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PRC-II Lab Section : “ C ”
Compressive Strength = f c’ = 22.5 Mpa Sp. Gravity Of Cement = Sc = 3.15 Sp. Gravity Of Fine Aggregate = Sf = 2.63 Sp. Gravity Of Coarse Aggregate = Sc.a = 2.56 Fineness Modulus Of Fine Aggregate = F.M = 2.72 Water Absorption For Coarse Aggregate = Wc.a = 1.0 % Water Absorption For Fine Aggregate = Wf = 1.2 % Roaeded Bulk Density Of Coarse Aggregate Aggregate = Dr = 3 1507 kg/m Slump Value = 75 mm ; Max. Aggregate Size = 24 mm 1) Target Target Stren Strength gth : ’ ’ f cr cr = f c + 8.3 = 22.5 + 8.3 = 30.8
MPa
’ f cr cr = 30.8
Mpa
2) Cement Cement Type Type :
Ordinary Portland Cement 3) W/C W/C Rati Ratio o:
From Table # 10.8 ; for
’ f cr cr =30.8
Mpa :
4) Worka Workabi bilit lity y:
From Table # 10.16(a); Relative Water Content = From Table # 10.16(b); Non-Air Water Content = Aggregate size)
w/c ratio = 0.528 %
192 % (►Slump Test) 3 196 kg/m (►Max.
Total Water = Relative Water Content x Non-Air Water Content
Total Water = 180.2 kg/m3 5) %age %age Air Void Voids s: %age Air Voids = 1.6 %
From Table # 10.16(b) ;
(►Max. Aggregate size)
6) Cement Cement Cont Content ent :
Section : “ C ”
Mix Design Calculations
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PRC-II Lab Section : “ C ” Total Water
= 180.32 kg/m3
w/c ratio = 0.528 % = Total Water / w/c
Cement
Cement = kg/m3
ratio 7) Aggregate Selection :
Type Of Fine Aggregate Type Of Coarse Aggregate
= =
341.52
? ?
8) Amount Amount Of Coarse Coarse aggrega aggregate te :
From Table # 10.17 ; we get = 0.668
;
(►For Fineness
Modulus )
Bulk Weight = 0.668 x Dr = 0.668 x 1507
Amount Of Fine aggregate : 9)
Bulk Weight Of Coarse = 1006.68 kg/m3
Bulk Volume Of Cement = Cement /3.15 108.52 kg/m3 Bulk Volume Of Coarse Aggregate = Bulk Weight / Sc.a kg/m3 Bulk Volume Of Water = Total Water 3 kg/m Air Entrapped = 1.6 % of 1000 3 kg/m
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PRC-II Lab Section : “ C ” Total Water
= Sum of All Water Calculated = 199.92 kg/m3
Final Total Water = 199.92 kg/m3
Cement : Crush
: Sand 341.52 1
: 794.34 : 1006.68 : 2.33 : 2.95
_ Adjusted w/c Ratio = Final Water/Cement wt.
= 199.92/341.52
Adjusted w/c Ratio = 0.585 %
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PRC-II Lab Section : “ C ”
Weight of Concrete Cylinders = 4 { π/4 x 0.152 x 0.3 x 2400} = 50.9 kg Cubes = 2 {0.15 x 0.15 x 0.15 x 2400} = 16.2 kg Columns = 4 {0.1 x 0.1 x 0.5 x 2400} = 48kg Beams = 4{0.075 x 0.15 x 1.375 x 2400} = 148.5 kg
Total weight of concrete = 263.6 kg Assuming 5% losses: Total wt. of concrete = 263.6 x 1.05 = 276.78 kg = 280 kg Weight of one batch = 140 kg
Quantities Cement = 1/6.28 x 140 = 22.3 kg Sand = 2.33/6.28 x 140 = 51.94 kg Crush = 2.95/6.28 x140 = 65.8 kg Water = 0.585 x 22.3 = 13.05 kg