (clue 1), Eunice Parker (clue 2), Anne Norton (clue 4), or Denis Thompson (clue 5), so Barry Morley was last. Eunica Parker was fourth (clue 2). Anne Norton was third (clue 4). Finally, Carla Sherman and Denis Thompson were first and second respectively (clue 1). In surnmary:
First; Carla Sherman. Red Coursc Second, Denis Thompson, White Course Third, Anne Norton, Yellow Course Fourth, Eunice Parker, Green Course Fifth, Barry Morley, Orange Course
(clue 4). The right center fielder is Camen Berra (clue 9). Joe Snider is an infielder (clue 14), so he's the shortstqp. The left center fielder isn't Ramon Clemente (clue l3), so he's Chad Maris, and by elimination Ramon Clemente is the left fielder. ln summary: First, Carmen Berra, right centdr fielder, maid of honor, escorted by Joe Snider, shortstop, best man Second, Leah Drysdale, second baseman, bridesmaid, escorted by Ramon Clemente, left fielder, groomsman Third, Yverre Mays, right fielder, bridesmaid, escorted by Dwight Ford, third baseman, groomsman Fourth, Susan Reese, first baseman, bridesmaid, escorted by Chad Maris, left center fielder,
CREDIT FOR CHFISTMAS PAGE 29 The party on the first earned Sylvia $ 150 (clue 7), and the party on the 29th eamed her $250 (clue 2). The party on the 15th eamed her more than at least two other parties (clue 3), so it didn't earn her $50 or $100; it must have earned her $200. The party that eamed her $ 100 was before at least two others (clue
6), so it wasn't on the 22nd; it was on the eighth, and by elimination the party on the 22nd was the one that eamed
Sylvia $50. Violet's party earned Sylvia at most $10O (clue 3), but Violet wasn't at the party on the 22nd (since it was before at least two others----clue 1), so she was at the. party on the eighth. Davis, then, was at the party on the first (as that one eamed Sylvia $ 150-"-clue 3). Simms was at the party on the eighth, and toys were sold on the 15th (clue 4). Cosmetics, then, were sold on the 22nd, and Hayward was at the party on the 29th (clue 1). Gretchen and Kent were at the parties on the l5th (clue oJ, amd zz,no zuro 22nd lgspecuyery 6), ano respectively (crue and by Dy elimination elrmlnauon berger Berger was at the pany on the l5th. Marissa's parly was on the 22nd (clue 5). Rose's party was on the 29th (alue ?), and by elimination the party on the first was Xenia's. s. Rose Rose Hayward didn't sell art or lingerie (clue 2), so she sold food cc containers. Violet Simms didn't sell art (clue 4), so she sold lingerie, and by elimination Xenia Davis sold art. In summary: November I, Xenia Davis, art, $150 November 8, Violet Simms, tingerie, $100 November 15, Gretchen Berger, toys, $200 November 22, Marissa Kent, cosmetics, $50 November 29, Rose Hayward, food containers, $250 THE BRIDE WORE SHINPADS PAGE 30 The three groomsmen were Ramon, Mr. Maris, and the third baseman (clue 3). Mr. Clemente wasn't the best man (clues I and 2), so he was a groomsman:'he isn't the third baseman (clue 6), so he is Ramon. Ramon Clemente escorted the second baseman (clue 2), who was therefore a bridesmaid; she isn't Ms. Mays (clue 11), so she must be Irah (clue 4)r Ms. Berra isn't second baseman t-eah (clue 2) or the first baseman (clue 7), so she wasn't a bridesmaid (clue 4); she was maid of.honor, and therefore Leah and Ramon Clemente were the Sdcond Dair
(clue 2). Joe was best man (clue 2). Chad isn't the third basem:rn (clue 6), so he's. Mr. Maris; and by elimination the third baseman is Duighr. Mr. Snider isn'( Dwight (clue 8), so he's Joe. and by eliminalion Mr. Ford (clue 15) is Dwighr. Dwight Ford wasn't part of the fourth pair (c!ue l5), so he was in the third pair. and by elimination Chad Maris was in the fourth pair Ms. Berra-who was escorted by Joe Snider-isnlt ,Susan or Yvette (clue 8), so she's Carmen. ChadMaris escorted Ms. Reese (clue 10). The right fielder is a womar, but not maid of honor Carmen Berra (clue 12), so she's a bridesmaid; we know l,eah is the second baseman, so the right fielder can only be Ms. Mays (clue 4), and therefore she can only have been escorted by Dwight Ford. Ms. Drysdale (clue l3) can only be Leah. Ms. Reese isn't Yyette (clue 5), so she's Susan, and by elimination Yvette is Mays. Susan Reese is the first baseman
sroomsmaq
YOUR STORE PAGE 31 The five customers were the first in line, the one who bought candy, Mr. Grimes, the one who spent $8 on gas, and Ms. Fugate (clue I ). The first in line didn't buy the newspaper (clue 2), soda (clue 3), or milk (clue 5), so he bought bread. Ms. Fugate didn't buy milk (clue 1) or the newspaper (a man did----clue 2), so she bought soda. The one who spent $8 on gas wasn't Mr. Jackson (who spent an odd number of dollars----clue 2) or Mr. Hebel (clue 3), so this was Mr. Lang. By elimination, the first person in line was eitherMr. Hebel or Mr. Jackson, and in either case he spent 4n'odd number of dollars (clues 2 and 3). Mr. l,ang, then, didn't buy rnilk (or olse the first in line would have spent $4 on gas-
,t r\, t
l)
il i1\r
ii
ii INTERNATIONAL PICNIC
PAGE 32
The five children are Nathan, the Schroeder boy, the oldest child, the child from India, and the child who arrived second (clue 1). Of these five, Marissa isn't the oldest (clue 2), and she didn't arrive second (clue 5), so she's fiom India- Carly Metzger is two yoars old and the ygungest (clue 4), so she's the child who arrived second. Marissa isn't Baker (clue 2) orOates (clue 5), so she's Trevino. Baker'isn't the oldest (clue 2) so hgls Nathan, and by elimination Oates is the oldest. Oates arrived after Marissa Trevino (clue 5), so he isn't from China (clue 3), and because he's the oldest he isn't from Ethiopia or Peru (clue 7), so he's from Korea. The children's ages include two (clue 4), five (clue 8), and six (clue 6), so at most or y two children can be older than six-namely the two oldest, the Oafes child from Korea being the oldest, and the child from Ethiopia being second-oldest (clue 7). Since Marissa Trevino isn'tfrom Korea DELL LOGIC PUZZLES February
1995
'!i i1;
lir
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il
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,11
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57
l: ll
li
or Ethiopia, she can't be older than six. She isn't one or two
