A 7-seater mid-sized helicopter to be used for transportation was aimed. This design gives a good room for a well-equipped 7 seats cabin and also comes with a skid landing gear just because of its ...
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Project Name: Jib Foundation Design Doc Title: Sizing and Stability Check
By : JEY Checked: CCO
Revision: A Date: 12.04.17
1.0 General 1.1 REFERENCE 1) Civil/Structural Civil/Stru ctural Design Philosophy 2) BS 8110: Structural Use of Concrete 3) BS 8004: Code of Practice for Foundation 4) Jib Foundation Drawings
Fig. 1 - Jib Crane GA 1.2 Desig Desig n Data Reaction Loading 10 mT Crane base rxn moment 10 mT Crane Vertical Rxn Base Size Base length Base width Base Depth Depth u/s foundation Soil/Material Data Allowable Allowable soil beari bearing ng capacity capacity Unit weight of soil Unit weight of concrete Unit weight of water Unit weight of fill (submerged) Coefficient of friction μ Unit weight of concrete (submerged) Concrete strength f cu cu Steel strength Min overall FOS for stability Ultimate Limit State FOS
Project Name: Jib Foundation Design Doc Title: Sizing and Stability Check
By : JEY Checked: CCO
Revision: A Date: 12.04.17
2.0 Geotechnical Stability 2.1 Preliminary Foundation sizing Ar ea of b ase 2 (m ) 0.80 2.89
Required Adopted
Base Length L (m) 0.89 1.70
Base Width W (m) 0.89 1.70
Base Depth H (m) 0.5 1.00
Crane Rxn Loads Load Type Vertical Rxn Moment Horizontal Rxn
Value (kN,kNm) 57.20 40.50 0.00
2.2 Final Foundation Size and Weight Item Base
L 1.70m
B 1.70m
H 1.00m
Self Weight of Foundation Item Base Total
Dry 69.36 69.36
Submerged 40.46 40.46
2.3 STABILITY CHECK Case I: 1.0 (Dry ) Overturning Overturning Moment, Mo = Total Axial Load, W t = W t (dry) + D =
41kNm 127kN
Eccentricity, e = Mo X sin45/W t =
0.23m
Factor of Safety against overturning =(Wt X L/2)/Mo =
2.66 > 1.5
O.K
Bearing 2
Equivalent uniform pressure = W t/(L-2e) =
81 kN/m2 < 120
O.K
Horizontal Sliding Horizontal Force S f
0kN
Frictional Force Fr = μ X (SW tSub + D)
N/A
Factor of Safety against sliding = F r / Sf
N/A 1.50
Max. Allowoable FOS against sliding
N/A
Bearing 2 Pressure (kN/m ) 120.00 33.05 O.K
Project Name: Jib Foundation Design Doc Title: Sizing and Stability Check
By : JEY Checked: CCO
Revision: A Date: 12.04.17
Case II: 1.0 (Submerg ed) Overturning Overturning Moment, M o =
41kNm
Total Axial Load, W t = W t (Sub) + D =
98kN
Eccentricity, e = Mo X sin45/W t =
0.29m
Factor of Safety against overturning =(W t X L/2)/Mo = M ax. A llowoable FOS against overturning =
2.05 >1.5 1.50
O.K
Bearing 2
Equivalent uniform pressure = W t/(L-2e) =
63 kN/m2 < 120
O.K
Horizontal Sliding Sliding Force Sf = Wk =
0kN
Frictional Force Fr = μ X (SW tSub + D) =
N/A
Factor of Safety against sliding = F r / Sf =
N/A 1.50
Max. Allowoable FOS against sliding =
N/A
Project Name: Jib Foundation Design Doc Title: Sizing and Stability Check
By : JEY Checked: CCO
3.0 Structur al Design Bolt array Diameter =
0.67m
Unit Self Weight of foundation w =
f =
1.60
Mu =
f X Mo =
65kNm
Wu =
f X Wt =
156kN ``
Parftial FOS, For ULS
e = Mu X sin45/Wu = 2
0.29m
Equivalent uniform pressure P eq = Wt/(L-2e) =
126kN/m2
3.1 Reinforcement Designing for ULS Bottom rei nforcement 2 Design Ult. Moment M = (Peq - (H*24))*(L/2-D/2) /2 =
14kNm/m
Cover to reinforcement c =
50.00mm
=
16.00mm
Effective depth d = H-c- -0.5 =
926.00mm
Take d =
925.00mm
Allow for Y16 bars
2
K = M/fcubd 0.000632482 La = 0.5+(0.25-K/0.9) 1.00 Z = la X d 879.70mm Area of reinforcement As =M/0.95*fy*Z = 35mm2/m Minimum reinforcement = 0.13%bd =
120mm2/m
Provide norminal Reinorcement Y16@200cc both ways for ease of construction Top reinforcement 2 Design Ult. Moment M = 1.4*(H*24)*(L/2-D/2) /2 =
4kNm/m
Provide norminal Reinorcement Y16@200cc both ways Shear 2 2 Shear Force V = (Peq*(L/2-D/2) /2)-(H*24*(L/2-D/2) /2) =
14kN/m width
<0.8*f cu = 3.92N/mm2 Norminal shear stress v = V/bvd = 0.01N/mm2 100As/bvd =
<0.8*f cu
0.00
From table 3.8 BS8110 v c = 0.36N/mm2 vc>v hence depth provided is adequate; hence no shear reinforcement required
