Laporan Kerja Praktek PT PLN (Persero) Sektor Pembangkitan Ombilin Analisa Performa Boiler Feed Water PumpFull description
Boiler Feed Water Chemical (Samsung Engg)
Laporan Kerja Praktek PT PLN (Persero) Sektor Pembangkitan Ombilin Analisa Performa Boiler Feed Water PumpFull description
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pengertian feed pump dan komponen utamaFull description
Boiler feed pumpFull description
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Bombas de calderos
HEI Feed Water Heater
I have uploaded feed water heater presentationFull description
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Boiler feed pump Balancing DiscFull description
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Boiler Feed water design calculations 1. P & T Press Pressure ure & Tempe Temperat rature ure of of steam steam h1= From steam tables at P & T h2= at P C pw= 4.186 KJ/Kg-K h3= hf = at P 2. Surf urface ace Ar Area: ea: a. Desuperheating Zo Zone: To find tx Ms(h1-h2) = MwC pw(two-tx) ∆ t =
( T − t wo ) − ( T sat − t x ) ( T − t wo ) ln ( T sat − t x )
Take U = 350 -450 Kcal/hr m K U
400 =
× 4.186
3600
KW/m2-K
Heat Load Q = Ws(h1-h2) Area A1= Q/U ∆t Length of zone L =
A1 Π × D × n × p
Baffle Spacing B = 0.2 * L b.
Condensing Zone:
To find Ty Ms(h2-h3) = MwC pw(tx-ty) ∆t =
( T sat − t x ) − T sat − t y ( T sat − t x ) ln
(T sat − t y )
Film Temp. tf = ts – 0.8 * ∆t If tf > 250 , take tf = 250 F Assume Velocity of feed water such that V < 8 fps At V = ________ at tf form Fig. 5.20 U = __________ _______ ___ Btu/hr F ft2 U
850 =
× 4.882 × 4.186
3600
= _______ KW/m2-K
Taking Tube OD = 15.875mm, BWG = _____, & Material:________ Multiplication Factor = ________ from Table T 5.19 U1 = U * Multiplication Factor
Heat Load Q = Mw C pw (tx-ty) Area A2= Q/U1 ∆t Length of zone L =
A2 Π × D × n × p
Baffle Spacing B = 0.4 * L c. Drain sub-cooling Zone: Form Experimental data Td = ____ oC ∆t =
T sat − t y − ( T d − t wi ) (T sat − t y ) ln
( T d − t wi )
Take U = 2000 -2500 Kcal/hr m K U
2000 =
× 4.186
= _____KW/m2-K
3600
Heat Load Q = Mw C pw (ty-twi) Area A3= Q/U ∆t Length of zone L =
A3 Π × D × n × p
Baffle Spacing B = 0.4 * L
Total Surface Area of Feed Water heater = A1+A2+A3 =
Theoretical calculation
Actual provided by Remarks at Power Plant
Total surface area Length of tube
HPH6 Feed water design
calculations
1. P & T Pressure & Temperature of steam h1= From steam tables at P & T h2= at P C pw= 4.186 KJ/Kg-K h3= hf = at P 2. Surface Area: a. Desuperheating Zone: To find tx Ms(h1-h2) = MwC pw(two-tx) ∆ t =
( T − t wo ) − ( T sat − t x ) ( T − t wo ) ln ( T sat − t x )
Take U = 350 -450 Kcal/hr m K U
400 =
× 4.186
3600
KW/m2-K
Heat Load Q = Ws(h1-h2) Area A1= Q/U ∆t Length of zone L =
A1 Π × D × n × p
Baffle Spacing B = 0.2 * L b.
Condensing Zone:
To find Ty Ms(h2-h3) = MwC pw(tx-ty) ∆t =
( T sat − t x ) − T sat − t y ( T sat − t x ) ln
(T sat − t y )
Film Temp. tf = ts – 0.8 * ∆t If tf > 250 , take tf = 250 F Assume Velocity of feed water such that V < 8 fps At V = ________ at tf form Fig. 5.20 U = __________ Btu/hr F ft2 U
850 =
× 4.882 × 4.186
3600
= _______ KW/m2-K
Taking Tube OD = 15.875mm, BWG = _____, & Material:________ Multiplication Factor = ________ from Table T 5.19 U1 = U * Multiplication Factor Heat Load Q = Mw C pw (tx-ty)
Area A2= Q/U1 ∆t Length of zone L =
A2 Π × D × n × p
Baffle Spacing B = 0.4 * L c. Drain sub-cooling Zone: Form Experimental data Td = ____ oC ∆t =
T sat − t y − ( T d − t wi ) (T sat − t y ) ln
( T d − t wi )
Take U = 2000 -2500 Kcal/hr m K U
2000 =
× 4.186
3600
= _____KW/m2-K
Heat Load Q = Mw C pw (ty-twi) Area A3= Q/U ∆t Length of zone L =
A3 Π × D × n × p
Baffle Spacing B = 0.4 * L
Total Surface Area of Feed Water heater = A1+A2+A3 =