(clue 4), three (clues 2 and 4), five (clue 8), or six (clue 6), so she's four. Nathan Baker is three (clues 2 and 4). The six- and five-year-olds must be Oates and Schroeder respectively (clue l). Kevin isn't Oates (clue 6), so he's Schrbeder, and by elimination Jared is Oates. Kevin Schroeder is from Ethiopia (clue 7). Narhan Baker isn't from China lclue 1,, so he's from Peru, and by elimination Carly Metzger is from China. Kevin Schroeder arrived fifth (clue 2), Jared Oates fourth and Marissa Trevino third (clue 5), and by elimination Nathan Baker first. rn summary: First, Nathan Baker. Peru. rhrec Second, Carly Metzger, China, two Third, Marissa Trevino, lndia, four Fourth, Jared Oates. Korea. six Fifth, Kevin Schroeder, Ethiopia, five CABIN FEVER PAGE 34 The A-frame isn't near Toivola (clue l), Point Abbaye (clue 8), or Kiva (clue l4), so it's near either Naubinway or Traunik. In either case it can't be owned by Ogden (clues 9 and l0), nor is the A-frame owned by Langdon (clue 1), Kingsden (clue 6), or Blagden (clue 8), so Glendon owru it. Thus it isn't near Naubinway (clue 2), so it's near TrauniL. lt doesn't have rhe new barbecui pit (clue 7), porch (clue 10), dock (clue 11), or sauna (clue 12), so it has the satellite dish. Blagden's property isn't near Toivola (clue 3) or Point Abbaye (ctue 8), so it's near either Kiva or Naubinway; in either case it isn't the dome (clue 9), nqr does Blagden own the log cabin (clue 3) or the houseboat (clue 13), so he owns the trailer. It isn't near Naubinway (clue 2), so it's near Kiya. The new porch isn't Kingsden's (ilue 6), bgden,s (clue i0), or Blagden's (clue 13), so it's Inngdon's. Langdon's property isn't near Toivola (clue 1) or Point Atlbaye (clue 4), so it's near Naubiriway. The dome isn't Langdon's or Ogden's (clue 9); so it's Kingsden's. It doesn't have the new sauna (clue 6) or barbecue pit (clue 7), so it has the bouit dock. It isn't near Toivola (clue 11), so it's near Point Atbaye. By elimination, Ogden's property is near Toivola. The log cabin isn't Ogden's (clue 3). so it's Langdon's, and by eliminarion Ogden owns rhe houseboat. Ogden didn't build the sauna (clue 5), so Blagden did, and by elimination Ogden built the barbecue pit. In sumrnary: Blagden, trailer, sauna, Kiva . Glendon, A,frame, satellite dish, Traunik ' Kingsden, dome, boat dock, Point Abbaye Langdon. log cabin, porch. Naubinway Ogden, houseboat, barbecue pit, Toivola CARTOON CRITTERS PAGE 35 One pair are Lu and the panot (clue 9). The parrotrs name isn't Fen (clue 6), Skimpy (clue 8), Binky (clue 9), Bomber or Jojo (clue 11), Mugsy or Red (clue 12), or Malt (clue 14), so this is Yu. Lu isn't the mouse or dog (clue 2), opossum of pig (clue 4), groundhog (clue 8), rooster (clue 9), bear or fox (clue 13), so Lu is the cat. Another pair are Binky and the rooster (clue 9). The rooster isn't Mugsy (clue 5), Fen (clue 6), Skimpy (clue 8), Bomber or Jojo (clue 11), or Malt (clue l4), so this is Red. Binky isn't the mouse or dog (clue 2), fox (clue 3), bear (clue 5), groundhog (clue 8), or opossum (clue 10), so Binky is.,the pig. Anothgr pair are Bomber and Jojo (ilue l1). Fen isn't teamed with Mugsy (clue 1) or Malt (clue 7), so Fen is teamed with Skimpy, and by elimination lhe remaining pair are Malt and Mugsy. Skimpy is the groundhog (clue 8), and the bear is either Bomber or Jojo (clue l), so the mouse and dog, who are tea4ed (clue 2), can only be Malt and Mugsy; Malt isn't the dog (clue 7), so Malt is the mouse, and Mugsy is the dog. The fox isn't Bomber (clue 3) or Fen (clue 8), so the fox is Jojo. 58
DELL LOGIC PLIZZLES February 1995
The bear, then, is Bomber (clue
l), and by elimination Fen is the opossum. In sumrnary. Binky the pig and Red the rooster Bomber the bear and Jojo the fox Fen the opossum and Skimpy the groundhog Lu lhe cal and Yu the oarroi Malt the mouse and Mugsy the dog CIRCLE
OFWOMEN
PAGE 36
The first two women to introduce themselves were Joanne
ald
Kiandra respectively, who both sat in chairs (clues l, 2, and l4). No matter which two consecutive chairs they sat in, one
sofa was occupied by either the third-fou h-fifth women or the fourth-fifth-sixth women, and the other was occuoied bv either the eighti-ninth-tenth women orthe ninth-tenth-ele;enft women; in any case, the fourth, fifth, ninth, and tenth women to speak sat on sofas. TlJe fourth and fifth women were Mabel and Nona respectively, and their last names are Blaine and Effingham in some order (clue 3). The ninth and tenth women were Ayers
and Glass respectively (clue 6). Lyn and Dobson sat,side by side on one sofa (clue 9); this wasn't the sofa that Mabel and Nona sat on (since neither can be Dobson), so it was the sofa that Ayers and Glass sat on, and Dobson was eighth oreleventh to speak. But eleventh was Stone (clue 7), so Dobson was
eighth. Lyn, then, is Ayers (clue 9). Since one sofa held the eighth-linth-tenth women, and the first and second women wgre in chabs, the other sofa can only have held the third-fourth-fifth women. Thus the fi-rst woman to speak-Joanne-sat in seat #5. The seventh woman was Townsend and the eighth was Ruth (clue 5). The four maried women (clue 14) include Kiandra (clue 2) and Stone (clue 7); Ruth Dobson and Lyn Ayers are both single (since they sat on a sofa-{lue 14), so Townsend is married
(clue 5) and Glass is single (clue 6): the remaining married woman is Ivy, who sat on a sofa (clue 14) and therefore can only be the woman in seal #?, the third to speak. Colby can only be Joanne in seat #5 (clue l0). Blaine isn't Nona in seat #9 (ctues 3 and l2), so she's Mabel, and Nona is Effingham. The woman in seat #10, sixth to speak, wasn't Fox or Volpone (ctue 4), so she was Zapata. Ivy, in seat #7 on a sofa, isn't Fox (clue 4), so she's Volpone, and by elimination Kiandra is Fox. There are now four women whose first names we haven't identified: Zapata in seaa #10, Townsend in #11, Gtass in #3, and Stone in #4; they are Heidi, Olivia, Patti, and Qula in some order. Of these four, Zapata, Townsend, and Stone sat in chain, while Glass sat dn a sofa, so neither Olivia nor Patti can be Glass (clue l3). Zapatais single, so Heidi must be married (clue I l): therefore Class. who is single, can't be Heidi either; so Glass can only by Qula. Qula Glass is single, so Olivia must also be married (clue 8). Thus Zapara. who is single, can't be either Heidi or Otivia. who are marriat Zapata can only be Patti. Olivia isn't Townsend (who sat nexl ro Patri Zapara* clue l3;, Olivia is Stone, and Heidi is To'*,rxend. In summary: First. #5 tchair). Joanne Colby Second, #6 (chair), Kiandra Fox (married) Third, #7 (sofa), Ivy Voipone (married) Fourth, #8 (sofa), Mabel Blaine Fifth, #9 (sofa), Nona Effingham Sixth, #10 (chair), Pati Zapata Seventlr, fl [ (chair). Heidi Townsend lmarried.l Eighth, #1 (sofa), Ruth Dobson . Ninth, #2 (sofa). Lyn Ayers Tenth. #3 (sofa). Qula Glass Eleventh, #4 (chair), Olivia Stone (married)
so
FEPLACEMENT WEEK
?.
