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BITSAT BITSAT 2008 200 8 MTP 5/QNS

BRILLIANT’S MOCK TEST 5

Test Booklet Code

FOR STUDENTS OF

OUR ONE/TWO-YEAR POSTAL COURSE TOWARDS

BITSAT, 2008 Time: 3 Hours

E Maximum Marks: 450

Read the following instructions carefully: 1. Immediately fill in the particulars on the Answer Book with Blue/Black Ball Point Pen. The Answ Answer er Shee Sheett is kept kept insi inside de this this Test Test Book Bookle let. t. When hen you you are are dir directe ected d to open open the the Test Test 2. The Booklet, take out the Answer Sheet and fill in the particulars carefully. idate e should write ite the their Enrolme olmen nt No. onl only in the the spa pace ce provid ovide ed on the the Test est 3. The candidat Booklet/Answer Sheet. each cor correct ect respo espons nse, e, the the can candida didate te will will get get 3 mar marks. ks. For each each inco incorrrect ect respo espons nse, e, 4. For each one mark will be deducted from the total score. No deduction from the total score, however, will be made if no response is indicated for an item in the Answer Sheet.

5. The test is of 3 hours duration. 6. The test consists of 150 questions. 7. The maximum marks are 450. Use Blue Blue/B /Bla lack ck Ball Ball Point oint Pen only only for for writ writin ing g pa parrticu ticula larrs/ma s/marrking ing respo espon nses ses on Side Side 8. Use

−

1

and Side − 2 of the Answer Sheet.

9. Rough work is to be done on the space provided for this purpose in the Test Booklet only. 10. Do not fold or make any stray marks on the Answer Sheet. 11. Use of Electronic/Manual Calculator is prohibited .

Name of the Candidate (in Capitals): ........................................................................... ........................................................................... Enrolment Number: ◊

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2 PART I: I: MATHEMATICS 1. If the sides of a triangle are in the ratio

1 :

3 : 2; then the angles opposite to

thes these e sides ides of a tri triangle gle are in the the ratio tio

t

4.

2

∫ xf x

dx =

4 2 5 t , t > 0, then f 25 5

is

0

equal to (1) 1 : 3 : 2

(2) 3 : 2 : 1

(3) 2 : 3 : 1

(4) 1 : 2 : 3

2. If sin (cot

−1

(1)

(x + 1)) = cos (tan−1 x), then x

is

(2) 0

3. If sin θ =

1 (4) − 2

(3) 1

1 1 , c os φ = (both θ and φ are 2 3

acute angles), then (θ + φ) lies in the interval

(3)

(2)

5 2

(3)

5 3

(4) 1

5. If f(x) is differentiable and strictly increas 2

1 (1) 2

(1)

2 5

π

3

,

ing functio ction n, then

Lt x → 0

f x  f x f x  f 0

is

equal to (1) 2

(2) 1

(3) − 1

(4) 0

6. If x is the first term of a geometric pro-

gressio ssion n with ith inf infini inite number mber of ter terms, ms, whose sum is 5, then π

2

2π 5π , 3 6

(2)

(4)

π

2

,

2π 3

5π , π 6

(1) 0 < x < 10

(2) x ≥ 10

(3) x < − 10

(4) − 10 < x < 0

SPACE FOR ROUGH WORK















3 7. The line 2x +

6 y = 2 touches the

hyperbola x2 − 2y2 = 4 at the point

the lines ines 10. If the x

(3) 4,

3

1

1 1 , 2 6

(1)



(2) 4,

(4)

6



y



1

2 

k

2

=

y

=



1

3

z 1

are

=

z



1

4

and

intersecting

each other, then k is

6

2,

=

x

(1)

6

8. The least positive value of n for which

(1 + ω2)n = (1 + ω4)2, where ω is a non-

2 9

(2)

9 2

(3) 1

(4)

3 2

equall 11. If log (x + y) − 2xy = 0, then y′(0) is equa to

real cube root of unity is (1) 0 (1) 2

(2) 3

(3) 6

i



2j

j







6k

and

k and 2 i

coplanar 

j



(3)

3j



k



3k

10

(2)

