BAB VI SAMBUNGAN BAJA Pada bab ini, sambungan yang harus direncanakan adalah: 1. Sambungan Sambungan pelat dasar kolom 2. Sambungan Sambungan antara balok balok dan dan kolom kolom tepi tepi 3. Sambungan Sambungan antara antara balok balok dan kolom kolom tengah tengah 4. Sambungan Sambungan antara antara kuda-kud kuda-kudaa dengan dengan kolom kolom 5. Sambun Sambungan gan pada pada atap atap ntuk lebih !elasnya dapat dilihat pada gambar berikut:
Gambar 12.1 Detail sambungan yang akan direncanakan direncanakan
6.1. Sambungan A ( Kuda – Kuda )
A Mu
Pu
Mu
18°
A Kuda- Kuda WF 250x175x7x11
D ari Output Output Sap 2000: Pu = Pu10 =
52$5,#34 cos 1"
= 5567,53 kg
Mu = 1802, 1802,45 45 kgm
%-1
11 50 122 50 11 172
50 11 175
PO TA- A
Kuda – kuda W 300 ! 200 ! " ! 14#
%.1.1. Kontrol Kekuatan a!
a $%%& ma! 'ada( =
#,&#&.
fu E &# xx
.tw
= #,&#&.
fu
41## &#'&#,3
.$
= 5,3#
mm
41##
a $%%& ma! )a*ap = 1,41. E &# xx .tf = 1,41. &#'&#,3 .14 = 1%,44 mm Mi)a+ka( t$'a+ +a) t$ = 1 -m . (1
) te *2d1 + 2b ) te *2*d-t + 2*b-t ) 1 /2*3#-#,$ + 2*2# 0 1,4 ) 5",2 cm2 + 3&,2 cm2 ) $5,4 cm2
(2
) te*2d2 + 2b ) te *2*d-t + 2*b-t ) 1 /2*2#-#,$ + 2*2# 0 1,4 ) 3",2 + 3&,2 ) &5,4 cm2
' )
1 b 3 4 . .t 12 2
+ .t . d − tf ÷ ÷÷+ 4 1 .t .h + t .h + t .h. d − h÷ ÷÷+ 4 1 . b.t + b t + tf ÷ 2 2 12 2 2 2 2 2 2 2 12 b
2
2
3
3
2
3
=
1 .$,3.13 + $,3.1.( 2$,2 − #,%5) 2 + 4 1 .1.%#3 + 1.%#3 + 1.%#( 2$,2 − 3#) 2 + 4 1 .$,35.13 + $,35( 12 12 12
4
S!
=
I x y ma'
=
2"#24,%$ 22,&5
= 1231,"5 cm3
/ ki'at g$)$r '$'a( )$(tri), % =
Pu A
=
55%&,53 13%
= 4#,$4 kgcm2 %-2
/ ki'at '$'a( mm$( +$(tur, % = % tta+ =
f! 2
+
f 2
=
4#,$4 2
Mu Sx
=
1"#245 1231,"5
= 14%,32 kgcm 2
+ 14%,32 2 = 151,$4 kgcm 2
ϕ&%( = 0,75 ! 0,6 ! 70 ! 70,3 = 2214,45 kg-m 2
t$ p$r+u = a p$r+u =
ft"tal
ϕ fn
=
te. #erlu #,&#&
151,$4 2214,45
=
#,#%$ #,&#&
= #,#%$ cm
= #,#$& cm
a p$r+u a mi( → adi dipakai +a) = a mi( = 5 mm 6.1.". Kontrol Kekuatan Baut
Dir$(-a(aka( : / K$kuata( aut 41 . / ∅ aut 12 mm / Mutu p+at 41 . / ' = π 4 &1,22 = 1,130 -m 2 / aut tip$ tumpu u+ir tidak pada 'ida(g g$)$r, t p+at p$(*am'u(g = 7 mm