PAGE 37
The graphics monitor was bought before Lawrence's item, which was bought before Jipescu's item (clue 2), which was
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lhe
bought the day before the modem (clue 6). The graphics monitog the[, was bought Monday or Tuesday. Selena didn't shop on the day the graphics monitor was bought, northe day after (clue 9), nor the day before (clue 5), so she can't have shopped Monday or Tuesday. Thus she shopped Wednesday or Thursday, and the disk drive was bought Thursday or Friday (clue 5). The modem was also bought Thursday or Friday (clues 2 and 6), so Thursday's and Friday's items were the disk drive and modem in some order Thursday's purchase, then, was made by Eng
(clue 1). Jipescu's purchasecanonly have been made Wednesday, l,awrence's was made Tuesday, the graphics monitor was bought Monday, and the modem was bought Thursday (clues 2 and 6); the disk drive, then, was boughf Friday, and Selena is Eng (clues 5 and 9). The keyboard was T[esday's purchase (clue 3), and by elimination the printer was Wednesday's. Pascayo can't be Monday's or Friday's purchaser (clue 4), so Pascayo shopped on Tuesday. Thomton shopped on Friday (clue 7), and by elimination Knowles shopped on Monday. Knowles is Zeke (clue 8), so Glenda is Jipescu (clue 4), and by elimination Albeno is Thornton. ln summary: Monday, Zeke Knowles, graphics monitor Tuesday, Lawrence Pascayo, keyboard Wednesday, Glenda Jipescu, printer Thursday, Selena Eng, modem Friday, Alberto Thomton, disk drive
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PAGE 38 WITHOUT A CLUE Each player held exactly three cards (introduction). Clive didn't
hold the lead pipe (clue 2) or the hall (clue 6), so he held Scarlett (clue 5); he didn't hold Green (clue 2) or the lounge (clue 1l), so he held the candlestick (clue i). Esmeralda didn't hold the rope (clue 12), so she held the conservatory (clue 8). Clive didn't hold the knife (clue 6), so his third card was White (clue 16), and he held no other ca.rds but these. One of Arbuckle's cards was either Peacock or the dining room (clue 3); another was eithii Mustard, the wrench, or the study (clue 7); and a third was either Green, the lead pipe, or the kitchen (clue 9); he had no other cards but these, so he must have had the dining room (clue 14). If Arbuckle didn't havE the wrench, he would have had both the kitchen (clue 4) andCreen (clue 13), and his three cards would be Green, the dining room, and the kitchen, which is impossible (he must also have had one card from clue 7): so Arbuckle had the wrench. Thus two ofhis cards were the wrench and the dining room, and the third was either Green, the lead pipe, or the kitchen (clue 9). One of Babette's cards was either Mustard or the billiard room (clue 10); another was either Plum, the rope, or the study (clue 12); and a third was either the revolver or the balhoom (clue 15); so she had no other cards but tirese. Peacock wasn't held by Florian (clue 3), Dahlia, or Esmeralda (clue 6); since.no one had Peacock, this card represented the murderer. Green wasn't hetd by Dahlia (clue 2), Esmeralda, or Florian (clue l3), and Green wasn:t the murderer (Peacock was), so Green was Arbuckle's third card. Nbither Mustard nor Plum was held by Dahlia, Esmeralda, or Florian (clues 7 and l2), so Babette must have held both cards, and her third card was eithe,r the revolver or the ballroom (clue 15), The rope wasn't held by Dahlia, Esmeralda, or Florian (clue 12), so no one held it, and it was the murder weapon. The leadpipe wasn't held by Dahlia (clue 2) or Florian (clue 9), and it wasn'tthe murder weapon (the rope was), so Esmeralda must have held it. The knife wasn't held by Dahlia or Esmeralda (ctue 6), so Florian must have held it. We knqw Dahlia held no suspects, so she must haye held at least one weapon (or she would have held three rooms, which is impossible-'--clue 17)l therefore Dahlia held the revolver, the only weapon unaccounted for. Babette, then, held the ballroom (clue l5). Th€ study wasn't held by Dahlia, Esmeralda, or Florian (clue 7), so no one held
it, and it was the scene ofthecrime. The lounge wasn'theldby Esmeralda or Florian (clue 13), and it wasn't the scene of the crime (the study was), so Dahlia must have held it. Neither Dahlia nor Esmeralda held the hall (clue 6), so Florian held it. Neither Dahlia nor Florian held fte library (clue 2), so Esmeralda held it, and we know all thee ofhercards. Florian didn't hold the kitchen (clue 9), so Dahlia held it, accounting for all three of her cards. By elimination, Florian's third card was the
billiard room. In summary: Arbuckle: Mr. Green, wrench, dining room Babette; Colonel Mustard, Professor Plum, ballroom Ctive: Miss Scarlett, Mrs. White, candlestick Dahlia: revolver, kitchen, lounge Esmeralda: lead pipe, conservatory, library Florian: knife, billiard room, hall The murder was committed by Mrs. Peacock with the rope in the study.
