Second Design Project for Mechanical Design 2 Course. Involved ground-up design of a shaft to hold a sheave on two bearings with a coupling. Included starting-point determination, failure considera...
Full description
Second Design Project for Mechanical Design 2 Course. Involved ground-up design of a shaft to hold a sheave on two bearings with a coupling. Included starting-point determination, failure co…Descripción completa
Shaft Design ENTC 463 Mechanical Design Applications II
Next Thursday 4/3/2008 Meet @ Thompson 009B Allen to Hagan – 2:20 to 3:00 PM Higginbotha Higginbotham m to to Winnifo Winniford– rd– 3:00 to 3:35 3:35 PM
ENTC 463 Mechanical Design Applications II
Next Thursday 4/3/2008 Meet @ Thompson 009B Allen to Hagan – 2:20 to 3:00 PM Higginbotha Higginbotham m to to Winnifo Winniford– rd– 3:00 to 3:35 3:35 PM
ENTC 463 Mechanical Design Applications II
ATTENTION: MMET Students, the IAC members would like to meet YOU on April 11th ! WHO? IAC Members WHAT? Meet and Greet WHERE? 510, 5th Floor Rudder Tower WHEN? April 11th 3:30-5:00pm WHY? They will also be available to review your resume and help you improve it for potential employers. Please sign up with Courtney in THOM 117
Deadline to sign up is April 8th.
MMET IAC Meeting April 11th 2008
STUDENTS NEEDED!! MMET Majors ONLY Come join us for the 2008 Spring IAC Meeting Great DOOR PRIZES! I-POD NANO and much more! (Must Be Present to Win)
Shaft Design • Given required power to be transmitted – Calculate torque, – Calculate forces, – Calculate stresses (if geometry is known), – Select material
• Given required power to be transmitted – Calculate torque, – Calculate forces, – Determine shaft diameter (if the material is known)
Shaft Design Procedure 1. Develop the free body diagram; model the various machine elements mounted on the shaft in terms of forces and torques 2. Develop the shear and moment diagram; identify bending moment (leads to normal stress) and torque (leads to shear stress) 3. Identify critical locations for stress analysis; calculate stresses (known diameter) 4. Determine diameter or select material based on failure theories
Forces Acting on Shaft • Forces due to gear (spur gear) T =
63000hp
W t =
n T D 2
W r = W t tan φ W x = W t tanψ (helical gear)
Forces due to Gears
Forces Acting on Shaft • Forces due to chain and sprocket F c =
T D 2
=
T A D A 2
F cx = F c cos θ F cy = F c sin θ
=
T B D B 2
Forces Acting on Shaft • Forces due to V-belt and sheave F B = F 1 − F 2 F B ≈
1.5T
D 2
For flat belt and pulley
F B ≈
2.0T
D 2
Example • A chain is transmitting 100 kW with the chain speed at 6000 rpm and V = 50 m/s. The shaft material is AISI 1040 cold drawn. Determine the shaft diameter required.
• Combined tangential and radial load (3-D) – Two shear and moment diagrams Wt
z
M y = M xy + M 2
Wr x
y
2 yz
Stress Concentration • Keyseats – Kt = 2.0 for profile keyseat – Kt = 1.6 for sled keyseat
• Shoulder fillets – Kt = 2.5 for sharp fillet – Kt = 1.5 for well-rounded fillet
• Retaining ring grooves – Kt = Kt = 3.0, or – Increase diameter by 6%
Forces Acting on A Shaft
Shear and Moment Diagrams From bottom look up
Front view
Shaft Design/Analysis Example SST : σ 1 − σ 3 ≤
( M + 32 ( M π d
S y N
16
π d 3
2
3
σ x =
Mc
τ xy =
Tc
I J
= =
M (d 2 )
(π d
4
64
T (d 2 )
(π d
4
32
)
)
=
=
32 M
)
+ T 2 ≤
16 π d 3
( M −
S y N
⎛ 32 N ⎞ 3 2 2 d ≥ ⎜ M + T ⎟ ⎜ π S ⎟ ⎝ y ⎠
π d 3
16T π d 3
2
(
2
(
16 ⎛ σ ⎞ 2 σ 1 = − ⎜ x ⎟ + τ xy = 3 M − M 2 + T 2 2 π d ⎝ 2 ⎠ σ x
2
1
16 ⎛ σ ⎞ 2 σ 1 = + ⎜ x ⎟ + τ xy = 3 M + M 2 + T 2 2 π d ⎝ 2 ⎠ σ x
)
M + T − 2
) )
⎛ ⎜ 32 N d ≥ ⎜ ⎜ π ⎝
1
3 ⎛ M ⎞ ⎛ T ⎞ ⎞⎟ ⎜ ⎟ +⎜ ⎟ ⎟ ⎜ S ⎟ ⎜ S ⎟ ⎟ ⎝ y ⎠ ⎝ y ⎠ ⎠ 2
2
Is this correct ?
)
M + T ≤ 2
2
S y N
Fatigue Failure Criterion • Cyclic loading due to shaft rotation – Find mean and alternating stresses – Construct Mohr’s circles for mean stress and alternating stress – Derive effective mean and alternating stresses (based on MSST or DET) – Use Soderberg or Goodman for design and analysis
Fatigue Failure of Shaft Alternating :
Mean :
σ mx = 0 σ x = ±
π d 3
τ mxy =
σ y = 0 τ xy =
3
π d
π d 3 σ my = 0
σ my = 0
32 M
16T
σ ax =
σ m ' = σ a ' =
16T
τ mxy = 0
π d 3
32T
π d 3 32 M
ANSI/ASME equation for fully reversed bending and steady torsion :
Example 12-1 (p. 548) • The system transmitting 200 hp from pinion P to gear A, and from pinion C to gear Q. • The shaft rotating speed is 600 rpm. • Shaft material is AISI 1144 OQT 1000
Example (p. 549) • • • •
Free body diagram Shear and moment diagrams Torque at each segment Calculate diameter for locations A, B, C, and D (at both left and right) No moment Torque = 21000