9 M$r$(-a(aka( k$kuata( )am'u(ga( 'aut m$td$ titik putar .
Kuat g$)$r 'aut,
d = ϕ & r1 & %u ' & ' & m = 0,75 & 0,5 & 4100 & 2 & 1 = 1737,38 kg
Kuat tumpu 'aut, ;d = ϕ & 2,4 & d' & tp & %u = 0,75 & 2,4 & 1,2 & 0,7 & 4100 = 61"",2 kg < d Ok
Kuat tarik >+ir .'aut ?d = ϕ & 0,75 & %u & ' = 0,75 & 0,75 & 4100 & 1,130 = 2606,06 kg
/ ki'at g$)$r )$(tri) , u =
Pu n
=
55%&,53 %
= $2&,$2 kg < d = 1&3&,3& kg
%-3
/ ?u ma! =
Mu.d ma'
∑ d 2
=
1"#245.35,5 2
2.*23,3
+ 35,52
= 1&&4,32 kg ≤ 6d*ulir...k
/ K(tr+ i(t$rak)i g$)$r tarik, %u =
$u Ab
=
$2&,$2
= "21,1& kgcm 2 < #,&5.#,5.41## = 153&,5 kgcm 2 .....k
1,13#
%t = 1,3 & %u' – 1,5 & %u . = 1,3 & 4100 – 1,5 & 821,17 . = 40"8,25 kg-m 2 4100 kg-m 2 maka digu(aka( %t = 40"8,25 kg-m 2 ?d = ϕ & %t & ' = 0,75 & 40"8,25 & 1,130 = 3473,27 kg-m 2 ?u ma! = 1774,32 kg ?d = 3473,27 kg&Ok 2
2
%u! + %ut ≤ 1,## Φ. %n! Φ.%nt Φ ;( =
0,75 & 0,5 & 4100 & 1,130 = 1737,38 kg
Φ ;(t =
0,75 & 0,75 & 4100 & 1,130 = 2606,06 kg
;u
Pu
=
n
55%&,53
=
%
2
= "27,"2 kg
2
$2&,$2 + %ut ≤ 1,## 1&3&,3" 2%#%,#%
;ut = 2203,23 kg ?d dipakai ?d = ;ut . a =
∑ & = %.22#3,23 = 0,30 -m b. fy
1&,5.25##
a dia(ggap di 'a@a 'aut t$r'a@a ada+a '$(ar .
11 50
2T
122 50 11 172 50 11
g.n. 175
2T d! d2 2T d1 a fy(pelat
POTA-A
6.1.#. Kontrol Momen
A M( = 0," & 0,5 & a 2 & ' & %* B Σ ? & d %-4
= 0," & 0,5 & 0,30 . 2 & 17,5 & 2500 B 2 & 2203,23 & 5,8 B 2",1 B 41,3 . . = 337544,13 kg-m ≈ 3375,44 kgm < Mu = 1802,45 kgmOk 6.". Sambungan B ( Kuda – Kuda dengan Kolom )
Pu1 A
Mu1
Kuda-%uda WF 250x175x7x11 18°
A O&e'(te)% WF 250x175x7x11 K"l"# WF 250x250x1$x1$
Dari Output Sap 2000: Pu1 = Pu10 =
%"$$,1$
= 7254,24 kg
cos1"
Mu1 = 8408,27 kgm Kuda – kuda W 250!175!7!11 t p+at mi( = 11 mm t mi( +a)
= 5 mm
+a) mak) = 11 – 1,6 = ",4 mm 11 50 *1 *1 50 11 50 122 50 11
∅ 'aut
= 1" mm
175 POTA-A
6.".1. Kontrol Kekuatan a!
a $%%& ma! 'ada( =
#,&#&.
fu E &# xx
.tw = #,&#&.
fu
41## &#'&#,3
.&
= 4,12 mm
41##
a $%%& ma! )a*ap = 1,41. E &# xx .tf = 1,41. &#'&#,3 .& = ",22 mm Mi)a+ka( t$'a+ +a) t$ = 1 -m . +a) = 4 & 22,2 & 1 . B 8 8,4 & 1 . = 156 -m 2 %-5
C!
= 4&
1 12
&1&22,23.B4& 22,2&1 .&11,65. 2.B4&8,4&1.&22,75.2.B4&8,4&1.&0,55.2.