PAGE 39 BATTER UP! Ian bats seventh (clue 9), so men bat first, third, fifth, seventh, and ninth, and women bat second, fourth, sixth, eighth, and
l). The pitcher bats third (clue 8). Two of the outfielders are th€ man who bats fifth and lan (clue 3)' The tenth (clue
other two outflelders are Ebony and Mr. Lopez (clue 3); Ebony can only bat second or tenth (or else she'd be bonsecutive with another outfielder----clue 3), so Mr Lnpez can't bat ffust (or he'd be consecutive with Ebony in either case----clue 3); Mr Lopez can only bat ninth. Ebony, then, can't bat tenth (orshe'd be consecutive with Mr. I-opez (clue 3)), so she bats second. Ms. Mincus plays infield, but she doesn't bat fourth (clue 5) or tenth (clue 4),.io she bats sixth or eighth; in either case Jack can only bat ninth, and Chloe bats tenth (clue 4). Mr. Ong, Anna, and Gus cah only bat third, fourth, and fifth respectiYely
(clue 7). Frank doesn't bat third (or Anna would be Gus's
wife----clue 6 - which she can't b€----{lue 2.1, so FranJ< bats first. and by elimination Hal bats third and is M-r. Ong. Ms. Ong bats eighth (clue 9), so Ms. Mincus (whom we already krow must bai sixth or eighth----clues 4 and 5) bats sixth. Diana isn't Ms. Mincus (clue 5), so she can only bat eighth, and by elimiuation Barb bats sixth and is Ms. Mincub. Three of the four infielders are
Diana Ong, Barb Mincus, and Anna; the fourth is Barb Mincus's husband (clue 5), who can only be Frank (as we know the positions of the other four men), so Frank is Mr Mincus.
By;limination, Chloe is the catcher. Gus and Ebony are
mafiied, but their last name isn't Krebs (clue 6), so it can only be Nye. Ms. lopez isn't Chloe (clue 2), so she's Anna. By elimination, the Krebses are Ian and Chloe. In summary: First. Frank Mincus. infielder Second. Ebony Nye. outfielder Third, Hal Ong, pitcher Fourth, Anna lrpez, infielder Fifth; Gus Nye, outfielder Sixth, Barb Mincus, infielder Seventh, Ian Krebs, outfielder Eighth, Diana Ong. infielder Ninth, Jack Lopez. outfielder Tenth, Chloe Krebs, catcher
THE
UNFORGOTTEN
PAGE 40
Thursday's and Friday's villains don't include Billy Bonnet (clue 2);John Hardly Westem (clue 7), or Wyatt Urp (clu€ 9), so they are Moondance Cassidy and Doc Easter in some order. In either case, Friday's villain can't be nicknamed 'Snake" (clue 8), nor is he "Full House" (clue 6), "Two Bits" (clue 7); DELL LOGIC PUZZLES Februarv
1995
59
i
or "Widowmaker" (clue 9), so he's "Deadeye." "Deadeye" isn't Doc Easter (clue 4), so he's Moondance Cassidy, and Doc Ea5ter is Thusday's villain. Monday's villain isn't "Full House" (clue 6), "Two Bits" (clue 7), or "Widowmaker" (clue 9), so he's "Snake." The El Peso villain isn't "Two Bits" (clue 1), "Deadeye" Moondance Cassidy (orelse "Widowmaker" would be Doc Easter---clue 9-which is impossible-clue 4). "Snake" (since the El Peso showdown isn't Mondav's--clue 9), or "Widowmaker" (clue 9); so fie El Peso villainis "Full House." "Widowmaker" isn't Doc Easter (clue 4), Joh-tr Hardly Westem (or else the El Peso villain would be "Two Bits----{lues 7 and 9-which we know is not the case), or Wyatt Urp (cluo 9), so "Widowmaker" is Bitly BonneL Thre€ consecutive showdowns, then, a-re the one with Wyatt Urp, the ond with "Widowmaker" Billy Bonnet, and the one with "Full House" in E[ Peso, in that order (clue 9); but these thee can't b€ on Tuesday-WednesdayThusday (if the showdown with Billy Bonnet were on Wednesday and the Et Peso showdown on Thursdan clue 2 would be impossitrle), so these can only be on Monday-TuesdayWednesday. By elimination, "Two tsits" is Thursday's villain, and John Hardty Westem is Wednesday's. The Crumpet Creek
showdown is Thursday's (clue 2). The Booty Hill showdown isn't Monday's (clue 3) or Friday's (clue 5), so it's Tuesday's. The Silver Town showdown isn't Monday's (clue 10), so it's Friday's, and by elimination the Monday showdown is in Dog City. In summary: Monday, "Snake" Wyatt Urp, Dog City Tuesday, "Widowmaker" Billy Bonnet, Booty Hill Wednesday, "Full House" John Hardly Westem, El Peso Thursday, "Two Bits" Doc Easter, Crumpet Creek Friday, "Deadeye" Moondance Cassidy, Silver Town DINNER PARTY Mr. and Mrs. Elkind sat in seats 6 and
'
PAGE 41
I respectively (clue l). The cellist isn't Mis. Elkind (clues I and 13), Mrs. Zigmond (whether she is the tax attorney or Richard's wife, she can'tbe the cellist---+lues 2, 9, and 13), Mrs. Fischer or Mrs. Glass (clue l2), or Mrs. Marquez (clues 2 and l3), so the cellist must be a man. Thus one side of the table included at least three men (clue l3): this can't be the north side (at leasr two women. the bcttanist and Mrs. Zigmond, sat on the north side---clues 4 and l2), so it's the south side. The botanist and Mrs. Zigmond oo the north side ofthe table each satnext to at leastone man (clue 4)i since at most one man sat on the north side, one of these lwo men musr have been Mr Elkind in seat 6; thus a man sat in seat 3, Mrs. Zigrdond sat in seat 4, and the female botanist (clue 12) sat in seat 5 (clue 4). By elimination, a woman sat in seat 2, and seats 7 thfough 10 contained three men and a woman in some order. The woman on the south side didn't sit in seat 9 (or no two men would have sat across from each other, which is impossible---clue 8), so she must have sat in seat 8, and Mr. Glass and Mr. Zigmond sat in seats 7 and 9 in some order (clue 7); by elimination a man sat in seat 10. The man in seat 9 (either Mr. Glass or Mr. Zigmond----clue 7) must be Dave, and the man in seat 3 is Mr. Fischer (ctue 8). Mrs. Fischer, then, sat on thq
south side (clue 2), so she was the woman in seat 8. Mrs. Fischer isn't the botanist (who was in seat 5), so Mrs. Fischer is the aerobics instructor, and the botanist is Mrs. Glass (clue 12). By elimination, the man in seat 10 and the woman in seat 2 are Ihe Marquezes. Judith, then. is Mrs. Elkind. and Mr Marquez is the private de(ec(ive (clue 6). Richard is the man in seat 7. and lhen the cellist can only be Dave in seat 9 lclue l3). Now Nancy, Quentin, and ltre sociology professor can only be the ones in seats 5, 6, and 7 respectively (clue I l). Yetta and the jeweler can only be the onos in seats 8 and 4 respectively (clue 3). The hardware store owner, Ursula, and the irptometrist sat in seats l,2, and 6 respectively (clue 10). By elimination,
6
DELL LOGIC PUZZLES February 1995