(4)

i



k



1 3

x − 2y − z = − 4, x + y + λz = 4 has no solution, then the value of λ is (2) 2

(3) 3

(4) − 3

13. A fair dice is rolled till the number 1

2 i

(4)

the syst system em of equa equati tion onss 2x − y − 4z = 2, 12. If the

(1) 1

10 i

with

k. Then the

vector is

(1)

(3) − 1

(4) 4

9. A given unit vector is orthogonal to

5i

(2) 1

3j

appears on top face of it. The probability that the the dice ice is thr thrown even ven number ber of times is

10 (1)

5 11


(2)

1 6

(3)

5 6

(4)

5 36















4 3 2 14. Let P = 1  2 T

1 2 ,A= 3 2 T

2008

Q = PAP . Then P Q (1)

1 1 4  2008

16. If a, b, c are integers and not all are equal,

then the least value of |a + bω + cω2|

1 1 and 0 1

is (wher where e ω and ω2 are non-real eal cube cube roots of unity)

P is (1) 0

2008  1

(2)

3 2

(3) 1

(4)

1 3

0

(2)

(3)

(4)

1 0

2008 1

17.

[

3

+ 3x2 + 3x + 3 + (x + 1) cos (x + 1) ] dx

2

is equal to

2008 1 1 0 1 4

∫x (1) 2

(2) 4

(3) 1

(4) 0

variabl iable e plan plane e at a unit unit dist distan ance ce from from 18. A var

 1  2008 2008 1

origin cuts the axes at A, B, C. If the

15. If 3 circles of radius 1 are drawn in an

equi equila late terral tria triang ngle le as show shown n in figu figurre, then area of the triangle will be

centroid (x, y, z) of ∆ABC ABC sati satisf sfie iess 1 x

2



1 y

2



(1) 3

1 = k, then k is 2 z

(2) 9

(3) 4

(4) 6

the roots ots of the the equatio ation n 19. If α and β are the ax (1) 7 

4 3 3

(3) 10  4 3

(2) 6  4 3 (4) 8 

3

2

+ 2bx + c = 0, ∆ = b2 − ac and and α + β,

α2 + β2, α3 + β3 are in G.P., then (a ≠ 0) (1) bc ≠ 0

(2) ∆ ≠ 0

(3) ∆b = 0

(4) ∆c = 0
















5 20. The value of

∞

30

C030C10 − 30C130C11 + 30C2030C30 is

(1) 30C10 (2) 60C20 (3) 60C30

(4) 40C30

21. If the graph of the function x 2 − 4x + log3 a

does does not cut cut the the real eal axis axis,, then then the the leas leastt integral value of a is 

(1) 80

(2) 81

(3) 82

(4) 0

real roots and 4(a − b) > 3c, then c should be (2) non-negative

(3) positive

(4) zero

23. Given 0 < x <

π

4

,

π

4

< y <

π

2

,

y is equal to

(1) a + b − ab (2)

ab a  b 1

(3)

1 1 1   a b ab

(4)

1 1 1   a b ab

 1

k

tan

2k

a1a2a7 is least when the common

23 20

25. If xn =

x and

13 22

(3)

C 

P 143 n 96 P

(2)

n 5

4

43 20  5

(4)

33 20

, n ∈ N a nd

n 3

Pk den denotes otes the the numb number er of per permuta mutati tion on

∞

k = 1

2k

k = 0

(1)

k = 1

∑

x cot

difference is

∞

b=

2k

24. If in an A.P. a1, a2, a3, ...; a7 = 9, then

(1) negative

∑

tan



the equa equati tion on ax2 − 2bx − 3c = 0 has no 22. If the

a=

∑

 1

k

cot

2k

y, then

of k things taken all at a time, then the number of negative terms in the sequence {xn} is (1) 1


(2) 2

(3) 3

(4) 4















6 26. If Cn denotes nCn and Sn denotes the sum

to n terms of the A.P. a, a + d, a + 2d, ... then aC0 + (a + d)C 1 + (a + 2d)C2 + ... (n + 1)

29. The number of permutations of the word

HIND HINDUS USTA TAN N such such that that non none of the the thr three patterns HIN, DUS, TAN occurs is (1) 169194

(2) 166680

(3) 169190

(4) 166670

terms is equal to

(1)

S

n

2

n

(3)

S n

27.

n



1

n





C

2

n

S

(2)

n

n 1

1

2

n

2



(4)