= 330"",44 -m 4 S! =
I x yma'
=
33#$$,44 22,&5
= 1454,$2 cm3
/ ki'at g$)$r '$'a( )$(tri), % = / ki'at '$'a( mm$( +$(tur, % = % tta+ =
f! 2
+
f 2
=
4%,5# 2
Pu A
&254,24
=
Mu Sx
15%
=
= 4%,5# kgcm 2
"4#"2& 1454,$2
= 5&&,$2 kgcm 2
+ 5&&,$2 2 = 5&$,&$ kgcm 2
ϕ&%( = 0,75 ! 0,6 ! 70 ! 70,3 = 2214,45 kg-m 2
t$ p$r+u = a p$r+u =
ft"tal fn ϕ
=
te. #erlu #,&#&
5&$,&$ 2214,45
=
#,2%2 #,&#&
= #,2%2 cm
= #,3&# cm ≈ #,4 cm
a p$r+u a mi( → adi dipakai +a) = 5 mm 6.".". Kontrol Kekuatan Baut
Dir$(-a(aka( : / K$kuata( aut 41 . / ∅ aut 1" mm / Mutu p+at 41 . / ' = π 4 &1,"2 = 2,834 -m 2 / aut tip$ tumpu u+ir tidak pada 'ida(g g$)$r, t p+at p$(*am'u(g = 7 mm 9 M$r$(-a(aka( k$kuata( )am'u(ga( 'aut m$td$ titik putar .
Kuat g$)$r 'aut, d = ϕ & r1 & %u ' & ' & m = 0,75 & 0,5 & 4100 & 2,834 & 1 = 4357,28 kg
Kuat tumpu 'aut, ;d = ϕ & 2,4 & d' & tp & %u = 0,75 & 2,4 & 1," & 0,7 & 4100 = "815,40 kg < d Ok
Kuat tarik >+ir .'aut ?d = ϕ & 0,75 & %u & ' %-%
= 0,75 & 0,75 & 4100 & 2,834 = 6535,"1 kg / ki'at g$)$r )$(tri) , u =
Pu n
=
&254,24 1#
= &25,42 kg < d = 435&,2" kg
Mu.d ma'
/ ?uma! =
∑ d 2 "4#"2&.35,5
=
2.*12,2
+ 23,32 + 2$,42 + 35,5 2
2
= 52$$,32 kg ≤ 6d*ulir...k
/ K(tr+ i(t$rak)i g$)$r tarik, %u =
$u Ab
=
&25,42 2,"34
= 255,$& kgcm 2 < #,&5.#,5.41## = 153&,5 kgcm 2 .....k
%t = 1,3 & %u' – 1,5 & %u . = 1,3 & 4100 – 1,5 & 255,"7 . = 4"46,045 kg-m 2 < 4100 kg-m 2 maka digu(aka( %t = 4100 kg-m 2 ?d = ϕ & %t & ' = 0,75 & 4100 & 2,834 = 8714,55 kg-m
2
?u ma! = 52"",32 kg ?d = 8714,55 kg&Ok 2
2
%u! + %ut ≤ 1,## Φ. %n! Φ.%nt Φ ;( = 0,75 & 0,5 & 4100 & 2,834 = 4357,28 kg Φ ;(t = 0,75 & 0,75 & 4100 & 2,834 = 6535,"1 kg
;u
=
Pu n
&254,24
=
1#
2
= 725,42 kg
2
&25,42 + %ut ≤ 1,## 435&,2" %535,$1
;ut = 6444,6" kg ?d dipakai ?d = ;ut . a =
∑ & = 1#.%444,%$ = 1,47 -m b. fy
1&,5.25##
a dia(ggap di 'a@a 'aut t$r'a@a ada+a '$(ar .
11 50 *1 *1 50 11 50 122 g.n. 175
50 11
2T 2T 2T d5 d$ d! d2 2T d1 a 2T
fy(pelat
POTA- A
%-&
6.".#. Kontrol Momen
A M( = 0," & 0,5 & a 2 & ' & %* B Σ ? & d = 0,"&0,5&1,47. 2&17,5&2500B 2&6444,6"&4,63B16,83B27,"3B34,03B 40,13 . . = 1635025,62 kg-m ≈ 16350,25 kgm < Mu = 8408,27 kgmOk 6.#. Sambungan $ ( Kolom dengan %&er!te'k )
+ Pu2
Mu2
Kuda-%uda WF 250x175x7x11 18°
+ O&e'(te)% WF 250x175x7x11 K"l"# WF 250x250x1$x1$
D ari Output Sap 2000: Pu2 = Pu12 =
2&",$" cos1"
= 2"3,34 kg
Mu2 = "02,81 kgm O$r)t$-k W 250!175!7!11 t p+at mi( = 11 mm t mi( +a)
= 5 mm
+a) mak) = 11 – 1,6 = ",4 mm ∅ 'aut
= 12 mm
11 50 122 50 11 172
50 11 175
POT+-+
%-"
6.#.1. Kontrol Kekuatan a!
a $%%& ma! 'ada( =
#,&#&.
fu E &# xx
.tw = #,&#&.
fu
41## &#'&#,3
.&
= 4,12 mm
41##
a $%%& ma! )a*ap = 1,41. E &# xx .tf = 1,41. &#'&#,3 .& = ",22 mm Mi)a+ka( t$'a+ +a) t$ = 1 -m . +a) = 4 & 20 & 1 . B 8 7 & 1 . = 136 -m 2 C!