Olga was in seat 4, so William wasn't in seat 3 (clue 5); William, then, was in seat 10, and by elimination Irwin was in seat 3. The video producer is Ursula Marquez (clue 3), so by elimination Irwin Fischer is the tax attomey. Olga Zigmond is Richard's wife (clue 9), so Richard is, Zigmond, and by elimination Dave is Glass. Insummary: Seat 1. Judith Elkind, hardware store owner Seat 2, Unula Marquez, video producer Seat 3, Irwin Fischer, tax attomey Seat 4, Olga Zigmond. jeweler Seat 5, Nancy Glass, botanist Seat 6, Quentin Elkind, optometrist Seat 7, Richard Zigmond, sociology professor Seat 8. Yetta Fischer. aerobics instructor Seat 9, Dave Glass, cellist Seat 10, William Maiquez, private detective. YOU MUST HAVE BEEN A BEAUTIFUL BABY PAGE 42 There are three consecutive photos mentioned in clue 1, and another three mentioned in clue 2; either these two groups are entilely separate, or they overlap. If they don't overlap, then one group appeared Monday through Wednesday and the other group appeared Thursday through Saturday. Ifthe three in clue I appeared Monday lhrough Wednesday, then Cliflon's pholo would have appeared Wednesday (clue 1) and the mayor's on Thursday (clue 2); Clifton wouldn't be the police chief (clue 4) and wasn't shown on a blanket (clue 3), so clue 9 woqld be impossible. If the th-ree in clue 2 appeared Monday through Wednesday, then Gregory's photo would have appeared Wednesday
(ctue 2) and the fire chief's on Thursday (clue 1); Gregory wouldn't be the police chief (clue 4) and the fire chief isn't Jessica (clue 1l ), so again clue 9 would be impossible. Therefore the two groups in clues I and 2 must overlap. Gregory isn't the
child posed in the bathtub (clue 5), and the mayor is neithei Clifton nor the child in the bathtub (clue 10) so the only way the two groups in clues 1 ar.d 2 car. overlap is if on five consecutive days photos appeared of the mayor, the child on the rocking horse, fiie chief Gregory, the child in the bathtub, and Clifton. The child on the rocking horse isn't Jessica (clue 11), and Clifton wasn't posed on th€ blanket (clue 3), so the only way the three photos mentioned in clue 9 can overlap th€se fiye is if the child on the rocking horse is the police chief, Gregory was posed on tlrc blanket, and the ctlild in the trathtub is Jessica. These five photos didn't app€ar Tuesday tfuough Sanfday (since the police chief's didn't app€ar on Wednesday---clue 4), so they appeared Monday thiough Friday. Cherise isn't the mayor and didn't appear on the rocking horse (clue 8), so she didn't appear Monday or Tuesday; she appeared Saturday. Deborah isn't the police chief (clue 4), so she appeared Monday, and by elimiiration Mitchell appeared Tuesday.'The doctor is Cherise (elue 7). The writer isn't Jessica (clue 11), so this is Clifton, and by elimination Jessica is the school superintendent. The child on the tricycle was Clifton (clue 6), and the child on the
rug isn't Cherise (clue 8) but Deborah, so by elimination Cherise posed in the wading pool. In stmmary: Monday. Deborah. rug, mayor Tuesday, Mitchell, rocking horse, police chief Wednesday' Gregory, blanket, fire chief Thursday, Jessica, bathtub, school superintendent Friday, Clifton, tricycle, writer Saturday, Cherise, wading pool, doctor
..: z|
PAGE 43 DEAB JOHN The two women whose first initials matched their boyfri€ndi' last initials (clue 4) can't include Alicia and Barb (since no man's last name begins with A or B), or Jessica (her relationship
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was the shortest---{lue 5-so it wasn't with John Johnsonl---or John Jones---{lue 7), so they were Julie and Winona, Winona's boyfriend, then, was John Williams. Julie's wasn't John Johnson (clue 2), so he was John Jones. Jessica's boyfriend wasn't John Johnson (clues I and 5) or John Roberts (clues 5 and 8), so he was John Smith. Alicia's wasn't John Johnson (clue l), so he was John Robens, and John Johnson was Barb's boyfriend. The relationship that lasted three months tclue a) wasnl Alicia's wirh John Robens or Barb's with John Johnson (clue 1), Julie's with John Jones (clue 7), or Winona's with John Williams (clues 2 and 7), as all four of these romances lasted evennumbers ofmonths: so the tfuee-month relationshiD was Jessica's. lrr r equal lhe length in monrhs of the romalci of the woman who claimed to be taking religious vows, and p equal the lengrh in months of the romance of the woman whb claimed to have taken a psychic's advice. ThenJulie's romance with John Jones lasted 2r" months (clue 7) and Winona's with John Williams lasted 6r months (clue 2); Alicia's with John Roberts lasted 2p months, and Barb's with John Jdhnson lasted 4p months (clue l). If lhe woman taking a psychic's advice were Jessica. then Alicia's and Barb's romances woJld have lasted six alld 12 months respectively; the 24-month romance (clue 5) could only be Winona's, and Julie's would have lasted €ight months; but then the value of r would be four, and yet none of the five romances would have lasted four months:-so this is impossible. lf the woman la-k ing a psychic's advice were Winona, thenp would equal 6r, so Barb's romance would have lasted 24r months; thert / would have to equal one (or Barb's romance would have lasted more than 24 months--clue 5), which is impossible (since we know the shonest romance was three months long). So the woman taking a psychic's advice can.only be Jdlie, and therefore p equals 2r. So Alicia's and Barb's romances lasted 4r and 8r months respectively; and by elimination the woman who claimed to be taking religious vows can only be Jessica. Thus Julie's, Alicia's,- Winona's, and Barb's romances lasted six, 12, 18, and 24 months respectively. The woman citing her boyfriend's obsession with baseball was Barb (clue 3), and the woman claiming to have found someon€ new wasn't Alicia (ilue 6), so she was Winona. By elimimtion, Alicia claimed an objection to long-distance romances. In summary: Alicia, John Roberts, long-distance romance,.l2 months Barti, John Johnson, obsession with baseball, 24 months Jessicb, John Smith, religious vows, three months Julie, John Jones, psychic's advice, six months Winona, John Williams, nbw boyfriend, 18 months c_lue
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MINOR LEAGUE PAGE 45 The Giants farm team finished second, and New Cha-rtres, tle Sha*s, and the Meteors finished hrst, third, and fourth in some
order (clue l). Winterglen didn't finish first, third, or fourth (clues 1 and 9), and neither did the Admirals (ctues I and I l), so the Adminls, Winterglen, and the Orioles farm team finished either fifth:sixth-seventh or sixth-seventh-eighth (clue 5). The Summerset Suns ilidn't finish first, third, or fourth (clues 1 and 8), and neither did the Mountaineers (clues 1 and 11), so the Surnmerset Suns, the Pirates farm team, aqd the Mountaineers fi nished either fi fth-sixth-seventh or sixth-seventh-eighth (clue
/$ di' no hip