S

C

2



3

C

2

1



n

n 2

1





4

2

n

C

2



2

n



1

)(x − δ), the then 30. If f(x) = (x − α)(x − β)(x − γ )(x

1



the determinant

n

C

2

is equal to (1) 12 + 22 + 32 + ... + n2

(4) 14 + 24 + 34 + ... + n4

The numb number er of posi positi tive ve inte integr gral al solu soluti tion onss 28. The of the the equatio tion x1 + x2 + x3 − x4 = 0 with the condition x4 ≤ 10 is (3) 55

x

x γ x

x

x x δ

is equal to

(1) f ′(x)

(2) xf ′(x)

(3) f(x) + xf ′(x)

(4) f(x) − xf ′(x)

Adj (AT) − (Adj A)T is equal to

(3) 1 + 2 + 3 + ... + n

(2) 150

x x

x x x β x

31. If A is a square matrix, then

(2) 13 + 23 + 33 + ... + n3

(1) 120

α

(4) 65

(1) 2|A|

(2) 2|A|I

(3) null matrix

(4) unit matrix

32. If z + 1 = i 3 and n is a positive integer

but not a multiple of 3, then z2n + 2n zn is equal to (1) 0


(2) − 1

(3) 22n

(4) − 22n

















7 epresen sented ted by the the 33. If z1, z2, z3, z4 are repr vertices of a quadrilateral taken in order such that z1 − z4 = z2 − z3 and z

Amp

z

4 2

 

z z

1

=

1

π

2

, then the quadri-

(1) Rhombus

(2) Square

(3) Rectangle

(4) Trapezium

1



a

2

cos x + c where

|a| < 1 and b > 0 lies in the interval (1) [b − c, b + c]

(2) (b + c, b − c)

(3) [c − b, c + b]

(4) (a − b, a + b)

35. The most general value of x for which

sin x + cos x = min {1, a2 − 4a + 6} are a ∈ R

1

n

π

4



π

4

36. If a right angled triangle ABC of maxi-

1 r

1 r



1

2

2

(1)



1 = r 3

1

R 2



2



1 2



sin

2



1

R R

(4)

1

cos x

2

(2)

R

(3)

37. If



2 x





1

1 = 2, then 2

1 sin−1 (k) where k is equal to 2

(1) 0

(2) 1

(3) − 1

(4) ± 1

38. If 4a2 + 3b(4a + 3b) − c2 = 0, then the

family of straight lines ax + by + c = 0 are concurrent at the point

2nπ (1) 2nπ

(2) 2n π



1)π (4) (2n + 1)π

x=

given by



mum area is ins inscri cribed in a circ ircle, le, then then

lateral is a

34. ab sin x + b

(3) n π



π

2

(1) (− 2, 0)

(2) (2, − 3)

(3) (2, 3)

(4) (3, 1)


















8 isosce cele less tria triang ngle le ABC ABC is insc inscrribed ibed in 39. An isos

The numb number er of solu soluti tion onss of the the equa equati tion on 43. The

a circle x2 + y2 = a2 with verte ertexx A(a, 0) and the the base ase angl angles es B and C are are equa qual

|2x − 1| = 3[x] + 2{x} where [x] is the

to 75°, the then the the coor oordin dinates tes of C which

fractional part of x is

lies in the third quadrant are (1)



3 2

a,

(3)  a, 

 a 2

3a

(2)

(1) one

 a  3 , a 2 2

(4) 

3a,  a

40. The area of the triangle formed by the

tangent to the parabola y = x2 at the poin pointt whos whose e ab absc scis issa sa is k ∈ [1, 3], the yaxis and the line y = k2 is greatest if k is equal to (1) 1

(2) 2

(3) 3

grea greate test st inte intege gerr ≤ x and {x} is the

bise bisect ctin ing g at right ight angl angles es,, then then the the locu locuss of the point P such that PA ⋅ PB = PC ⋅ PD is (1) Circle

f x

= ax  b,

42. The number of real roots of the equation

x< 1

able then the values of a and b are (1) (2, 3)

(2) (3, 2)

(3) (− 2, − 3)