= 4&
1 12
&1&203 .B 4& 7&1 .& 22,75 . 2.B 4& 7&1 .& 0,55 . 2.B 4& 20&1 .& 11,65 . 2.
= 2666,7 B 144"1,75 B 8,47 B 10857,8 = 28024,6" -m 4 S!
=
I x y ma'
=
2"#24,%$ 22,&5
= 1231,"5 cm3
/ ki'at g$)$r '$'a( )$(tri), % = / ki'at '$'a( mm$( +$(tur, % = % tta+ =
f! 2
+
f 2
=
2,1% 2
Pu A
=
Mu Sx
2$3,34
=
13%
= 2,1% kgcm2
$#2"1 1231,"5
= &3,2$ kgcm2
+ &3,2$2 = &3,32 kgcm 2
ϕ&%( = 0,75 ! 0,6 ! 70 ! 70,3 = 2214,45 kg-m 2
t$ p$r+u = a p$r+u =
ft"tal
ϕ fn
=
te. #erlu #,&#&
&3,32 2214,45
=
#,#33 #,&#&
= #,#33 cm
= #,#4& cm
a p$r+u a mi( → adi dipakai +a) = a mi( = 5 mm
6.#.". Kontrol Kekuatan Baut
Dir$(-a(aka( : / K$kuata( aut 41 . %-$
/ ∅ aut 12 mm / Mutu p+at 41 . / ' = π 4 &1,22 = 1,130 -m 2 / aut tip$ tumpu u+ir tidak pada 'ida(g g$)$r, t p+at p$(*am'u(g = 7 mm M$r$(-a(aka( k$kuata( )am'u(ga( 'aut m$td$ titik putar .
•
d = ϕ & r1 & %u ' & ' & m
Kuat g$)$r 'aut,
= 0,75 & 0,5 & 4100 & 2 & 1 = 1737,38 kg
Kuat tumpu 'aut,
;d = ϕ & 2,4 & d' & tp & %u = 0,75 & 2,4 & 1,2 & 0,7 & 4100 = 61"",2 kg < d Ok
Kuat tarik >+ir .'aut ?d = ϕ & 0,75 & %u & ' = 0,75 & 0,75 & 4100 & 1,130 = 2606,06 kg
/ ki'at g$)$r )$(tri) , u = Mu.d ma'
/ ?u ma! =
∑ d 2
=
Pu n
=
2$3,34 %
= 4","$ kg < d = 1&3&,3& kg
$#2"1.35,5 2.*23,3
2
+ 35,52
= """,&2 kg ≤ 6d*ulir.. .k
/ K(tr+ i(t$rak)i g$)$r tarik, %u =
$u Ab
=
4","$ 1,13#
= 43,2% kgcm 2 < #,&5.#,5.41## = 153&,5 kgcm 2 .....k
%t = 1,3 & %u' – 1,5 & %u . = 1,3 & 4100 – 1,5 & 43,26 . = 5265,11 kg-m 2 < 4100 kg-m 2 maka digu(aka( %t = 40"8,25 kg-m 2 ?d = ϕ & %t & ' = 0,75 & 4100 & 1,130 = 3474,75 kg-m
2
?u ma! = 888,72 kg ?d = 3474,75 kg&Ok 2
2
%u! + %ut ≤ 1,## Φ. %n! Φ.%nt Φ ;(
= 0,75 & 0,5 & 4100 & 1,130 = 1737,38 kg %-1#
Φ ;(t
= 0,75 & 0,75 & 4100 & 1,130 = 2606,06 kg
;u
=
Pu
=
n
2$3,34 %
2
= 48,8" kg
2
4","$ + %ut ≤ 1,## 1&3&,3" 2%#%,#%
;ut = 2605,03 kg ?d dipakai ?d = ;ut . a =
∑ & = %.2%#5,#3 = 0,35 -m 1&,5.25##
b. fy
a dia(ggap di 'a@a 'aut t$r'a@a ada+a '$(ar .