8). The only way the two groups in clues 5 and 8 can overlap, then, is that the Summerset Suns finished fifth; the Admirals, which is the Pirates farm team, finished sixth; the Winterglen Mountaineers fiirished seventh; and the Orioles farn team finish€d eighth. The Dukes didn'r finish second or lasr (clue 7), so rhey {inished first, rhird. or fourth, and in any case they must be the New Chartros team (clue l). The Waves didn't finish last (clue 4), and they didn't finish first, third, or fourth (those three teams
were the Dukes, Meteors, and Sharks in some order---
Fifth, Summerset Suns, Texas Rangers Sixth, Gravesend Admirals, Pittsburgh Pirates Seventh, Winterglen Mountaineers, Colorado Rockies Eighth, St. Bamaby Parrots, Baltimore Orioles
ALBASABODES
1
PAGE 46
The five houses were purchased in five consecutive months during the same calendar year (introduction). A five-bedroom house was.purchased in March (clue 9), and the Ifknalises bought a house in April (clue 4)" so the fiye months were either January-February-March-April-May, February-March-AprilMay-June, or March-April-May-June-July. The March house wasn't bought by the Quinns (clue 3) or the Zubins (who didn't buy a five-bedroom house----clue 6). Ifthe W€yricks hadbought the March house. then the Quinns would have boughl lheir house in February lclue 31: the Yardleys couldn't have bought their house after the Quinns-Weyricks-IJknalises (or they'd be
the fourth or fifth to buy, which is impossible--,+lue 7), so they'd have bought theirs in January; and by elimination the May house would be the Zubins'; but this is impossible (since the March house had five bedrooms, not four----clue 6), so the March house wasn't bought by the Weyricks; it can only have been bought by the Yardleys. Thp Uknalises'house is the Victorian, and the May house was in Oak Creek (clue 7). The Quinns didn't buy in February (clue 3), and neither did the
Weyricks (or else the Quinns would have bought theirs in January-clue 3-and the Zubins could then have only bought theirs in May, but as the March house had five bedrooms, not four, this is impossible ---clue 6). Ifthe Zdbins had boughtthoir house in February, then the Quinns and Weyricks could only have.bought in May and June respectively (clue 3); the Weydcks would have bought in Palmer Village (clue 3); the Zubins and Uknalises would have both bought four-bedroom houses (clue 6); and the Kentfield house would have six bedrooms (clue 4), which would be impossible {by elimination the Kentfield house
could only be one of the four- or five-bedroom houses). So tie five couples can have bought a house in February and therefore the houses were bought in March,April-MayJune-July. The Yardleys bought the colonial (clue 2). The Quinns and Weyricks boughr in csnsecutive months (clue 3). either May-June or June-July, so by elimination the Zubins boughl in either May or July; in either case the May and July houses both have four bedrooms (clue 6). The Uknalises didn't none of
buy in Palmer \4llage (clue 3), Kentfield (clge 4), or Lanh4mton
(clue 5), so they bought in New Durham. The Yardleys didn't buy in Patmer Village (clue 3) or t anhamton (clue 5), so they bought in Kentfield. The flknalises' house, then, has three DELL LOGIC PUZZLES Februarl
1995 6l
I
?
i
bedrooms (clue 4). Some house has six bedrooms (clue 1); this can only be the June house. The art nouveau house can't have four bedrooms (since no house has two {lue 8), so it can only . be the June house. The Georgian isn't the July house (clue 5), so it's the May house, and by elimination the July house is the Bauhaus. The Quinns and Weyricks, then, bought in May and June respectively, and the Weyricks bought in Palmer Village (clue 3). By etimination the Zubins bought a house in Lanhamton
in July. In summary: March, the Yardleys, colonial, Kentheld, five bedrooms April, the Uknalises, Victorian, New Durham, three bedrooms
May, the Quinns, Georgian, Oak Creek, four bedrooms June, the Weyricks, art nouveau, Palmer Village, six bedrooms July, the Zubins, Bauhaus, Lanhamton, four bedrooms
the same floor, first in a room with amber and next in the burgundy and ivory room (clue l3); the only possibility is that Dorabella moved from room l4 (containing amber) to room l1 (the burgundy and ivory room) between Friday and Saturday nights: Bamaby. then. slept in room 7 on Saturday. Thg five rooms on the eround floor musl contain all len coiors bet{veen them (clue 3), so one contains gold; this can't be 13 or 14 (clue 3 ), so it's 12. S imilarly, one of the ground floor rooms contains turquoise; this can't be 12 (clue 2) or 13 (clue 3), so it's room 14. One of the ground floor rooms contains crimson; this can't be 12 (clue 2), so it's 13. By elimination, the other colors in rooms 12 and 13 arejet and silver in some order There is ajet and silver room, which can't be 3 or 10 (which Bamaby visited-{lue 7), nor any room in the same column as either room 12 or l3 (which containjet and silver in some order----clue 3);thejetand silverroom can only be room 9. Dorabella visited room 9 on Tuesday (clue 7), and Bamaby's Tuesday room was by eliminati6n room 5. The third room containing turquoise (besides rooms 8 and 14) can only be room 4 (clue 3). If room
13 contained silver, then the third room containing silver
PAGE 47 BEDROOM FARCE Between them, Barnaby and Dorabella stayed in all but one of the 15 rooms (introduction). From each night to the next, the sum of their room numbers increased (clug 5). The sum of all 15 room numbers is 120, and the sum of the 14 room numbers Bamaby dnd Dorabella visited is between 105 and 119 (120 minus Ralph's room number, which may be anywhere from 1 to l5). If Monday's sum were 15 or more, the lowest Possible sum of all seven days' totals would be 15 + 16 + 17 + 18 + 19 +20 + 21= 126, which is impossible. If Sunday's sumwere 17 or less, the greatest possible sum of all seven days' totals would be 11 + 12 + 13 + 14 + 15 + 16 + 1'7 = 98, which is also impossible. So Monday's sum was 14 or less; and Sunday's sum was 18 or more. Therefore Bamaby's Monday room number was at most 13, and Dorabella's Sunday room number was at least 3. Bamaby's Monday and Dorabella's Sunday numbers, then, must be 12 and 4, or 9 and 3, respectively (clue 15)' If the latter, then Sunday's total couldn't be greater than 18 (if Barnaby had room 15 that day), so that the greatest possible total for the
(besides rooms 9 and 13) could only be room 4 (clue 3), which is impossible (clue l1); so room 12 contains silver and room 13 contains jet. Then the third room containing jet (besides rooms 9 and 13) can only be room 4 (clue 3). The third room containing crimson (besides rooms 6 and 13) can't be l0 (since room 6 contains crimson --clue 4), sq it can only b€ 7 (clue 3).