(4) (− 3, − 2) t

tion f(t) = d 45. The function dt

∫ 1  codxs t cos x 0

satisfies the differential equation (1)

df + 2f(t) cot t = 0 dt

(2)

df − 2f(t) cot t = 0 dt

(3)

df + 2f(t) = 0 dt

(4)

df − 2f(t) = 0 dt

3x5 + 15x = 0, greater than 1 is equal to (4) 5

x ≥1

is everywhere continuous and differenti-

(4) Rectangular hyperbola

(3) 3

2

= bx b x  ax  4, 2

(2) Parabola (3) Ellipse

(4) nil

44. If the derivative of the function

a

(2) 1

(3) three

(4) 4

41. AOB, COD are two unequal line segments

(1) 0

(2) two


















9 PART II: PHYSICS PHYSICS

ment of the force show shown n abou bout 46. The momen A is

48. The most suitable material for making

an LDR (Light dependent resistor) is a semiconductor material having (1) Eg >> h ν (2) Eg > h ν

(1) zero

(2) − 565.68 N-m

(3) 848.528 N-m

(4) 200 N-m

47. Stationary waves are formed in an

acoustic medium by combining two simple harmonic waves in such a way that the point x = 0 is a node. The equation of one of the waves is y = a cos (ωt − kx). The equ equation tion of the other wave is (ωt + kx) (1) y = a cos (ω (ωt + kx) (2) y = a sin (ω (ωt + kx) (3) y = − a cos (ω (ωt − kx) (4) y = − a sin (ω

(3) Eg = h ν (4) Eg << h ν

atch List List-I (Polar olariz izat atio ion n proc proces ess) s) with with 49. Match List -II

(Approximate

frequency)

and

select the correct answer using the codes given below the lists. List-I

List-II

(Polarization

(Approximate

process) A. Elec Electr tron onic ic

frequency)

i 102 Hz

polarization B. Ionic Ionic polar polariza izatio tion n ii 105 Hz C. Orie Orient ntat atio ion n iii 1013 Hz polarization D. Space-charge iv 1015 Hz polarization


















10 Codes

(3) intrinsic

A

B

C

D

(1)

i

ii

iii

iv

(2)

iv

iii

ii

i

(3)

i

iii

ii

iv

(4)

iv

ii

iii

i

(4) highly degenerate 52. Given two statements A:

The The inte interrnal nal ener energy gy of an idea ideall ga gass does not change isothermal process.

R:

50. Compare the total energy (Eb) of a

boun ound system tem such as nucleu leus with ith the the total energy (Es) of the separated

during

an

The decrease in volume of a gas is comp compen ensa sate ted d by a corr corres espo pond ndin ing g increase in pressure when its temperature is kept constant.

are tru true, and and R is the (1) Both A and R are

nucleons:

correct explanation of A.

(1) Eb < Es

are true true,, but but R is NOT (2) Both A and R are (2) Eb = Es

the correct explanation of A.

(3) Eb > Es

(3)

A is true, but R is false.

(4) depends on how heavy the nucleus

(4)

A is false but R is true

is

the foll follow owin ing g ap appl plic icat atio ion ns, fric fricti tion on is 53. Of the

When a semi semico cond nduc ucto torr ba barr is heat heated ed at 51. When one end, a voltage across the bar is developed. If the heated end is positive, the semiconductor is

maximized in (1) Roller and Ball bearings (2) door hinges

(1) p-type

(3) Piston and cylinder

(2) n-type

(4) wedges SPACE FOR ROUGH WORK

















11 lectrron (E), E), prot proton on (P), heli helium um nucl nucleu euss 54. Elect (He++) and deuterium nucleus (2H+) all have cha charge as well as mas mass. The ord order in which they are arranged in incr incre easi asing mag magnitu itudes of the valu alue of charge to mass ratio is

D. Cyclotron

Codes

A

B

C

D

(1)

i

iii

ii

iv

(2)

iv

iii

i

ii

(3)

iv

iii

ii

i

(4)

ii

i

iii

iv

(1) E, P, He++, 2H+ (2) P, He++, E, 2H+ (3) 2H+, He ++, P, E (4) He++, 2H+, P, E 55. Match

the

following

(choose

the

correct alternative). I

A. Asto Aston’ n’ss mas masss spectrograph

B. Magnetron

C. Betatron

iv. All particles with same value of e/m brought to a single focus

56. The technology used for display in PC II

i. Relati lativ vistic stic variation of mass has no effect ii. Relativistic variation of mass limits the maximum velocity Iii. Radial electrical field and axial magnetic field

note-books (lap-top computers) is (1) Light Emitting Diodes display (2) Liquid Crystal display (3) CRT display (4) Plasma display




















