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Pump Horsepower Calculation
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Pump Horsepower Calculation
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Pump
The power added to the fluid flow by the pump ( P o), is defined using SI units by:
where: PO = the output output power of the pump (W) = ρ g H Q
∆P
= the fluid density (kg/m3) = = the gravitational constant (9.81 m/s2) = = the energy Head added added to the flow (m) = 3 = the flow rate (m /s) =
=
99.99 bars =
Fluid Spec. Gravity =
Fluid Density =
48,902.3 1066 9.81 956.52 0
101.96 kg/cm2 =
1.13 @ 20/20 oC =
1,123.0 kg/m3 =
=
48.9 kW (Esta potencia no incluye in
956.52 meters
70.11 lb/ft3 =
9.37
eficiencia)
lb/gal
Art Montemayor
September 02, 2009 Rev: 0
Reciprocating Pump Performance
Reference Reference:: API Standar Standard d 674 Second Edition, June 1995 Positive Displacement Pumps - Reciprocating
The power required for driving a single-acting power pump shall be calculated as follows:
kW
= ( Q ) ( ∆P ) + ( Q ) ( Pd )
1
1 + P s − 1 E ff d P
where, 6.5 m3/h = 101.01 BarA = 1.02 BarA = 0.95 99.99 Bar =
Q = Suction flow = Pd = Discharge pressure = Ps = Suction pressure = Eff = Overall Eff., fraction = P = (Pd - Ps) = kW =
28.6 gpm 1,465.08 psia 14.80 psia 1,450.28 psi
650.6 (No puede ser!)
Wrong answer; the equ
In U.S. Customary units, the above equation transforms to the following:
hp
=
( Q ) ( ∆P ) 1714
hp =
+
Q ( ) P( d ) 1714
24.2
=
1 1 + P s −E ff 1 P d 48.9 kW (Esto tiene sentido!)
Reasona
Note: The above API 674 equation for the kW requirement of a single-acting power pump is wrong The correct equation is said to be:
kW
=
( Q ) ( ∆P )+ Q( P ) ( d )
1 + P s − E ff 1 P d
36
kW =
0.7
1
Still wrong answer; the equation is not c
Art Montemayor
Reciprocating Pump Performance
September 02, 2009 Rev: 0
Pump Horsepower Calculation GPSA Data Book Section 12
hp
=
Q h SpGr 3960
eff
Gasoline Pump for SNG site hp h h spgr eff
= Unkn Unknow own n Hors Horsepo epowe wer r = 297 ft of head ∆P*2.31/spgr = = 0.64 specific gravity = 70% pump % efficiency ∆P = 82 psi Q = 100 gpm = 3,429 B/Day Q = 36,000 B/Day = 1,050 gpm
hp =
7
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