Rooms l, 2, and 5 must contain amber, burgundy, emerald, ivory, peach, and silver in some order (clue 3). Silver can't be in room I or 5 (as rooms 12 and 9 both contain silver-'-clue 4), so silver is in room 2. Peach must be in room I (we know the colors of all of Dorabellars other rooms, and peach isn't amolg them---{lue 8). Emeratd isn't in room 1 (room 15 is emerald and peach----clue 2) or 5 (clue 14), so it's in room 2. The third
room containing emerald (besides roomp 2 and 15) can only be 7 (clue 3). Then the third roon containing peach (besides rooms 1 and 1J) can only be 3 (clue 3). All the colors have been used three times now but amber, burgundy, and ivory, and neither room 5 nor room 10 can contain both burgundy and ivory (as that's room 1l's color scheme----clue 2), so rooms 5 ' weekwould be 12 + 13 + 14 + 15 + 16 + 17 + 18 = 105-bitt and 10 are, in some order, the amber and burgundy room and the amber and ivory room; the three rooms containing amber as Bamaby would have used room 15, Ralphts room number could be at the most 14, matring the maximum total ofthe 15 room are thus 5, 10, and 14. If room 5 contained amber and iYory, then numbers only 119-an impossibility. So Bamaby slept in room . room I would contain burgundy and peach (clue 3), and room 12 on Monday, and Dorabella in room 4 on Sunday. Thus 3's other color ftelides.peach) couldn't be either burgundy Monday's total is at least 13, and Sunday's total is at most (clue 2) or ivory (as Barnaby stayed in roorhs 3 and 5 lg-and then the only possible totals for the seven days are both-"-clue 9), which is impossible. So room 5 contains amber 13-14-15-16-17-18-19. Since these seven totals add up to and burgundy, and room 10 contains amber and ivory. Room 1 containi ivory and peach (clue 3). By elimination, room 3's 1.12, Ralph's bedroom must be ropm 8. Dorabella must have in room on Sundayr Bamaby 15 1 on Monday, and other color is burgundy. In summary: slept in room Ropm 1, ivory and peach Room 9,jet.and silver Room 7 wasn't oicupied on Tuesday thmugh Friday (or that Robm 2, emerald and silver Room 10, amber3nd ivory day's total would be between 14 and 17, making the other room would on the two looms be and 10, and the between 7 Room 3, burgundy and peach Room 11, burgundy and ivory number Room 4,je( and lurquoise Room 12. gold and silver same floor, which is impossibte---clue 4), so room 7 was Room 5, amber and burgundy Room 13, crimson andjet occupied on Saturday, and the other room occupied that day Room 6, crimson and gold Room 14, amber and turquoise was room 11. Then the only possible pair of rooms for Friday, Room 7, crimson and emerald Room 15, emerald andpeach with a total of l?, is room 3 and room 14; Bamaby had room Room 8. gold and turquoisc 3 and Dorabella had room 14 (clue l2). The only possible pair of rooms for Thursday' with a total of 16, is room 6 and room Ralph's bedroom was room 8. 10. The only possible pairofrooms for Wednesday, with a total
15, is room 2 and room 13; Barnaby had room 2 and Dorabella had room 13 (clue 12). By elimination, Bamaby and Dorabella had rooms 5 and 9 in some order on Tuesday. Room 8 was gold and turquoise (clue 6). Dorabella stayed in the crimson and gold room between Monday and Thursday (clue l0); the crimson and gold room can't be room l, 5, 9, 10, or 13 (clue 3), so it can only be room 6. Thus Dorab€lla had room 6 on Thursday. and Bamaby had room 10. Room l5 was emerald and peach (clue l0). Someone slept two consecutive nights on
of
62
DELLLOGIC PUZZLES Fehruary
1995
Bamaby slept in b€drooms 12 5-2-10 3-7-15 Dorabella slept in bedrooms l-9-13-6-14-11 4
i PAGE 48 TTLLTHE FAT LADrf STNGS Four ofthe.five menare Wolf (clue 10), Zaines (clue 12), and two ofBradley, Fitzpatrick, and Kleiner (clue l1). Edward had three lessons in all, two.of them on the lst and 29th (clue 8)' so Edward can't be Wolf (clue 10), Zaines (clue 12), or elther of the two men among Bradley, Fiupahick, and Kleiner (clue
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I l), so Edward is the fifth man. Ventura can't be Edward (clue 4), so Ventura is a woman; she isn't Deena (Ventura had one Wednesday lesson----{lue 4-and Deena had none --clue 9) or Lillian (Ventura had three lessons----clue 4-and Liltian had two----{lue 5), so Ventura is Jill. Jill Ventura and Bradley had the lessons on the 8th and 22nd in some order (clue 7). Kleiner and Lillian, then, had lessons on two of the following four possiblepain ofdates:4th-8fi, l lth-l5th, 15th- l9th, and 18th-22nd (clue 5); the two pairs of dates can't include both I lth- l5th and l5th-l9th (or both Kleiner and Lillian would have had lessons
PAGE 43
EXTRA CLUE FOR DEAR JOHN
No romance lasted gxactly four or five months. PAGE 47 EXTRA CLUE FOR BEDROOM FARCE Ralph's bedroom was room 8. Monday's two rooms were 1 and 12 in some order; Tuesday's were 5 and 9; Wednesday's were 2 and 13; Thursday's wele 6 and 10; Friday's were 3 and 14; Saturday's were 7 and I l; Sunday's were 4 and 15.