12 57. Identify Rutherford s discovery of proton: 

gas is

(1) 7N14 + 2He4 → 8O17 + 1H1 9

4

13

(2) 4Be + 2He → 6C

temper temperatu ature re T2 . The work done by the

1

(1) R(T1 − T2)

(2) Cv (T1 − T2)

(3) Cp(T1 − T2)

(4)

+ 0n

C 12

(3) 6C

15

(4) 7N

1

13

+ 1H → 7N 1

12

+ 1H → 6C

+ ∆E

C

(T1 − T2)

v

4

+ 2He

60. Which

58. When a given mass of ice at 0°C is

converted to water at the same temperature, OR when an equal amount of water at 100°C is conv conver erte ted d

of the following are the properties of ferromagnetic domains?

i.

Perma ermane nent nt magn magnet etis isat atio ion n.

ii.

Atomic moments in individual domains are all aligned neither parallel to nor perpendicular to one another below Curie point temperature.

iii.

Each domain saturated.

iv. iv.

Abov Above e Cur Curie temp temper erat atur ure, e, doma domain inss disrupt.

to stea steam m at the the same same temp temper erat atu ure, re, the the entropy changes. If the entropy chan changes ges are are δS1 and δS2 in the case of ice and water, respectively, then (1) δS1 = gain δS2 = gain δS2 < δS1 (2) δS1 = gain δS2 = gain δS2 < δS1 (3) δS1 = loss δS2 = loss δS1 < δS2 (4) δS = gain δS = loss δS

p

δS

is

magnetically

Select the correct answer using the codes given below.



















13 61. If a varying current flows in the wire CD

placed placed near a copper copper ring, ring, what what will happen in the wire?

(2) Silicon dioxide (3) Tin oxide (4) Chromium oxide 64. When a metal is heated, electrons are

(1) A current will flow in the ring in the

clockwise direction (2) A current will flow in the ring in the

anticlockwise direction

(3) thermions

The ring ring will be attra attracte cted d to the (4) The wire 62. The total intensity of earth’s magnetic

field (F) is (where V and H are standard components of F) (2)

V

V H

(4)

V

(3)

2

(1) heated electrons (2) photoelectrons

(3) No current will be set up

(1) V ⋅ H

emitted from its surface. These electrons are called





H

H

2

(4) positrons

When ice melts and becomes becomes water, water, 65. When the

ice ice-wa wate terr

syst system em

unde underg rgoe oess

a

change such that entrop opy y (1) entr

and and

inter interna nall

entrop opy y (2) entr

and and

inte intern rnal al

decre decreas ases es energy increases

incr increa ease sess energy decreases



















14 66. Dimension of nucleus is of the order of

1 Fermi. With what velocity should elec electr tron onss move move so that that it is found ound insi inside de the nucleus? (1) 7 × 1011 m/s

(2) 3 × 108 m/s

(3) 6 × 108 m/s

(4) 1.5 × 108 m/s

Identify fy the β deca decay y from from the the foll follow owin ing g 67. Identi

ii. In the exoergic reaction

Q is negative

Energy is absorbed

Iii. ii. In the the endoergic reaction

Q is negative

Energy is absorbed

iv. In th the endoergic reaction

Q is positive

Energy is released

reactions

(1) i and iii

(2) i and iv

(1) 6C11 → 5B11 + −1e0 + ν

(3) ii and iv

(4) i only

(2) 1p1 → 0n1 + −1e0 + ν

69. Given two statements: A:

1

1

(3) 1p + ν → 0n + −1e

0

(4) 0n1 → 1p1 + −1e0 + ν 68. In

any nuclear reaction, energy is rele releas ased ed or ab abso sorb rbed ed and and acco accord rdin ingl gly y the Q-value which is our index for the

change in the energy is positive or ti St dy th stat stat t iv

BaTiO3 is a piezo iezoe elec lectri tric mater terial ial and is used in a record player .

R:

In a piezoe piezoelec lectr tric ic tran transdu sducer cer,, stress stress induces polarization a nd an electric field strains the material.

are tru true, and and R is the (1) Both A and R are correct explanation of A.



