11 50
2T
122 50 11
2T d!
172
50 11
g.n. 175
d2 2T d1 a fy(pelat
POT+- +
6.#.#. Kontrol Momen
A M( = 0," & 0,5 & a 2 & ' & %* B Σ ? & d = 0," & 0,5 & 0,35 . 2 & 17,5 & 2500 B 2 & 2605,03 & 5,75 B 2",05 B 41,25 . . = 3"8636,78 kg-m ≈ 3"86,37 kgm < Mu = "02,81 kgm&&Ok
6.. Sambungan ( Balok Induk dengan Balok Anak ) Pu1
Pu2
WF !00x200x8x12
, 50x50x5 WF $00x200x8x1!
Data Sap 2000 : Pu1 = 1151",14 kg %-11
Pu1 = 1151",14 kg K(tr+ k$kuata( 'aut pada 'ada( 'a+k a(ak : A ;(t = ϕ & r1 & %u ' & ' & m = 0,75 & 0,5 & 4100 & & π &1,62 . & 2 = 617",52 kg m$($(tuka( EEE . A ;(t = ϕ & 2,4 & d' & tp & %u = 0,75 & 2,4 & 1,6 & 0,8 & 4100 = "446,40 kg K(tr+ k$kuata( 'aut pada 'ada( 'a+k i(duk : A ;(t = ϕ & r1 & %u ' & ' & m = 0,75 & 0,5 & 4100 & & π &1,62 . & 2 = 617",52 kg m$($(tuka( EEE . A ;(t = ϕ & 2,4 & d' & tp & %u = 0,75 & 2,4 & 1,6 & 0,8 & 4100 = "446,40 kg um+a 'aut pada 'ada( 'a+k a(ak : (=
Pu φ . %nt
=
1151$,14 %1&$,52
= 1,86 ≈ 2 'ua
um+a 'aut pada 'ada( 'a+k i(duk : (=
Pu φ . %nt
=
2 . 1151$,14 %1&$,52
= 3,73 ≈ 4 'ua
F$k )iku p$(*am'u(g pada 'ada( 'a+k i(duk da( 'a+k a(ak : ( = G – (&d1 . & t G
d1 = 16 B 1,5 = 17,5 mm
= 20 – 2 & 1,75 . . & 0,5 *5
= 8,25 -m 2
70 200
*5 50
2 A P( = 2 & 0,6 & %u & ( . = 2 & 0,6 & 4100 & 8,25 . 2 A P( = 405"0 kg < Pu = 1151",14 kg&&Ok %-12
6.*. Sambungan + ( Balok dengan Kolom ,e- ) Pu 8 2*
Data Sap 2000 :
Mu
Pu = 4565,83 kg
$ !2
! 12
2 12
$ !2
WF $00x200x8x1!
Mu = 21155,36 kgm
8 2*
K"l"# WF 250x250x1$x1$
& Sam'u(ga( a(tara 'ada( 'a+k da( %+$() k+m Dir$(-a(aka( : / Pr%i+ H 60!60!6 / ∅ 'aut 12 mm
Sam'u(ga( pada 'ada( 'a+k Kuat g$)$r A ;( = 0,75 & 0,5 & %u & 2 ' = 0,75 & 0,5 & 4100 & 2 & 1,1304 = 3475,"8 kg m$($(tuka( EEE . Kuat tumpu A ;( = 0,75 & 2,4 & d' & tp & %u = 0,75 & 2,4 & 1,2 & 0,8 & 4100 = 7084,80 kg um+a 'aut ( . =
Pu
= φ %n
45%5,"3 34&5,$"
= 1,31 ≈ 2 'ua
Sam'u(ga( pada %+$() k+m Kuat g$)$r A ;( = 0,75 & 0,5 & %u & ' = 0,75 & 0,5 & 4100 & 1,1304 = 1737,38 kg m$($(tuka( EEE . Kuat tumpu A ;( = 0,75 & 2,4 & d' & tp & %u = 0,75 & 2,4 & 1,2 & 0,6 & 4100 %-13
= 5313,60 kg um+a 'aut ( . =
Pu
= φ %n
45%5,"3 1&3&,3"
= 2,63 ≈ 3 'ua
K(tr+ k$kuata( )iku p$(*am'u(g ( = G – (&d1 . & tG
d1 = 12 B 1,5 = 13,5 mm
= 10 – 2 & 1,35 . . & 0,6 = 4,38 -m 2 2 A P( = 2 & 0,75 & 0,6 & %u & ( . = 2 & 0,75 & 0,6 & 4100 & 4,38 . 2 A P( = 16162,20 kg < Pu = 4565,83 kg&&Ok
& Sam'u(ga( a(tara %+$() k+m da( pr%i+ ?
