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DesignofConcreteDomesasperIS456 1) GeometryofDome: Table1 ConcreteGradefc'
15 n/mm2
m(modularratio)
18
SteelGradefyallowable
����� ����������������������
0 5 . 7
140 n/mm2
DiameterofDomebaseAB=
15.00
m
RisePS
7.50
m
.:RadiusofDomer=AO=
7.50
m
CD=Diameterofopening=
1.60
m
0.04
m
PQ=riseofopening=h sinα=cd/(2*r)
0.1067
α=
6.1232
cosα=
0.9943
sinΦ=AB/(2*r)
deg
1.0000
Φ=
90.0000
7.50
radiusofdome
���� ������� ������� ��� ��������� ��� ����� ������� ��� ���������� �� �� 7.50 � � ������ ���������������������� ������������������ ������������������ 2) Loading: ���������� ThicknessofDome= �����������
deg
SelfWtofDomeStructure=
7.50
100
LiveLoad
1.500 kn/m2
Total=w
4.000 kn/m2
WeightofLantern
22.00
kn
8.07
kn
13.93
kn
WeightofDomeShellCPD .:EffectiveWeightofLantern=WL
3) CalculationofStressesduetoCombinedLoading: Table2 M MeridonialStresses(N/mm2) er idoni al Str es s es ( N/m m 2)
mm
2.500 kn/m2
HoopStresses(N/mm2) H oop St ress es (N /m m2)
θ° D ue to w Duetow
D ue to W L DuetoWL
T otal Total
D ue to w Duetow
D ue to W L DuetoWL
Total Total
6.1232
0.1504
0.2599
0.4103
0.1479
-0.2599
-0.1120
14.5109
0.1524
0.0471
0.1995
0.1380
-0.0471
0.0909
22.8986
0.1562
0.0195
0.1757
0.1202
-0.0195
0.1007
31.2862
0.1618
0.0110
0.1727
0.0946
-0.0110
0.0836
39.6739
0.1695
0.0073
0.1768
0.0614
-0.0073
0.0541
48.0616
0.1798
0.0053
0.1852
0.0207
-0.0053
0.0153
56.4493
0.1932
0.0043
0.1975
-0.0274
-0.0043
-0.0317
64.8370
0.2105
0.0036
0.2141
-0.0829
-0.0036
-0.0865
73.2246
0.2328
0.0032
0.2360
-0.1462
-0.0032
-0.1494
81.6123
0.2618
0.0030
0.2648
-0.2180
-0.0030
-0.2211
90.0000
0.3000
0.0030
0.3030
-0.3000
-0.0030
-0.3030
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Output
4) HoopStressinabsenceofLiveLoad: HoopStressinabsenceofLiveLoadthiswillincreasetheTensileStressintheupperportionofthe Dome,speciallyneartheperipheryoftheopening.However,meridonalthrustwillnotincreaseby increasingtheLiveLoad. s el f wt = selfwt=
2.5 2.5
kn
.:EffectiveWeightofLantern=WL
=
2 2.00 22.00
-
=
16.959
kn
2 .5 2.5
x
2Π x
7 .5 7.5
x
0.043 0.043
T hus the H oop Str ess es due to s el f w eight s wt w ill be dec r eased in a r at io ThustheHoopStressesduetoselfweightswtwillbedecreasedinaratio
2 50 250
==
0.625 0. 625
=
1.217 1.217
400 whiletheHoopStressesduetoweightoflanternWLwillbeincreasedby
1 16.959 6.959
TheResultsareTabulatedbelow.
13.935
Table3 Thusweseethatthemaximumhooptensionattheopening
HoopStresses(N/mm2) θ°
hasbeenincreasedfrom D ue to w Duetow
D ue to W L DuetoWL
0.0924
-0.3163
n/mm2 to
-0.2239
n/mm2
Total Tot al 5)
6.1232
-0.1120
ProvisionofReinforcement:
-0.2239 MaximumCompressiveStress=
0.4103
n/mm2
MaximumHoopTensileStress=
-0.2239
n/mm2
14.5109
0.0862
-0.0573
0.0289
22.8986
0.0751
-0.0238
0.0514
31.2862
0.0591
-0.0133
0.0458
meridian =
39.6739
0.0384
-0.0088
0.0295
.: Area of Steel
48.0616
0.0129
-0.0065
0.0064
Temperature Steel =
56.4493
-0.0171
-0.0052
-0.0223
64.8370
-0.0518
-0.0044
-0.0562
Safe
.:MaximumHoopTensileStresspermeterlengthof -0.2239 =
x
100
x
1000
-22389.11 N =
22389
=
160
mm2/m
140 0.15
x
100
x
1000
100 =
150
mm2/m
.: Total Reinforcement : = use Hence Provide 73.2246
-0.0914
-0.0039
310
mm2/m
8
mm Φ @
162
mmc/c
8
mm Φ @
160
mmc/c
ok
-0.0953 InPortionwherenoHoopTensionisdeveloped
81.6123
-0.1363
-0.0037
-0.1400
provide0.15%reinforcement use
90.0000
-0.1875
-0.0036
-0.1911
Hence Provide
=
150
mm2/m
8
mm Φ @
335
mmc/c
8
mm Φ @
300
mmc/c
Prep By : A B Quadri- Abq Consultants - 9959010210 -
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[email protected]/2 Royal Residency, Besides Amba talkies, Mehdipatnam , Hyderabad-India. 500028-w.abqconsultants.com 500028-w.abqconsultants.com
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6)
Calculation
Output
DesignforLowerRingBeam:
M er idonal Thr ust per M eter l ength of the D om e at i t's Base = MeridonalThrustperMeterlengthoftheDomeatit'sBase= = H ori z ontal c om ponent T per unit length : HorizontalcomponentTperunitlength:
=
..:HoopTensiontryingtorupturetheBeam: : H oop Tensi on tr yi ng to r uptur e the Beam :
30296 =
x
0.3030
x
30296
n/m
cos
0
x
15
90.00
=
=
0
100
x
1000
0
n/m
n
2 .: Area of Steel
=
0
=
0
mm2/m
use
140
As =
10 79
mm Φ
mm2 >
HenceProvideRings
10
1 0
mmΦ
nos mm2
6
ok
nos
ok
EquivalentareaofcompositesectionofBeamofareaofcross-sectionofareaA: = A + (m - 1)*Ast
=
A
+
=
A
+
Allowing Tensile Stress of
1.2
18
x
78.5
x
6
8482
n/mm2 in composite section, we have
1.2
=
0 (A+
SolvingFromwhich A conc weget
=
-8482
mm2
.:
Provide a Ring Beam size Area=
Stirrups Note:RingBeamisassumed
200
40000
HenceProvideRings 6
mm Φ
8482
mm2 > 10
mmΦ @
160
x
)
200
-8482 6
ok nos
mm c/c
0 0 2
tobecontinouslysupportedby concretewallfrombelow.
RingBeam
200
Prep By : A B Quadri- Abq Consultants - 9959010210 -
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[email protected]/2 Royal Residency, Besides Amba talkies, Mehdipatnam , Hyderabad-India. 500028-w.abqconsultants.com 500028-w.abqconsultants.com
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