15 70. A:

When lig light fails ails at the the jun junction tion of a p-n photo diode, its P side becomes positive and becomes negative.

R:

N

side

When a photo diode is shortcircuited, the current in external circuit flows from P-side to the N-side.

the the

are true true,, and and R is the (1) Both A and R are correct explanation of A. are true true,, but but R is NOT (2) Both A and R are the correct explanation of A. (3) A is true, but R is false.

72. The Bohr magnetron (µB) is directly

proportional

to

e/ m

elect lectrron. on. That That is µB = K

ratio

of

the

e where K is m

given by h/4π (1) h/4π

h/2π (2) h/2π

(3) h

(4) 2t

Minimum mum distan distance ce betwee between n objec objectt and 73. Mini its real imag mage form ormed by a conv onvex lens ens, in terms of its focal length (f) is (1) 1.5 f

(2) 2.5 f

(3) 2 f

74. Suppose

(4) 4 f

that the earth s angular veloc velocity ity incr increa eases ses n time timess the the cur current ent veloci locity ty,, a pers erson on the sur surface ace of the the earth will feel weightless if 





(4) A is false but R is true. (1) n = 17

(2) n = 71

(3) n = 1.7

(4) n = 0.17

71. Suppose along

a narrow cylindrical tube tube of are area of cro cross-sect sectio ion n (A) (A) ther there e is a flow of electrons with a drift vel (v). Then the electric current is (1) proportional to 1/v and A

75. The true r.m.s. voltmeter employs two

thermocouples in order to (1) prevent drift



















16 76. If a small amount of Cu is added to a Ni

conductor, then the


(1) resistivity of Ni will decrease at all

temperatures because Cu is a better conductor than Ni

When an impurity is added to a pure metal etal,, the the resi esidua dual resis esisti tiv vity ity at zero K is not zero.

R:

At

absolute

zero

temperature,

lattice vibration ceases to exist.

(2) residual

resistivity of Ni at low temperatures will increase as Cu atoms act as defect centres

are tru true, and and R is the (1) Both A and R are

(3) resistivity of Ni will increase at all

are true true,, but but R is NOT (2) Both A and R are

temperatures as Cu destroys the periodicity of Ni and acts as defects resist stiv ivit ity y of Ni rema remain inss unal unalte tere red d as (4) resi Cu atom atomss give give the the same same numb number er of free electrons as Ni atoms

correct explanation of A. the correct explanation of A. (3)

A is true, but R is false.

(4)

A is false but R is true.

79. A:

Superconducting materials are not good good cond conduc ucto tors rs at room room temperature temperature as the normal metals are at room temperature.

R:

Sup Supercon conductiv ctivit ity y is obse obserrvab ablle only only if the the ap appl plie ied d magn magnet etic ic fiel field d is below the critical field.

77. A plane EM wave of the form

E

=

E0 cos [2π [2π {(5 × 1014 sec −1) t −1

− (2.5 × 106 m ) x }] represents a wave travelling along (1)

x direction

are tru true, and and R is the (1) Both A and R are correct explanation of A.





















17 arallel llel resona onance circ ircuit formed med 80. In a para of L and C, reson sonance is to be obtain taine ed with an oscillator giving an output frequen quenc cy of ω rad/sec. To obtain resonance, and unity power factor (1) either one, L, C or ω can be varied (2) it is better to vary L rather than C or ω (3) it is better to vary C or ω rather than L (4) it is best to vary C 81. When a concave lens made of glass is

immersed in water it becomes

(ii)

Use of thicker medium of the same refractive index to increase magnification

(iii) Use of a second lens to enhance the magnification (iv) iv) Use Use of spec specia iall wood wood oil oil to elim elimin inat ate e chromatic aberration (1) (i) and (iv)

(2) (ii) and (iv)

(3) (ii) and (iii)

(4) (i), (ii) and (iii)


Optical

fibres

have

broader



















18 84. An electric dipole of length 2 cm is

place laced d with with its its axis at an angle of 60° to

earth. The three isotopes and their masses are are

5

a uniform electric field of 10 N/C. It expe experrienc iences es a tor torque que of 8 3 N-m. The potential energy of the dipole is (1) 2 J (3) − 8 J