W 50
a
$$
.
1$ $$ 50 !0*
a = 50 mm ' = 44 mm 2? =
Mu
21155,3%
=
db
#,4
= 52888,40 kg
? = 26444,20 kg a
≤ 1,25 & '
aI = a B
d
'I = ' /
d
δ =
2 2
= 50 B
32
= 44 /
32
' − Σd 7 '
→ 50 mm
=
2 2
≤ 55 mm
= 66 mm = 28 mm
2## − 2 . *32 + 1,5 2##
= 0,66
K$kuata( 'aut pada %+$() pr%i+ ? %-14
= 0,75 & 0,75 & %u ' & ' & ( = 0,75 & 0,75 & 4100 & & π & 3,2 2 . & 2 = 37077,12 kg 3&#&&,12 %% 8 − 1 . a7 − 1 . = 0,"48 1,00 = 6 b7 2%444,2# 2"
β = α =
β = δ 1 − β 1
1
.
#,%%
#,$4" = 27,62 < 1,00 1 # , $4" −
.
dipakai α = 1,00 α .δ . b7 = 1 + α .δ a7
Pr*i(g %r-$ J =
& .
1,## . #,%% 2" . 1 + 1,## . #,%% %%
2%444,2.
= 4460,47 kg ?BJ
≤ A&;(
26444,20 B 4460,47 = 30"04,67 kg
≤ 37077,12 kg&&Ok
K(tr+ t$'a+ %+$() prpi+ ? t ≥
t ≥
2,3 -m
4.6.b7 ;.<.y.*1 + 9.: 4 . 2%444,2# . 2," #,$ . 2# . 25## . *1 + 1 . #,%%
≥ 1,"" -m&&Ok
F& Sam'u(ga( pada 'ada( pr%i+ ? Kuat g$)$r A ;( = 0,75 & 0,5 & %u & ' = 0,75 & 0,5 & 4100 & & π&2,62 . = 8158,8" kg m$($(tuka( EEE . Kuat tumpu A ;( = 0,75 & 2,4 & d' & tp & %u = 0,75 & 2,4 & 2,6 & 1,3 & 4100 = 24"44,40 kg um+a 'aut ( . =
Pu
= φ %n
52""",4 "15","$
= 6,48 ≈ 8 'ua
D& K$kuata( pr%i+ ? g & 0," & %*
≥ 2? %-15
≥ 2? 20 & 1,4 & 0," & 2500 ≥ 52888,40 63000 kg ≥ 52888,40 kgOk ( & 0,75 & %u ≥ 2? g / Σ dI t@ . & 0,75 & %u ≥ 2? W & t@ & 0," & %*
≥ 52888,40
20&1,4 – 2&2,6B0,15.&1,4 . & 0,75 & 4100 62422,50 kg
200 110 $5
≥ 52888,40 kgOk
$5 25
50
50 100
$$ 202 1$ $$
25 *0
50 78 57 57 57 57 !0*
6.6. Sambungan / ( Balok – Kolom – Balok )
Mu
Pu
! 12
Pu
Mu
2 12
$ !2
WF $00x200x8x1! 8 2*
K"l"# WF 250x250x1$x1$
Data Sap 2000 : Pu = 4384,83 kg Mu = 26""0,3" kgm & Sam'u(ga( a(tara 'ada( 'a+k da( %+$() k+m Dir$(-a(aka( : / Pr%i+ H 60!60!6 / ∅ 'aut 12 mm %-1%
Sam'u(ga( pada 'ada( 'a+k Kuat g$)$r A ;( = 0,75 & 0,5 & %u & 2 ' = 0,75 & 0,5 & 4100 & 2 & 1,1304 = 3475,"8 kg m$($(tuka( EEE . Kuat tumpu A ;( = 0,75 & 2,4 & d' & tp & %u = 0,75 & 2,4 & 1,2 & 0,8 & 4100 = 7084,80 kg um+a 'aut ( . =
Pu
= φ %n
43"4,"3 34&5,$"
= 1,26 ≈ 2 'ua