on the 15th), so they include at least one of 4th-8th and 18th-22nd; and in any case, Lillian had at least one lesson on either the 8th or the 22ntl; so Lillian must be Bradley (clue 7). Fitzpatrick and Kleiner, then, are men (clue 1l). Deena isn't Grauer (clue 9), so Deena car only be Stuart, and by elimination Edward is Grauer. Kleiner isn't Adam (clues 3 and 5) or Matt (clues 5 and 6), and Zaines isn't Adam (clue 12) or Matt (clues 6 and 12), so Kleiner and Zaines are Harold and Xavier in some order, and Wolf and Fitzpatrick are Adam and Matt in some order. Wolf, then, had at least three lessons (Matt had three---clue 6-and Adam at least four----clue 3). Jill Ventura, then, can't havs had a lesson on the 22nd (or there wouldn't be enough lesson days for Wolf's lessons 'clue l0), so she had the lesson on the 8th, and Lillian Bradley had the lesson on the 22nd (clue ?). Kleiner, then, had a lesson on the 18th (clue 5). The other Kleiner-Bradley pair of lessons can't be l5th-l9lh (since we know Kleiner is a man and didn't have a lesson on any of the first three Wednesdays---{lue I l), so il can only be 11lh-l5th. Zaines had lessons on the 4th and 5th (clue 12). Since two of Edward Grauer's three lessons (clue 8) were on Wednesdays, Deena Stuart can only have taken one lesson during the month, and it was on the same day as Edward Grauer's remaining lesson (clue 9). If Jill Ventura's tfuee
8th, l1th, and l2th (clue 4), then Wolf couldn't be Matt (clues 6 and l0), so Wolf would be Adam; Adam Wolf would haye had at least four lessons (clue 3), which could only be on tlie l8th, 19th, 25th, and 26th (clue 10); but then there would be no day on which the Signora's two pupils could be Deena Stuart and Edward Grauer (clue 9). So Jill Ventura's lessons were either on the 4th, 5th, and Sth, or else the 5th,8th, and llth; in either case, she had. a lesson on the 5th. Matt's three Sunday lessons, then, were oir the 12th, 19th, and 26th (since we already krow he isn'l Zaines-clue 6). Now
oett crossword lnnual Wnter ..........................o""e;;"",:ti Official Word Search Puzzles February.............December 1 Solver's Choice Crosswords Winter...........,.....Decembel 6 100 Easy Crosswords January .......... .... .........'December 6 Dell Champion Variety Puzzles February........'-December 6 Dell Crosswords & Variety Puzzles January.....December I Dell word Search Puzzles January....................December 13 Dell Crosswords Closswords #11...................'.December 15 Officiat Grossword Puzzles February................December 15 Dell Pencil Puzzles & Word Games March -.....;December '15 'l5 Dell Variety Puzzle Spectacular #26 .................December Dell Crossword Puzzles February ..........'..........December 20 Pocket Crossword Puzzles February '...'.......... December 20 Dell Pencil Puzzles & Word Games Yearbook
Win1er....................
lessons wcre on the
the day on which the two pupils were Deena Stuart and Edward
Grauer (clue 9) can only be the 25th. Xavier had a lesson on the 26th (clue 2). Xavier, then, can'f be Kleiner (whose only two lessons we know were on the 1lth and 18th), so Xavier is Zaines, and Kleiner is Harold. Adam had at least four lessons (clue 3), and the only possible dates for him are the 4th, 11th, 12th, l8th, and l9th, so he had at least one lesson on the same date as Harold Kleiner (the 1lth and/or the l8th); thereforei Adam isn't Fitzpatrick (clue 1), so Adam is Wolf, and FitzDaftick is Matt. Adam Wolf's lessons, then, must have been on the llth, i2th, 18th, and 19th, and Jill Ventura's were on the 4th, 5th, and 8th (clue 10), In summary: Wednesday, January 1, Edward C'rauer Saturday, January 4, Jill Ventura and Xavier Zaines Sunday, January 5, Jill Ventura and Xavier Zaines Wednesday. January 8. Jill Ventura Saturday, January I I, Adam Wolf ald Harold Kleiner Sunday, January 12, Adam Wolf and Matt Fitzpatrick Wednesday, January 15, Lillian Bradley Saturday, January 18, Adam Wolf and Harold Kleiner Sunday, January 19, Adam Wolf and Matt Fitzparick Wednesday, January 22, Lillian Bradley Saturday, January 25, Deena Stuart and Edward Grauer Sunday, January 26, Matt Fitzpatrick and Xavier Zaines Wednesday, January 29, Edward Grauer
....... December 29
lOO Easy Crosswords February............................January 3 Dell Crossword Special March....................... ......January 3 Ofticial Crossword Yearbook Winier....'...............January 5 Dell Champion Crossword Puzzles March...........January 5
Easy Fast 'N' Fun Crosswords February........'-...'January 12 Detl Word SOarch Puzzles February......................January 12' .January 12 Best of Dell Crosswords Detl Pencil Puzzles & Word Games April.......... ...January'l2 Official Crossword Puzzles Mdrch......'.................January 17 Dell Crossword Super Special Yearbook #33......January l9 Def f Crossword Puzzles March .................'...........January 24 ' Pocket Crossword Puzzles March ...... ..................January 24 24 ................'..January March.. Ofticiaf Word Search Puzzles Official Pencil Puzztes & Word Games April........January 31 Dell Crossword Yea$ook Spring.........-................January 31
#31
Easy Crosswords March ........................... ...February 2 Dell Logic Puzzles April ................. .......... ..........February 2 Delt Champion Variety Puzzles Apri1...................February 7 DellWord Search Puzzles March...... . ........'......February 7 Dell Crosswords & Variety Puzzles March .........February Delt Crosdword Extravaganza #31 ...............''.....February 9 Easy Fast'N' Fun Crosswords March.............-...February 14 Official Crossword Puzzles Apri|.........................February 14 Dell Pencil Puzzles & Word Games May...........'.Februaiy 14 Solver's Choice Crosswords Spriig ...................February 16 Pocket Crosswotd Puzzles April -...................'....February 21 Dell Cf ossword Puzzles Apri1........................-......February 21 Fast'N' Fun Word Search April.... ... ....... .- ........February 23 Dell Pencil Puzzles & Word Games Yearbook Spring.............,...... Math Puzzles & Logic Problems May .........-......'February 28 1OO
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DELL LOGIC P\)ZZLES February
1995
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