(2) − 4 J

and and

24 12

Mg 23.98504 u ,

24 12

24 12

Mg 25.98259 u . The natural abun-

dance of

24 12

Mg 24.98504 u is 78.99% by

mass. The abundance of

(4) + 8 J

Mg 24.98584 u

24 12

Mg 24.98584

is

eriodi odic tabl table, e, the the avera erage atom atomic ic 85. In peri mass of magnesium is given as 24.312 u. The average value is based on the rela relati tive ve natu natura rall ab abun unda danc nce e of isot isotop opes es

(1) 11.7%

(2) 21.2

(3) 78.99%

(4) 50%




















19

PART III: CHEMISTRY our diff differ eren entt sets sets of quan quantu tum m numb number erss 86. Four of four electrons are given as A. 5, 0, 0, +

1 2

B. 4, 1, + 1, −

Nature bonds in the compounds between these elements XY, YZ and XZ are

1 2

(1) ionic (2) covalent

C. 4, 2, + 2, + 1 2

D. 4, 0, 0, − 1 2

(3) XY is covalent, but YZ and XZ are

ionic Order of energy is (4) XY and YZ are covalent but XZ is (1) A > B > C > D

(2) D > C > B > A

ionic



















20 90. Correct order of hydration energy is (1) Li+ < Na+ < K+ < Rb+ +

+

+

(2) Li < K < Na < Rb

+

(3)

Pt NH

(4)

Cr NH

Cl

3 3

3 6

Cl

activity is

(4) Rb+ < Na+ < K+ < Li +

(1) tran - Co NH

effect is

(2)

(2) F, Cl, Br, I

(3) Tl, Pb, Bi

(4) Pb, Ba, Al, I

statem emen entt amon among g the the foll follo o92. The correct stat



3 4

Cl

2

3

Cr H O 2

(1) Na, Mg, N, P

3

94. The complex ion which can exhibit optical

(3) Rb+ < K+ < Na+ < Li +

91. The set of elements showing inert pair

Cl

3

6 

(3) cis- Co NH

3 4

Cl

2 3

(4) cis- Co en

2

NH

3 2



















21 98. 0.1 M silver nitrate and 0.2 M aqueous

KCl are mixed in equal volume. The molarity of NO

 3

103. A gas behaves ideally at (1) high pressure

in the solution is (2) high temperature

(1) 0.2 M

(2) 0.15 M

(3) 0.05 M

(4) 0.1 M

99. The decomposition of limestone in a

closed volume vessel is represented as

(3) around its Boyle s temperature 

(4) all of the above conditions 104. The type of bonds present in copper

sulphate crystals are (1) ionic bonds

The pressure exerted by CO2 is equal to

(2) covalent bonds (3) coordinate bonds





















22 106. One mole a gas absorbs 1.2 kJ of heat

atch the the Lis List I with ith Lis List II and selec electt the the 109. Match

at cons consta tant nt volu volume me and and its its temp temper erat atur ure e is raised from 298 K to 328 K. The values

correct answer from the codes given below the lists:

of q, w and ∆u are respectively (1) ∆u = q = 1.2 kJ, w = 0

List I

A RCH OH

List II

P Vi l t

l

ith



















23 tch the List ist I with ith Lis List II and and select lect the the 110. Match correct answer from the codes given below the lists: List I

List II

111. The products A, B and C of the following

reactions respectively are



















24

113. Match the List I with List II and select the correct answer from the codes given below the lists: List I

List II

C. Dialysis

R. Tyndall effect

D. Coag Coagul ulat atio ion n S. Lar Large volu volume me of H2 is adsorbed by palladium



















25

116. Which one is not a fertiliser?

119. Arrange in the increasing order of acidic stren strength gth of tertia tertiary ry butan butanol, ol, isopr isopropa opano noll

(1) NH2CONH2

and ethanol.

(2) (NH4)2 HPO4

(1) Ethanol < isopropanol < tertiary butanol



















26

122. Which of the nitrate leave behind its metal on strong heating?

(1) Ferric nitrate

are poiso poiso(2) Hg0, Hg+2, Cu0, Cu+2, Cd+ are nous to living system. lexibl ble e rubb rubber er is hard harden ened ed by cros crosss (3) Flexi polymerisation with ZnO.























































































































































































































































































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