Sam'u(ga( pada %+$() k+m Kuat g$)$r A ;( = 0,75 & 0,5 & %u & ' = 0,75 & 0,5 & 4100 & 1,1304 = 1737,38 kg m$($(tuka( EEE . Kuat tumpu A ;( = 0,75 & 2,4 & d' & tp & %u = 0,75 & 2,4 & 1,2 & 0,6 & 4100 = 5313,60 kg Pu
um+a 'aut ( . =
= φ %n
43"4,"3 1&3&,3"
= 2,52 ≈ 3 'ua
K(tr+ k$kuata( )iku p$(*am'u(g ( = G – (&d1 . & tG
d1 = 12 B 1,5 = 13,5 mm
= 10 – 2 & 1,35 . . & 0,6 = 4,38 -m 2 2 A P( = 2 & 0,75 & 0,6 & %u & ( . = 2 & 0,75 & 0,6 & 4100 & 4,38 . 2 A P( = 16162,20 kg < Pu = 4384,83 kg&&Ok & Sam'u(ga( a(tara %+$() k+m da( pr%i+ ? W 72
a
70 18 70
.
72 $5*
a = 72 mm %-1&
' = 70 mm 2? =
Mu
2%$$#,3$
=
db
= 67475,"75 kg
#,4
? = 33737,"" kg a
≤ 1,25 & '
aI = a B
d
'I = ' /
d
2 2
= 72 B
32
= 70 /
32
' − Σd 7
δ =
'
≤ 87,50 mm
→ 72 mm 2
= 88 mm = 54 mm
2
2## − 2 . *32 + 1,5
=
2##
= 0,66
K$kuata( 'aut pada %+$() pr%i+ ? = 0,75 & 0,75 & %u ' & ' & ( = 0,75 & 0,75 & 5100 & & π & 3,2 2 . & 2 = 46120,32 kg 4%12#,32 "" 8 − 1 . a7 − 1 . = 0,5"8 1,00 = 6 b7 33&3&,$$ 54
β = α =
β = δ 1 − β 1
.
1 #,%%
#,5$" = 2,250 < 1,00 1 − #,5$"
.
dipakai α = 1,00 Pr*i(g %r-$ J =
α .δ . b7 = 1 + α .δ a7
& .
1,## . #,%% . 54 1 + 1,## . #,%% ""
33&3&,$$ .
= 8231,26 kg ?BJ
≤ A&;(
33737,"" B 8231,26 = 41"6",25 kg
≤ 46120,32 kg&&Ok
K(tr+ t$'a+ %+$() prpi+ ? t ≥
t ≥
3,4 -m
4.6.b7 ;.<.y.*1 + 9.: 4 . 33&3&,$$ . 5,4 #,$ . 2# . 25## . *1 + 1 . #,%%
≥ 3,12 -m&&Ok
F& Sam'u(ga( pada 'ada( pr%i+ ? %-1"
Kuat g$)$r A ;( = 0,75 & 0,5 & %u & ' = 0,75 & 0,5 & 5100 & & π&2,62 . = 1014",64 kg m$($(tuka( EEE . Kuat tumpu A ;( = 0,75 & 2,4 & d' & tp & %u = 0,75 & 2,4 & 2,6 & 1,3 & 4100 = 24"44,40 kg um+a 'aut ( . =
Pu
= φ %n
33&3&,$$ 1#14$,%4
= 6,65 ≈ 8 'ua
D& K$kuata( pr%i+ ?
≥ 2? W & t@ & 0," & %* ≥ 2? 20 & 1,8 & 0," & 2500 ≥ 67475,"75 81000 kg ≥ 67475,"75 kgOk g & 0," & %*
( & 0,75 & %u
≥ 2?
g / Σ dI t@ . & 0,75 & %u
≥ 2?
20&1,8 – 2&2,6B0,15.&1,8 . & 0,75 & 5100 ""832,50 kg
≥ 67475,"75
≥ 67475,"75 kgOk
$5 200 110 $5
25
72
50 100
70 !02 18 70
25 *0
72 80 /$ /$ /$ /$ $5*
%-1$
