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CHEMICAL ENGINEERING SERIES: HEAT TRANSFER SOLVED SOLVED PROBLEMS PRO BLEMS
Consider a composie !a"" #a inc"$des an %&mm #ic' #ard!ood sidin( )'* +,+-. /0m1234 .+& mm 56 78+&mm #ard!ood s$ds )'* +,79 /0m123 on +,9&m ceners !i# ("ass ;i5er ins$"aions )paper&;aced4 <% '(0m 83 )'* +,+8% /0m1234 and a 7<&mm "a6er o; (6ps$m )=ermic$"ie3 )=ermic$"i e3 )'* +,7> /0m123 !a"" 5oard, /#a is #e #erma" resisance associaed !i# a !a"" #a is <, m #i(# 56 9, m !ide )#a=in( 7+ s$ds4 eac# <, m #i(#3?
So$rce: F$ndamena"s o; Hea and Mass Trans;er 9 # ediion4 56 Incropera4 e a" SOL@TION:
Mode o; Hea Trans;er: cond$cion !i# resisances in series and para""e" RT
1
R wall= 10
( ) 1
=
10
RT
R T = R A + R¿ + R D
1
RT = R A +
1
R B
R A =
R B =
x A k A A A
x B k B A B
+
=
=
1
+ R
D
RC
0.008 m
(
0. 094 094
W m ∙ K
)
( 0.65 m x 2.5 m )
0.130 m
(
0.16
W m ∙ K
)
( 0.04 m x 2.5 m )
ENGR, RONNIE V, FLORES
=0.0524
= 8.125
K W
Pa(e 7
K W
CHEMICAL ENGINEERING SERIES: HEAT TRANSFER SOLVED PROBLEMS R C =
R D=
x C k C AC
=
x D k D A D
(
=
R T =0.0524
0.130 m
0.038
W m ∙ K
(
0.17
K W
W m ∙ K
)
= 0.0434
( 0.65 m x 2.5 m ) 1
+
1
K
+
W
+ 0.0434
1 2.2433
K W
K W
10
K W
ENGR, RONNIE V, FLORES
W
K W
W
W
R wall= 0.18537
K
m ∙ K
K
1.8537
R wall=
( 0.6 1 m x 2.5 m )
0.012 m
8.125
R T =1.8537
)
=2.2433
Pa(e <
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