DESIGN OF WELL FOUNDATION 1.0
HYDRAULIC PARTICULARS
Design discharge through the bridge
=
2800
LWW
=
125.00
%
=
&.&0
#$L
=
51'.(5
h
=
0.15
ds"
=
5.',-
a!i"u" de+th of scour at ier
D
=
11.2(
a!i"u" de+th of scour at )but"ents
D
=
-.1-
1
=
,(-.-55
2
=
,(2.,1'
&
=
,('.11,
)1
=
505.0'&
)2
=
505.0'&
=
-5
u"ber of *+ans. * irder
=
&
*+an c3c of iers
=
&,.8
*4ew of the /ridge 6ight rossing7
=
il
Effective linear water way a!i"u" "ean velocity of flow at #$L #igh $lood Level )fflu! assu"ed *cour De+ths with *ilt $actor of 1.25 for ediu" *and ean de+th of scour
$ounding Levels of Wells iers
)but"ents
*afe /earing a+acity for $oundations on *and
2.0
TECHNICAL DATA
#eighest $lood Level
#$L
=
51'.(50
/otto" of Dec4
/D
=
518.-8,
6oad $or"ation Level
6$L
=
520.8,(
#eight of Dec4 9 radient 9 W.
=
2.0'5
#eight of edastal for resting /earings
=
0.150
:hic4ness of Elasto"eric /earings
=
0.0-8
ini"u" :hic4ness of ross /ea"
=
:o+ of /ed /loc4
=
518.55'
/earing Level
=
518.-0'
=
50(.(1'
Low Water Level
LWL
;
:o+ of Well ca+ 150 "" above LWL7
=
510.0''
uter Dia"eter of ier
=
&.10
=
1.50
:hic4ness of ier
=
0.80
De+th of a+ing /ea"
=
2000
:hic4ness of Well ca+
=
2.25
/otto" of Well ca+
=
50-.81'
*cour Levels with ds"
=
5.',-
=
505.'5'
$or ier 2 ds" $or )but"ent 1.2- ds"
=
50(.--8&1
=
50'.-85,
lause 222., of <6';2000. $or *eis"ic (0> $or ier 1.8 ds" (0> $or )but"ent 1.1,& ds"
=
510.,(5,-(
/otto" of $oundations as +er + er *cour calculations Well $oundations7 $oundations7 iers ; 2
=
501.8(1
rovided considering e!isting soils
=
,(2.,1'
)but"ents ; )2
=
505.0'&
Line Linear ar wate waterw rwa ay +rov +roviided ded 6ig 6ight ht cros crossi sin ng7
=
125. 125.00 000 0
a!. "ean %elocity of water flow at #$L :ilt
= =
&.&0 1 in 80
*hift
=
)llowable :ilts :ilts ? *hift of well
Dia"eter of Wells ; ier
0.15
= ; )but"ent
-.00
= a aisson
:hic4ness of steining
=
0.(00
*lant height of well curb
=
1.''5
a!i"u" $oundation ressure
=
5'.880
a!i"u" *teining *tress
=
12(.2-
.6
=
20-(.''
=
11(2.12
*+an length c3c of +iers
=
&,.8
:otal width of dec4ing
=
12
*traight 6eturns $lywings
Design of a+ing /ea"
3.0 3. 0
SUPE SU PER R STRU STRUCT CTUR URE E AN AND D LOAD LOADIN INGS GS & TY TYPE PE OF OF SUB SUBST STRU RUCT CTUR URE E
Width of roadway in between rash /arriers
=
11
Width of $oot+aths
=
Width of rash /arriers
=
:y+e of *u+erstructure
= * irder
a"ber considered in slab in one direction
=
2.5
:hic4ness of @nifor" Wearing coat in &0
=
0.0-8
:y+e of *ubstructure
= 6 #ollow
:y+e of $oundation for iers
= 6 ircular
) 0.50
6 aisson :y+e of Well ca+s
4.0
= 6 6 ircular
DESIGN LOADINGS
@nit Weight of Dead Loads as +er <6';2000 @nit Weight of *
=
2.50
@nit Weight of 6
=
2.,0
@nit Weight of
=
2.&0
Weight of rash /arriers
=
0.80
Weight of Wearing oat
=
0.18
:y+e of Live Loads
= n ne lane of ne lane of
*eis"ic Effect; Aone
=
*eis"ic oefficient
=
<< 0.021
arts of the structure e"bedded in soil shall not be considered to +roduce +r oduce any *ei"ic forces.
5.0
Wind force
= )s +er <6';
:y+e of /earings
= El Elasto"eric
E!+ansion Boints
= &0 &0 "" *tri+
Drainage *+outs
= )s +er <6 *t
DESIGN OF SUBSTRUCTURE
*+an;1C c3c of iers
=
&,.80
*+an;2C c3c of iers
=
&,.80
:hic4ness of E!+ansion Boints
=
&0
:otal length of irder ;1
=
&,.05
:otal length of irder ;2
=
&,.05
c3c of bearings with end distance of ,0 ""
u"ecs " "3sec " "
" " "
" " " " " t3"2
os "
" " " " " " " " " "
" " " " "" " " " " "
" "
" " " " "3sec
" "
" "
t3"2 t3"2 t;" t;"
" "
"
"
> " ircular iers Well ?
t3"& t3"& t3"& t3" t3"2 lass ; -0 6 9 lass )
2000 earings
seal
andards
" " ""
" "
DESIGN OF PIER CAPING BEAM 1.0
DEAD WEIGHT
Weight of rectangular +ortion
=
1100
=
12.00
=
&.10
=
(8.21
=
0.00
)rea to+
=
&-.20
)rea botto"
=
15.81
)verage area
=
2'.51
/ea" Weight of :a+ered +ortion
Weight of :a+er +ortion
"" " " t t
s" s" s"
